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Salesforce JS-Dev-101 Exam Overview:

Certification Vendor:Salesforce
Exam Name:Salesforce Certified JavaScript Developer I - Multiple Choice Exam (JS-Dev-101)
Exam Number:JS-Dev-101
Exam Price:$200 USD
Available Languages:English
Exam Format:Multiple Select Questions, Multiple Choice Questions
Real Exam Qty:60 (multiple choice)
Related Certifications:Salesforce Platform Developer II
Salesforce Platform Developer I
Passing Score:65%
Exam Duration:105 minutes
Certificate Validity Period:1 year (maintenance required annually in Salesforce certification program)
Recommended Training:MDN Web Docs - JavaScript Guide
Salesforce Trailhead - JavaScript Developer I
Exam Registration:Kryterion Webassessor (Exam Delivery)
Salesforce Certification Registration
Sample Questions:Salesforce JS-Dev-101 Sample Questions
Exam Way:Online proctored exam via Salesforce authorized testing platform (e.g., Webassessor)
Pre Condition:No formal prerequisites, but familiarity with JavaScript and web development is recommended.
Official Syllabus URL:https://trailhead.salesforce.com/credentials/javascriptdeveloper

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Salesforce JS-Dev-101 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.
Topic 2
  • Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
Topic 3
  • Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
Topic 4
  • Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.
Topic 5
  • Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.

Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q72-Q77):

NEW QUESTION # 72
Refer to the code below:
01 new Promise((resolve, reject) => {
02 const fraction = Math.random();
03 if (fraction > 0.5) reject('fraction > 0.5, ' + fraction);
04 resolve(fraction);
05 })
06 .then(() => console.log('resolved'))
07 .catch((error) => console.error(error))
08 .finally(() => console.log('when am I called?'));
When does Promise.finally on line 08 get called?

Answer: C

Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
Behavior of Promise.prototype.finally:
.finally(handler) registers a callback that runs when the promise is settled, meaning:
Either fulfilled (resolved), or
rejected.
Important points:
The finally callback does not receive the promise's value or error (unlike then and catch).
It is executed after the promise is settled, but before the resolution value or rejection reason is passed further down the chain.
It runs in both success and failure paths.
In the given code:
The promise may either:
Call reject('fraction > 0.5, ' + fraction) if fraction > 0.5, or
Call resolve(fraction) otherwise.
In both cases:
If it resolves, .then(() => console.log('resolved')) runs, and then .finally(...) is executed.
If it rejects, .catch((error) => console.error(error)) runs, and then .finally(...) is executed.
So .finally runs:
Not just "when rejected".
Not just "when resolved".
But whenever the promise is resolved or rejected.
Therefore, the correct choice is:
D . When resolved or rejected.


NEW QUESTION # 73
Considering the implications of 'use strict' on line 04, which three statements describe the execution of the code?
Choose 3 answers

Answer: B,C,D


NEW QUESTION # 74
Refer to the code:
01 const exec = (item, delay) =>
02 new Promise(resolve => setTimeout(() => resolve(item), delay));
03
04 async function runParallel() {
05 const [result1, result2, result3] = await Promise.all(
06 [exec('x', '100'), exec('y', '500'), exec('z', '100')]
07 );
08 return `parallel is done: ${result1}${result2}${result3}`;
09 }
Which two statements correctly execute runParallel()?

Answer: B,D

Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge Facts about JavaScript Promises:
runParallel() is declared async, which means it always returns a Promise.
Promises are consumed using .then(), .catch(), and .finally().
There is no .done() method in native JavaScript Promises.
The async keyword cannot be placed before a function call (option A is invalid syntax).
Analysis of each option:
A . async runParallel().then(data);
Invalid syntax. async cannot prefix an expression.
B . Valid. Calls the function and attaches a .then() handler.
C . Invalid. .done() is not part of JavaScript Promise API.
D . Valid. Calls runParallel() and chains .then().
Therefore the correct answers are B and D.
________________________________________
JavaScript Knowledge Reference (text-only)
async functions return Promises.
Promises use .then() to retrieve resolved values.
.done() is not part of the standard Promise interface.


NEW QUESTION # 75
Refer to the code declarations below:
Which three expressions return the string JavaScript?
Choose 3 answers

Answer: A,C,D


NEW QUESTION # 76
A class was written to represent regular items and sale items. Code:
01 let regItem = new Item('Scarf', 55);
02 let saleItem = new SaleItem('Shirt', 80, .1);
03 Item.prototype.description = function() { return 'This is a ' + this.name; }
04 console.log(regItem.description());
05 console.log(saleItem.description());
06
07 SaleItem.prototype.description = function() { return 'This is a discounted ' + this.name; }
08 console.log(regItem.description());
09 console.log(saleItem.description());
What is the output?

Answer: C

Explanation:
At line 03, the developer assigns:
Item.prototype.description = function() { return 'This is a ' + this.name; } This affects all objects whose prototype chain includes Item.prototype.
regItem inherits from Item → gets this method.
saleItem, as an instance of SaleItem, also inherits Item.prototype (since SaleItem uses prototype inheritance from Item), so it also has this method at this moment.
Outputs at lines 04 and 05:
regItem.description() → "This is a Scarf"
saleItem.description() → "This is a Shirt"
At line 07, the developer overrides the method on SaleItem.prototype:
SaleItem.prototype.description = function() {
return 'This is a discounted ' + this.name;
}
From this point:
regItem still uses the Item.prototype version
saleItem uses the overridden SaleItem.prototype version
Outputs at lines 08 and 09:
regItem.description() → "This is a Scarf"
saleItem.description() → "This is a discounted Shirt"
Combining all results:
This is a Scarf
This is a Shirt
This is a Scarf
This is a discounted Shirt
This matches option B.
JavaScript Knowledge Reference (text-only)
Objects created from constructor functions use prototype chaining.
Overriding a subclass prototype method does not affect the parent class prototype.
Instances inherit the most specific version of the method on their prototype chain.


NEW QUESTION # 77
......

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