Exam Applied-Algebra Overview - Latest Applied-Algebra Examprep

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WGU Applied-Algebra Exam Syllabus Topics:

Section	Objectives
Functions and Graphs	- Function Concepts 1. Function notation 2. Domain and range - Graphing Functions 1. Transformations of graphs 2. Coordinate plane interpretation
Polynomial and Rational Expressions	- Rational Expressions 1. Simplification 2. Restrictions on variables - Polynomials 1. Operations with polynomials 2. Factoring techniques
Exponential and Logarithmic Concepts	- Exponential Functions 1. Exponential equations 2. Growth and decay models - Logarithmic Basics 1. Conversion between exponential and logarithmic form 2. Logarithm properties
Foundations of Algebra	- Equations and Inequalities 1. Linear equations in one variable 2. Inequalities and interval notation - Algebraic Expressions 1. Simplifying expressions 2. Order of operations 3. Evaluating expressions
Linear Functions and Systems	- Linear Equations 1. Point-slope form 2. Slope-intercept form - Systems of Equations 1. Substitution method 2. Elimination method

>> Exam Applied-Algebra Overview <<

Marvelous Exam Applied-Algebra Overview | Easy To Study and Pass Exam at first attempt & First-Grade Applied-Algebra: WGU Applied Algebra FXO2 PFXP C957

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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q101-Q106):

NEW QUESTION # 101
The graph shows the number of people waiting in a virtual queue to buy tickets for an event.
What does the horizontal asymptote mean?

A. As time passes, the number of people in the queue approaches 100.
B. The number of people in the queue was initially 750.
C. Eventually, the number of people in the queue will decrease to 0.
D. Over time, the number of people in the queue will increase back up to 750.

Answer: A

Explanation:
The graph shows the queue size changing over time.
The horizontal axis represents:
" Time in minutes "
The vertical axis represents:
" Queue size "
The graph is a decreasing exponential curve. It starts near 750people and decreases quickly at first. Then the curve begins to flatten near:
y=100
A horizontal asymptote is the horizontal line that the graph approaches as time continues.
Here, the graph approaches the horizontal line:
y=100
This means that as time passes, the number of people in the virtual queue gets closer and closer to 100.
It does not mean the queue decreases to 0, because the graph levels off near 100, not near 0.
Therefore, the correct interpretation is:
" As time passes, the number of people in the queue approaches 100. "

NEW QUESTION # 102
The graph shows the number of trees sold by a nursery, where the number of days since the beginning of the month is along the horizontal axis and the number of trees sold per day is along the vertical axis. The greatest number of trees are sold when the temperature is over 70°F.

When was the temperature likely over 70°F?

A. The temperature was likely over 70°F on days 6 and 12.
B. The temperature was likely over 70°F on days 2 and 10.
C. The temperature was likely over 70°F on only day 6.
D. The temperature was likely over 70°F on only day 2.

Answer: B

Explanation:
The problem states that the greatest number of trees are sold when the temperature is over 70°F. Therefore, we need to identify the days on the graph when tree sales are highest. The graph shows two major peaks in the number of trees sold per day. These peaks occur around day 2 and day 10. Since higher tree sales are linked to temperatures over 70°F, those two days are the most likely days when the temperature exceeded 70°F. Day 6 appears near a low point, so it is not likely associated with high temperature based on the given relationship.
Day 12 also does not match the main peaks. Therefore, the correct answer is C.

NEW QUESTION # 103
The population of bison in a preserve can be modeled using the logistic function f(x), where x represents the number of years since the preserve was established and f(x) represents the population. The graph of f(x) is shown.

How does the bison population change as time progresses from year 7 to year 10?

A. The bison population decreases slower and slower.
B. The bison population decreases faster and faster.
C. The bison population increases slower and slower.
D. The bison population increases faster and faster.

Answer: C

Explanation:
A logistic function often increases quickly in the middle and then begins to level off as it approaches a maximum carrying capacity. From year 7 to year 10, the graph is still increasing, so the bison population is going up. However, the curve is becoming flatter during this interval. A flatter curve means the slope is getting smaller, so the population is increasing at a slower rate. This behavior is described as "increases slower and slower." It is not decreasing, because the graph continues to move upward. It is also not increasing faster and faster, because the slope is not becoming steeper in this interval. Therefore, the correct interpretation is answer B.

NEW QUESTION # 104
A researcher collected data on the number of daily posts on a blog. The results are shown in the scatterplot.
The graphed regression function has an r
2
value of 0.89.

Is it appropriate to make a prediction for the number of daily posts after 18.6 months?

A. No. The r2value indicates a strong fit, but x=18.6 is more than 50% of the range beyond the maximum value.
B. Yes. The r2value indicates a strong fit, and x=18.6 is within 50% of the range of the maximum value.
C. No. The r2value indicates a moderate fit, but x=18.6 is more than 25% of the range beyond the maximum value.
D. Yes. The r2value indicates a moderate fit, and x=18.6 is within 25% of the range of the maximum value.

Answer: B

Explanation:
The value r2=0.89 indicates a strong fit because it is close to 1. A strong fit means the regression function follows the scatterplot data closely enough to support reasonable prediction. The question asks whether a prediction at x=18.6 months is appropriate. This value is outside the observed data range, so the prediction involves extrapolation. For a strong regression model, extrapolation can be acceptable if the new x-value is not too far beyond the maximum observed value. Here, x=18.6 is within 50% of the range beyond the maximum value, so the prediction is considered appropriate. Therefore, the correct answer is C.

NEW QUESTION # 105
As a drone travels away from an operator, the function G(x)=24+47x models the distance, in yards, between the drone and the operator at x minutes. What is the value of G(1.9)?

A. 0
B. 113.3
C. 1
D. 1.88

Answer: B

Explanation:
This is a linear function evaluation problem. The function G(x)=24+47x gives the drone's distance from the operator after x minutes. The constant 24 is the starting distance, and 47 is the rate of change in yards per minute. To evaluate G(1.9), substitute 1.9 for x. Then compute G(1.9)=24+47(1.9). Multiplying first gives
47×1.9=89.3. Adding 24 gives 113.3. Because the function measures distance in yards, the result means the drone is 113.3 yards from the operator after 1.9 minutes. The other options do not result from correctly substituting 1.9 into the function. Therefore, the correct answer is D.

NEW QUESTION # 106
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