Fortinet FCSS_NST_SE-7.6 New Test Materials & FCSS_NST_SE-7.6 Free Exam

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Fortinet FCSS_NST_SE-7.6 Exam Syllabus Topics:

TopicDetails
Topic 1
  • VPN: This section is aimed at IT Professionals and includes diagnosing and addressing issues with IPsec VPNs, specifically IKE version 1 and 2, to secure remote and site-to-site connections within the network infrastructure.
Topic 2
  • Routing: This section focuses on Network Engineers and involves tackling issues related to packet routing using static routes, as well as OSPF and BGP protocols to support enterprise network traffic flow.
Topic 3
  • Security profiles: This part measures skills of Security Operations Specialists and covers identifying and resolving problems linked to FortiGuard services, web filtering configurations, and intrusion prevention systems to maintain protection across network environments.
Topic 4
  • System troubleshooting: This section of the exam measures the skills of Network Security Support Engineers and addresses diagnosing and correcting issues within Security Fabric setups, automation stitches, resource utilization, general connectivity, and different operation modes in FortiGate HA clusters. Candidates work with built-in tools to effectively find and resolve faults.
Topic 5
  • Authentication: This section evaluates the abilities of System Administrators and requires troubleshooting both local and remote authentication methods, including resolving Fortinet Single Sign-On (FSSO) problems for secure network access.

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Fortinet FCSS - Network Security 7.6 Support Engineer Sample Questions (Q97-Q102):

NEW QUESTION # 97
Refer to the exhibit, which shows the partial output of a diagnose command.

Which two conclusions can you draw from the output shown in the exhibit? (Choose two.)

Answer: B,C


NEW QUESTION # 98
Refer to the exhibit, which shows the partial output of a real-time OSPF debug.

Why are the two FortiGate devices unable to form an adjacency?

Answer: D


NEW QUESTION # 99
What is the correct order of the IKEv2 request-and-response protocol?

Answer: A

Explanation:
The Internet Key Exchange version 2 (IKEv2) protocol simplifies the negotiation process compared to IKEv1.
It is defined by a specific sequence of message exchanges to establish a secure IPsec tunnel.
The correct chronological order of the IKEv2 exchanges is:
* IKE_SA_INIT (Initial Exchange):
* This is the first exchange. It negotiates the security parameters for the IKE Security Association (IKE SA), sends nonces, and performs the Diffie-Hellman key exchange. At the end of this exchange, the communication is encrypted, but the peers are not yet authenticated.
* IKE_AUTH (Authentication Exchange):
* This is the second exchange. It authenticates the previous messages, exchanges identities and certificates (if used), and establishes the first Child SA (the actual IPsec Security Association used for data traffic).
* CREATE_CHILD_SA (Subsequent Exchanges):
* This exchange occurs after the IKE SA and the initial Child SA are established. It is used to create additional Child SAs (for different traffic selectors) or to perform re-keying for the IKE SA or existing Child SAs.
Why other options are incorrect:
* A & B: Incorrect because CREATE_CHILD_SA cannot happen before the SA is initialized (IKE_SA_INIT) and authenticated (IKE_AUTH).
* D: Incorrect because IKE_AUTH cannot occur before IKE_SA_INIT.
Therefore, the protocol flow is IKE_SA_INIT $\rightarrow$ IKE_AUTH $\rightarrow$ CREATE_CHILD_SA.


NEW QUESTION # 100
Refer to the exhibit.

The output of diagnose sys session list command is shown.
If the HA ID for the primary device is 9, what happens if the primary fails and the secondary becomes the primary?

Answer: C

Explanation:
The output of the diagnose sys session list command provides the critical evidence needed to determine the behavior during a failover:
Session Synchronization (synced):
The most important indicator in the exhibit is the synced flag located in the state= line (state=may_dirty synced none app_ntf).
In FortiOS HA (High Availability), the synced flag confirms that this specific session has been successfully synchronized from the primary device to the secondary (backup) device.
Session synchronization (Session Pickup) ensures that if the primary unit fails, the secondary unit already has the session in its table and can resume traffic processing immediately.
TCP State (proto_state=01):
The output shows proto=6 (TCP) and proto_state=01.
In the FortiGate session table, proto_state=01 for TCP indicates that the session is in the ESTABLISHED state (post-three-way handshake).
This invalidates Option B, which claims the TCP session is not fully established.
Failover Outcome:
Because the session is ESTABLISHED and SYNCED, the secondary device will seamlessly take over the session upon primary failure.
The traffic continues to flow through the new primary without requiring the user/client to restart the connection. This is the primary function of HA Session Pickup.
Why other options are incorrect:
A: While the output shows app_ntf (Application Control notification) and may_dirty, the presence of the synced flag overrides this concern regarding failover. If the session type were not supported for failover (e.g., certain proxy sessions in older versions), it would not be marked as synced. Since it is synced, it persists.
B: As noted, proto_state=01 means established, not " not fully established " .
D: While the kernel updates routing tables, the purpose of syncing the session is to preserve the state so it does not need to be re-evaluated as a new packet would, preventing traffic drops.
Reference:
FortiGate Security 7.6 Study Guide (High Availability): " If session pickup is enabled, the primary unit synchronizes its session table... to the backup unit. If the primary unit fails, the backup unit... continues to process the sessions with no interruption. "


NEW QUESTION # 101
Which two statements about application-layer test commands are true? (Choose two answers)

Answer: B,C

Explanation:
The correct answers are A and D.
The study guide states:
"Application layer test commands do not display information in real time. They display statistics and configuration information about a feature or process. You can also use some of these commands to restart a process or execute a change in its operation." This directly proves:
A is correct because they can display statistics and configuration information D is correct because some of them can restart a process/application Why the other options are wrong:
B is wrong because the study guide explicitly says application-layer test commands do not display information in real time. Real-time output is done with diagnose debug application ... commands instead.
C is wrong because diagnose debug console enable is related to debug output behavior, not a requirement for application-layer test commands to display output. The study guide does not describe test commands that way.
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NEW QUESTION # 102
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