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| Section | Objectives |
|---|---|
| Topic 1: Polynomial Functions | - Interpret concavity for polynomial functions - Interpret rates of change for polynomial functions - Interpret inputs and outputs for polynomial functions |
| Topic 2: Functions and Algebra of Functions | - Derive conclusions based on graphs - Derive conclusions based on data - Derive conclusions based on notation |
| Topic 3: Linear Functions | - Interpret inputs and outputs of linear functions - Interpret rates of change for linear functions |
| Topic 4: Graphical Depictions | - Interpret rates of change for situations - Interpret concavity for situations - Interpret maximum and minimum for situations - Interpret inputs and outputs for situations - Interpret asymptotes for situations |
| Topic 5: Logistic Functions | - Interpret inputs and outputs for logistic functions - Interpret rates of change for logistic functions - Interpret asymptotes for logistic functions |
| Topic 6: Exponential Functions | - Interpret rates of change for exponential functions - Interpret inputs and outputs for exponential functions - Interpret concavity for exponential functions |
| Topic 7: Validity of Models | - Determine fit - Determine validity - Examine utility |
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NEW QUESTION # 88
The function P(t)represents the weekly profit, in thousands of dollars, for a rental store since opening. The graph of P(t)is shown.
When did the store have its maximum weekly profit?
Answer: B
Explanation:
The graph shows:
P(t)= " weekly profit in thousands of dollars "
where:
t= " years since opening "
The graph is a downward-opening curve, so it has a maximum value at its highest point. In Applied Algebra, the highest point of this kind of polynomial graph is called the vertex.
To answer the question, we need the t-value of the vertex because the question asks when the store had its maximum weekly profit.
From the graph, the highest point occurs between:
t=5
and
t=6
More specifically, it is approximately:
t=5.5
So the store had its maximum weekly profit approximately:
5.5 " years after opening "
NEW QUESTION # 89
A music student attempted to learn a difficult new song. Each day, the student would play the song and be scored on their performance. The graph shows the results.
What was the average daily change in performance from day 16 to day 20?
Answer: D
Explanation:
The average daily change is the average rate of change over the interval from day 16 to day 20. From the graph, the performance score at day 16 is approximately 30.1, and the score at day 20 is approximately 57.6.
Use the formula
x
2
#x
1
y
2
#y
1
Substituting gives
20#16
57.6#30.1
The numerator is 27.5, and the denominator is 4, so the average daily change is 27.5/4=6.875, which rounds to 6.88. This means the performance score increased by an average of about 6.88 points per day over the interval. Therefore, the correct answer is B.
NEW QUESTION # 90
The figure displays the graphs of two functions representing the heights, h_1and h_2, in feet, of two balls tseconds after being launched.
Which ball was lower 0.9seconds after being launched?
Answer: C
Explanation:
This question asks us to compare the heights of two balls at a specific time:
t=0.9
The graph shows:
Ball 1 as the solid blue curve.
Ball 2 as the dashed blue curve.
To determine which ball was lower at t=0.9, we look at the vertical positions of both curves when the time is
0.9seconds.
At approximately t=0.9:
" height of Ball 1 " < " height of Ball 2 "
This means Ball 1 is lower than Ball 2 at that time.
The correct reasoning must say both:
Ball 1 was lower, and
Ball 1's height was less than Ball 2's height at t=0.9.
That matches option A.
NEW QUESTION # 91
The temperature of an object changes according to the relationship in the graph.
What is the equation of the horizontal asymptote?
Answer: A
Explanation:
The graph shows the temperature of an object decreasing over time.
The horizontal axis represents:
" Time in minutes "
The vertical axis represents:
" Temperature in degrees Fahrenheit "
The curve decreases and approaches the horizontal axis as time increases.
A horizontal asymptote is a horizontal line that the graph approaches but may not reach. Horizontal lines have equations of the form:
y= " constant "
From the graph, the curve approaches:
y=0
So the horizontal asymptote is:
y=0
The options x=0and x=500are vertical lines, not horizontal asymptotes.
Therefore, the correct answer is:
# ( " B " )
NEW QUESTION # 92
Which statement correctly interprets u(8), given that u(t)=0.21t
3
#4.09t
2
+18.89t+69.5 represents the number of units, u, in an inventory warehouse t hours after 9:00 a.m.?
Answer: A
Explanation:
The function u(t) gives the number of units in the inventory warehouse t hours after 9:00 a.m. The expression u(8) means the value of the inventory function 8 hours after 9:00 a.m. Since 8 hours after 9:00 a.m. is 5:00 p.
m., the time must be 5:00 p.m., not 10:00 a.m. Now evaluate the function: u(8)=0.21(8)
3
#4.09(8)
2
+18.89(8)+69.5. This gives approximately 66.38, which rounds to about 66 units. Therefore, the correct interpretation is that there are approximately 66 units in the inventory at 5:00 p.m.
NEW QUESTION # 93
......
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