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Huawei H12-811_V2.0 Exam Syllabus Topics:

Topic	Details
Topic 1	Network Security and Services: Covers essential network security mechanisms including ACLs, AAA, NAT, and basic firewall concepts to protect network infrastructure.
Topic 2	IP Technology Basics: Covers IPv4 IPv6 addressing, subnetting, routing fundamentals, and common routing protocols such as OSPF, RIP, and static routing.
Topic 3	Data Center Network Basics: Covers the architecture and key technologies used in modern data center networks including virtualization and high-availability design concepts.
Topic 4	Ethernet Technology Basics: Covers Ethernet standards, switching principles, VLANs, and Layer 2 protocols used in enterprise network environments.
Topic 5	Typical Campus Networking Solution: Covers end-to-end campus network design scenarios, integrating switching, routing, security, and wireless technologies into a unified solution.
Topic 6	WLAN Technology Basics: Covers wireless LAN standards, components such as APs and ACs, WLAN architecture, and basic configuration principles.
Topic 7	Network O&M and Troubleshooting: Covers network operation and maintenance practices, common diagnostic tools, and methodologies for identifying and resolving network faults.

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Huawei HCIA-Datacom V2.0 Sample Questions (Q29-Q34):

NEW QUESTION # 29
Radio waves are a type of electromagnetic waves with relatively high frequencies and short wavelengths in the electromagnetic spectrum.

A. FALSE
B. TRUE

Answer: B

Explanation:
Radio waves are part of the electromagnetic spectrum and are characterized by relatively low frequency and long wavelength compared to other types such as microwaves, infrared, and visible light. However, they still belong to the broader category of electromagnetic waves, so the statement correctly identifies them as electromagnetic waves, making it true.

NEW QUESTION # 30
Which of the following hosts are reachable to the host at 192.168.1.200/27 at Layer 2? (Select all that apply)

A. 192.168.1.192/27
B. 192.168.1.221/27
C. 192.168.1.193/27
D. 192.168.1.222/27

Answer: B,C,D

Explanation:
A /27 subnet mask is 255.255.255.224, which means each subnet contains 32 IP addresses. The subnet increments in blocks of 32 in the last octet: 0, 32, 64, 96, 128, 160, 192, 224. The address 192.168.1.200/27 belongs to the subnet 192.168.1.192/27.
For this subnet, the network address is 192.168.1.192, the broadcast address is 192.168.1.223, and the valid host range is from 192.168.1.193 to 192.168.1.222. Therefore, 192.168.1.221/27, 192.168.1.193/27, and
192.168.1.222/27 are all valid host addresses in the same subnet and are reachable at Layer 2 without routing.
That makes A, C, and D correct.
Option B is not correct because 192.168.1.192/27 is the network address of the subnet and cannot be assigned to a host by default. This question checks IP subnetting and the ability to identify valid hosts within the same broadcast domain.

NEW QUESTION # 31
Assume you need to assign IP addresses from different networks to four departments, which have 100, 50, 32, and 31 hosts, respectively. Assigning addresses from subnet 192.168.1.0/24 cannot meet this requirement.

A. FALSE
B. TRUE

Answer: B

Explanation:
A /24 network (192.168.1.0/24) provides 256 IP addresses, with 254 usable host addresses.
Using VLSM, the host requirements are 100, 50, 32, and 31, which require subnet sizes of 128,
64, 64, and 64 addresses respectively (since 32-host and 31-host networks both need /26 or larger depending on usable host calculation). The total required address space exceeds what can be efficiently allocated within a single /24 network without overlap or waste constraints.

NEW QUESTION # 32
If PC1 obtains an IPv6 address through SLAAC, which of the following is the network prefix length of the address that PC1 receives?

A. 0
B. 1
C. 2
D. 3

Answer: D

Explanation:
In SLAAC (Stateless Address Autoconfiguration), IPv6 hosts always use a 64-bit interface identifier with a /64 network prefix. The router advertisement provides a /64 prefix, and the host generates the remaining 64 bits for its interface ID.

NEW QUESTION # 33
On the network shown in the figure, the administrator creates Eth-Trunk 1 in manual mode on SW1 and SW2, and adds GE1/0/1 and GE1/0/2 on both switches to the Eth-Trunk. After the administrator runs the display interface brief command on SW1, the administrator finds that GE1/0/1 is Up and GE1/0/2 is Down. Which of the following statements is true about this scenario?

A. Eth-Trunk 1 is Down because it has only two member interfaces and the minimum number of active links is not reached after one member interface is Down.
B. Eth-Trunk 1 is Down because the states of member interfaces must be the same in manual mode.
C. Eth-Trunk 1 is Down because all member interfaces of the Eth-Trunk must be Up.
D. Eth-Trunk 1 is Up because it is Up as long as one member interface is Up.

Answer: D

Explanation:
For an Eth-Trunk operating in manual load-balancing mode, the logical Eth-Trunk interface can remain Up as long as at least one member link is operational and properly added to the trunk.
Therefore, if GE1/0/1 is Up and GE1/0/2 is Down, Eth-Trunk 1 can still stay Up, making option A correct.

NEW QUESTION # 34
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