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Salesforce JS-Dev-101 Exam Overview:

Certification Vendor:Salesforce
Exam Name:Salesforce Certified JavaScript Developer I - Multiple Choice Exam (JS-Dev-101)
Exam Number:JS-Dev-101
Available Languages:English
Real Exam Qty:60 (multiple choice)
Passing Score:65%
Related Certifications:Salesforce Platform Developer I
Salesforce Platform Developer II
Exam Format:Multiple Select Questions, Multiple Choice Questions
Certificate Validity Period:1 year (maintenance required annually in Salesforce certification program)
Exam Price:$200 USD
Exam Duration:105 minutes
Recommended Training:MDN Web Docs - JavaScript Guide
Salesforce Trailhead - JavaScript Developer I
Exam Registration:Kryterion Webassessor (Exam Delivery)
Salesforce Certification Registration
Sample Questions:Salesforce JS-Dev-101 Sample Questions
Exam Way:Online proctored exam via Salesforce authorized testing platform (e.g., Webassessor)
Pre Condition:No formal prerequisites, but familiarity with JavaScript and web development is recommended.
Official Syllabus URL:https://trailhead.salesforce.com/credentials/javascriptdeveloper

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Salesforce JS-Dev-101 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Browser and Events: Covers DOM manipulation, event handling and propagation, browser-specific APIs, and using Browser Developer Tools to inspect code behavior.
Topic 2
  • Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.
Topic 3
  • Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
Topic 4
  • Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
Topic 5
  • Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.

Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q79-Q84):

NEW QUESTION # 79
A developer creates a simple webpage with an input field. When a user enters text and clicks the button, the actual value must be displayed in the console:
HTML:
<input type="text" value="Hello" name="input">
<button type="button">Display</button>
JavaScript:
01 const button = document.querySelector('button');
02 button.addEventListener('click', () => {
03 const input = document.querySelector('input');
04 console.log(input.getAttribute('value'));
05 });
When the user clicks the button, the output is always "Hello".
What needs to be done to make this code work as expected?

Answer: B

Explanation:
getAttribute('value')
This returns the initial HTML attribute, not the live, updated value.
Even if the user edits the text, the value attribute remains "Hello" because HTML attributes do not update dynamically.
Input elements have a property value that always reflects the live current text inside the field.
So:
input.value
returns the user-entered value.
Therefore, line 04 must use the property, not the attribute:
console.log(input.value);
This ensures the updated input value is displayed.
JavaScript knowledge references (text-only)
HTML attributes are static and retrieved using getAttribute().
DOM element properties (like value) represent the current live state.
Input value changes update the .value property, not the attribute.


NEW QUESTION # 80
A developer uses a parsed JSON string to work with user information as in the block below:
01 const userInformation = {
02 "id": "user-01",
03 "email": "user01@universalcontainers.demo",
04 "age": 25
05 };
Which two options access the email attribute in the object?

Answer: A,D

Explanation:
userInformation is a plain JavaScript object:
{
id: "user-01",
email: "user01@universalcontainers.demo",
age: 25
}
You can access object properties in two standard ways:
Dot notation: object.propertyName
Bracket notation: object['propertyName']
Apply to each option:
A . userInformation.email
Correct dot notation; accesses "user01@universalcontainers.demo".
B . userInformation.get("email")
.get() is a method on Map instances, not on plain objects.
A regular object does not have a .get method; this would be TypeError.
C . userInformation["email"]
Correct bracket notation; string "email" is used as the property key.
Returns "user01@universalcontainers.demo".
D . userInformation[email]
Here email is treated as a variable, not a string literal.
Unless there is a variable named email defined with a value matching a property key, this will either:
Throw a ReferenceError (if email is not defined), or
Use the value of email as a computed key (not what is intended here).
It is not the correct way to access the "email" property literal.
Therefore, the correct ways are:
Answe r: A, C
Relevant concepts: object property access (. vs []), plain objects vs Map, literal property names vs computed property names.


NEW QUESTION # 81
A developer at Universal Containers is creating their new landing pagebased on HTML, CSS, and JavaScript. The website includes multiple external resources that are loaded when the page is opened.
To ensure that visitors have a good experience, a script named personalizeWebsiteContent needs to be executed when the webpage isloaded and there is no need to wait for the resources to be available.
Which statement should be used to call personalizeWebsiteContent based on the above business requirement?

Answer: C


NEW QUESTION # 82
Refer to the code:
01 const exec = (item, delay) =>
02 new Promise(resolve => setTimeout(() => resolve(item), delay));
03
04 async function runParallel() {
05 const [result1, result2, result3] = await Promise.all(
06 [exec('x', '100'), exec('y', '500'), exec('z', '100')]
07 );
08 return `parallel is done: ${result1}${result2}${result3}`;
09 }
Which two statements correctly execute runParallel()?

Answer: C,D

Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge Facts about JavaScript Promises:
runParallel() is declared async, which means it always returns a Promise.
Promises are consumed using .then(), .catch(), and .finally().
There is no .done() method in native JavaScript Promises.
The async keyword cannot be placed before a function call (option A is invalid syntax).
Analysis of each option:
A . async runParallel().then(data);
Invalid syntax. async cannot prefix an expression.
B . Valid. Calls the function and attaches a .then() handler.
C . Invalid. .done() is not part of JavaScript Promise API.
D . Valid. Calls runParallel() and chains .then().
Therefore the correct answers are B and D.
________________________________________
JavaScript Knowledge Reference (text-only)
async functions return Promises.
Promises use .then() to retrieve resolved values.
.done() is not part of the standard Promise interface.


NEW QUESTION # 83
Refer to the code below:
01 let sayHello = () => {
02 console.log('Hello, World!');
03 };
Which code executes sayHello once, two minutes from now?

Answer: B

Explanation:
To schedule a function for later execution in JavaScript, the standard built-in method is:
setTimeout(functionReference, delayInMilliseconds)
Characteristics of setTimeout():
Executes only once.
Delay is specified in milliseconds.
Requires passing the function reference, not calling the function.
Two minutes is:
2 minutes = 120 seconds = 120,000 milliseconds
Now evaluate each option:
Option A: delay(sayHello, 120000);
Incorrect.
There is no built-in delay() function in JavaScript.
Option B: setTimeout(sayHello, 120000);
Correct.
sayHello is passed as a function reference, so it will execute once after 120,000 ms.
Option C: setTimeout(sayHello(), 120000);
Incorrect.
sayHello() calls the function immediately, and the return value (undefined) is passed to setTimeout.
This executes the function right away instead of after two minutes.
Option D: setInterval(sayHello, 120000);
Incorrect.
setInterval() repeats execution every 120,000 ms.
The question requires executing the function once, so this cannot be correct.
JavaScript Knowledge Reference (text-only)
setTimeout() schedules a function to run once after a specified delay.
Passing functionName gives a reference; passing functionName() invokes it immediately.
setInterval() repeats indefinitely, unlike setTimeout().


NEW QUESTION # 84
......

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