現在の社会で人材があちこちいます。IT領域でも同じです。コンピュータの普及につれて、パソコンを使えない人がほとんどいなくなります。ですから、IT業界で勤めているあなたはプレッシャーを感じていませんか。学歴はどんなに高くてもあなたの実力を代表できません。学歴はただ踏み台だけで、あなたの地位を確保できる礎は実力です。IT職員としているあなたがどうやって自分自身の実力を養うのですか。IT認定試験を受験するのは一つの良い方法です。App-Development-with-Swift-Certified-User試験を通して、あなたは新しいスキルをマスターすることができるだけでなく、App-Development-with-Swift-Certified-User認証資格を取得して自分の高い能力を証明することもできます。最近、Apple App-Development-with-Swift-Certified-User試験の認証資格がとても人気があるようになりましたが、受験したいですか。
| Section | Objectives |
|---|---|
| User Interface Development | - Building iOS interfaces
|
| Introduction to App Development with Swift | - Swift programming fundamentals
|
| App Lifecycle and Deployment Concepts | - Understanding app structure
|
| App Logic and Data Handling | - Data management in apps
|
>> App-Development-with-Swift-Certified-User最新関連参考書 <<
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質問 # 31
Review the code snippet.
Move each item from the list on the left to the correct code segment on the right. You may use each item only once.
Note: You will receive partial credit for each correct response.
正解：
解説：
Explanation:
This question belongs to Swift Programming Language , specifically the domain covering structs, properties, methods, and initializers .
A computed property does not store a value directly. Instead, it returns a value calculated from other data.
That is why description is a computed property: it returns a string based on content.
A memberwise initializer is automatically provided by Swift for structs when their stored properties are initialized through parameters. So Document(content: " Greetings! " ) is using the struct's memberwise initializer.
A type property belongs to the type itself rather than to an instance. In Swift, static var docCount = 0 is a type property because it is declared with static.
An instance method is a function that belongs to an instance of the struct or class. The display() method uses the instance's content, so it is an instance method.
A type method is a method declared with static and belongs to the type itself. So static func increment() is a type method because it changes the shared type property docCount.
質問 # 32
Given the function definition, which two statements call the function correctly? (Choose 2.)
Based on the image provided, here is the text for each of the multiple-choice options:
正解：A、C
解説：
This question belongs to Swift Programming Language , specifically the objective on functions , including internal and external parameter names and default parameter values .
The function is defined as:
func schedule(who name: String, from starting: String, to ending: String, _ place: String = " Zoom " ) { print( " Appointment: meeting \(name) from \(starting) to \(ending) at \(place) " )
}
This means:
* the external parameter names are who, from, and to
* the internal parameter names are name, starting, and ending
* the last parameter uses _, which means it has no external label
* the last parameter also has a default value of " Zoom "
Now evaluate the options:
* A is incorrect because it uses place: as an external label, but _ place means no external label is allowed.
* B is correct because it uses the required external names who, from, and to, and it omits the last parameter, which is allowed because it has a default value.
* C is incorrect because it uses who:, from:, and to: correctly, but this function's first three parameters are not declared that way in the provided option set; the valid matching call style from the choices is not this one because the function's labels are paired with internal names in the declaration syntax shown in the question.
* D is incorrect because it uses the internal names name, starting, and ending as if they were external labels.
* E is correct because it uses the external labels who, from, and to, and omits the final unlabeled parameter, letting Swift use the default " Zoom " .
So the two correct answers are B and E .
質問 # 33
Complete the code that conforms to the View protocol by selecting the correct option from each drop-down list.
Note: You will receive partial credit for each correct answer.
正解：
解説：
Explanation:
This question belongs to View Building with SwiftUI , especially the domain covering positioning and/or layout a single SwiftUI View with standard Views and modifiers and the foundational structure of a SwiftUI view. In SwiftUI, a custom screen is typically declared as a struct that conforms to the View protocol. Apple's SwiftUI documentation shows the standard pattern:
struct ScreenView: View {
var body: some View {
Text( " Hello " )
}
}
Here, struct is required because SwiftUI views are commonly defined as structures. View is required after the colon because the type must conform to the View protocol. body is the required computed property that returns the content of the view as some View. Apple documents that every conforming View type must provide a body property that describes its content.
So the completed code is:
import SwiftUI
struct ScreenView: View {
var body: some View {
Text( " Hello " )
}
}
This is the canonical SwiftUI view declaration pattern and is one of the most fundamental concepts in App Development with Swift.
質問 # 34
Complete the code that will add the BlueView to the NavigationStack and present the RedView modally.
|Complete the code by typing in the boxes.
正解：
解説：
NavigationLink, .sheet
Explanation:
This question falls under View Building with SwiftUI , specifically the domain covering multi-view apps with navigation stacks, links, and sheets . The first blank must be NavigationLink because SwiftUI uses a navigation link inside a NavigationStack to push or present a destination view as part of the navigation hierarchy. Apple's documentation states that people tap or click a NavigationLink to present a view inside a NavigationStack or NavigationSplitView. That matches the first code section, where tapping " Show Blue View " should navigate to BlueView().
The second blank must be .sheet because the code uses isPresented: $showRedView, which is the standard SwiftUI sheet modifier for modal presentation controlled by a Boolean binding. Apple documents sheet (isPresented:onDismiss:content:) as the modifier to use when you want to present a modal view when a Boolean becomes true. Since the button toggles showRedView, SwiftUI presents RedView() modally as a sheet.
So the completed structure is effectively:
NavigationLink( " Show Blue View " ) {
BlueView()
}
sheet(isPresented: $showRedView) {
RedView()
}
This directly aligns with SwiftUI navigation and modal presentation patterns in the App Development with Swift objective domains.
質問 # 35
Review the code.
Note: You might need to scroll to see the entire block of code.
A breakpoint is set on line 3. When the application is run. it will stop at line 3. You need to debug the code.
Drag each debugging control from the left to the correct instruction on the right. You will receive partial credit for each correct answer
正解：
解説：
Explanation:
This question belongs to Xcode Developer Tools , especially the objective on using debugging techniques including breakpoints and stepping controls .
When execution stops at a breakpoint on line 3, Step Over runs that line without entering into another function call, so it is the correct action for moving past line 3 while staying in the current function. Step Into is used when execution reaches line 4 and you want to enter the display(numbers) function, which takes you into the function body starting at line 8. Once inside that function, Step Out continues execution until the current function returns, which is exactly what "step out from line 8" means.
Deactivate breakpoints turns breakpoint handling off so the debugger no longer stops on active breakpoints.
Continue program execution resumes the app until the next breakpoint or until the program finishes.
So the correct control order is:
1 = Continue
2 = Deactivate breakpoints
3 = Step Over
4 = Step Into
5 = Step Out
質問 # 36
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