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The learning material is available in three different easy-to-use forms. The first one is a PDF form. The students can save the JavaScript-Developer-I questions by taking out their prints or can access them on their smartphones, tablets, and laptops. The PDF form can be used anywhere anytime and is essential for applicants who like to learn from their smart devices. The second form is Salesforce Certified JavaScript Developer (JS-Dev-101) (JavaScript-Developer-I) web-based practice test which can be taken from browsers like Firefox, Microsoft Edge, Google Chrome, and Safari.
Earning the Salesforce Certified JavaScript Developer I certification demonstrates a candidate's proficiency in developing custom applications using JavaScript in Salesforce. Salesforce Certified JavaScript Developer (JS-Dev-101) certification is a valuable asset for individuals seeking to advance their careers in Salesforce development or for organizations looking to hire skilled Salesforce developers. Salesforce Certified JavaScript Developer (JS-Dev-101) certification also provides access to the Salesforce Certified Community, which offers networking opportunities, exclusive resources, and ongoing support for Salesforce developers.
What is the duration, language, and format of Salesforce JavaScript-Developer-I Exam
- This exam is offered in only English.
- Passing score 65%
- There is a time limit of 105 minutes for the exam.
- The type of questions is Multiple Choice and situation-based questions.
- This exam consists of 60 questions
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Salesforce JavaScript-Developer-I Exam is an essential certification for anyone who plans to develop applications on the Salesforce platform using JavaScript. It demonstrates a person’s proficiency in developing secure and scalable applications that can be customized to meet specific business needs. By passing JavaScript-Developer-I Exam, candidates can enhance their career prospects, increase job opportunities, and develop a strong foundation in Salesforce development.
Salesforce Certified JavaScript Developer (JS-Dev-101) Sample Questions (Q63-Q68):
NEW QUESTION # 63
Refer to the following code that imports a module named utils:
import (foo, bar) from '/path/Utils.js';
foo() ;
bar() ;
Which two implementations of Utils.js export foo and bar such that the code above runs without error?
Choose 2 answers
- A. const foo = () => { return 'foo';}
const bar = () => {return 'bar'; }
Export default foo, bar; - B. const foo = () => { return 'foo' ; }
const bar = () => { return 'bar' ; }
export { bar, foo } - C. // FooUtils.js and BarUtils.js exist
Import (foo) from '/path/FooUtils.js';
Import (boo) from ' /path/NarUtils.js'; - D. Export default class {
foo() { return 'foo' ; }
bar() { return 'bar' ; }
}
Answer: B,D
NEW QUESTION # 64
A developer has two ways to write a function:
Option A:
01 function Monster() {
02 this.growl = () = > {
03 console.log( " Grr! " );
04 }
05 }
Option B:
01 function Monster() {};
02 Monster.prototype.growl = () = > {
03 console.log( " Grr! " );
04 }
After deciding on an option, the developer creates 1000 monster objects. How many growl methods are created with Option A and Option B?
- A. 1000 growl methods are created for Option A. 1 growl method is created for Option B.
- B. 1 growl method is created for Option A. 1000 growl methods are created for Option B.
- C. 1000 growl methods are created regardless of which option is used.
- D. 1 growl method is created regardless of which option is used.
Answer: A
Explanation:
Option A:
* this.growl = () = > { ... } inside the constructor creates a new function per instance .
* For 1000 new Monster(), you get 1000 distinct growl functions , each stored on the instance itself.
Option B:
* Monster.prototype.growl = () = > { ... } attaches growl to the prototype.
* All instances share the same single growl function via the prototype chain.
* For 1000 instances, only 1 growl method exists in memory.
So: Option A # 1000; Option B # 1.
NEW QUESTION # 65
A developer creates a generic function to log custom messages In the console. To do this, the function below is implemented.

Which three console logging methods allow the use of string substitution in line 02?
Choose 3 answers
- A. Log
- B. error
- C. Assert
- D. Info
- E. Message
Answer: B,C,E
NEW QUESTION # 66
Given the following code:
01 counter = 0;
02 const logCounter = () = > {
03 console.log(counter);
04 };
05 logCounter();
06 setTimeout(logCounter, 2100);
07 setInterval(() = > {
08 counter++;
09 logCounter();
10 }, 1000);
What will be the first four numbers logged?
- A. 0112
- B. 0123
- C. 0122
- D. 0012
Answer: C
Explanation:
We need to track the value of counter and the timing of each call to logCounter.
Initial state:
* Line 01: counter = 0;
* Line 02-04: logCounter logs the current value of counter.
Execution order and timing:
* Line 05: logCounter();
* Called immediately at time t = 0 ms.
* counter is 0.
* First log: 0.
* Line 06: setTimeout(logCounter, 2100);
* Schedules logCounter to run once after 2100 ms.
* No log yet at this line.
* Line 07-10: setInterval(() = > { counter++; logCounter(); }, 1000);
* Schedules a repeating callback every 1000 ms (1 second).
* First interval callback runs at t # 1000 ms.
Now follow the timeline:
* t = 0 ms:
* logCounter(); from line 05
* Logs: 0
* t = 1000 ms (first interval execution):
* counter++; # counter goes from 0 to 1.
* logCounter(); logs 1.
* t = 2000 ms (second interval execution):
* counter++; # counter goes from 1 to 2.
* logCounter(); logs 2.
* t = 2100 ms (timeout from line 06):
* logCounter(); runs again.
* counter is still 2 (next setInterval will be at t = 3000 ms).
* Logs 2.
So the first four logs are:
* 0
* 1
* 2
* 2
Concatenated as in the options: 0122.
Therefore, the correct choice is:
The answer: A
Study Guide / Concept References (no links):
* setTimeout and setInterval timing behavior
* Order of execution in the event loop
* Closures capturing variables (here, logCounter using counter)
* Understanding asynchronous scheduling in JavaScript
NEW QUESTION # 67
const str = ' Salesforce ' ;
Which two statements result in the word " Sales " ?
- A. str.substr(s, 5);
- B. str.substr(0, 5);
- C. str.substring(0, 5);
- D. str.substring(0, 5);
Answer: B,D
Explanation:
Comprehensive and Detailed Explanation:
* " Salesforce " indices: S(0) a(1) l(2) e(3) s(4) f(5) ...
A / C (substring(0, 5)):
* substring(start, end) returns characters from start up to but not including end.
* str.substring(0, 5) # characters at indices 0,1,2,3,4 # " Sales " .
D (substr(0, 5)):
* substr(start, length) returns length characters starting at start.
* str.substr(0, 5) # 5 chars from index 0 # " Sales " .
B is invalid because s is not defined; it should be 0. So the two correct statements are A and D.
NEW QUESTION # 68
......
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