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Salesforce JS-Dev-101 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
Topic 2
  • Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
Topic 3
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.

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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q45-Q50):

NEW QUESTION # 45
Given the code below:
01 function GameConsole (name) {
02 this.name = name;
03 }
04
05 GameConsole.prototype.load = function(gamename) {
06 console.log( ` $(this.name) is loading agame : $(gamename) ...`);
07 )
08 function Console 16 Bit (name) {
09 GameConsole.call(this, name) ;
10 }
11 Console16bit.prototype = Object.create ( GameConsole.prototype) ;
12 //insert code here
13 console.log( ` $(this.name) is loading a cartridge game :$(gamename) ...`);
14 }
15 const console16bit = new Console16bit(' SNEGeneziz ');
16 console16bit.load(' Super Nonic 3x Force ');
What should a developer insert at line 15 to output the following message using the method ?
> SNEGeneziz is loading a cartridgegame: Super Monic 3x Force . . .

Answer: A


NEW QUESTION # 46
A developer initiates a server with the file server.js and adds dependencies in the source code's package.json that are required to run the server.
Which command should the developer run to start the server locally?

Answer: B

Explanation:
Comprehensive and Detailed Explanation From JavaScript/Node.js Knowledge:
In a Node.js project that uses package.json, you typically define a "start" script:
{
"scripts": {
"start": "node server.js"
}
}
Then you start the app with:
npm start
npm start:
Looks up the "start" script in package.json.
Runs the command defined there (commonly node server.js).
This is the standard way to start a Node.js app with npm-managed dependencies.
Why others are incorrect:
A . node start
Tries to run a file named start with Node; does not use package.json scripts.
C . npm start server.js
npm start does not take the script filename as an argument in this way; it just runs the start script as defined.
D . start server.js
Not an npm or node command; on some shells it just tries to "start" a process but is not the standard Node/npm workflow.
Relevant concepts: package.json, npm scripts, npm start, Node entry file execution.


NEW QUESTION # 47
Refer to the following code:
01 let obj = {
02 foo: 1,
03 bar: 2
04 }
05 let output = []
06
07 for (let something of obj) {
08 output.push(something);
09 }
10
11 console.log(output);
What is the value of output on line 11?

Answer: B

Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
The key line is:
for (let something of obj) {
In JavaScript:
for...of is used to iterate over iterable objects, such as:
Arrays
Strings
Maps
Sets
Other objects that implement a [Symbol.iterator] method.
Plain JavaScript objects created with object literal {} are not iterable by default. They do not have [Symbol.iterator], so using for...of directly on them causes a runtime error.
Specifically:
for (let something of obj) { ... }
will throw a TypeError similar to:
obj is not iterable
Therefore, the loop body never executes, and console.log(output); is never reached without an error.
Why other options are incorrect:
B . [1, 2]
To get [1, 2], you could use Object.values(obj) and iterate that array.
But here, for...of obj never yields values because it throws an error.
C . ["foo", "bar"]
To get property names, you could use Object.keys(obj) with for...of.
Again, the code does not do that; it incorrectly tries to iterate the object directly.
D . ["foo:1", "bar:2"]
You would need both keys and values, combining them manually.
The given code does not implement such logic and fails before pushing anything into output.
Hence, the correct answer is:
Answe r: A
Study Guide / Concept Reference (no links):
Difference between for...of and for...in
Iterables in JavaScript and [Symbol.iterator]
Plain objects {} are not iterable by default
Correct patterns to iterate object keys/values (Object.keys, Object.values, Object.entries)
________________________________________


NEW QUESTION # 48
A developer writes the code below to return a message to a user attempting to register a new username. If the username is available, a variable named msg is declared and assigned a value on line 03.
```javascript
function getAvailabilityMessage(item) {
if (getAvailability(item)) {
var msg = "Username available";
return msg;
}
}

Answer: A


NEW QUESTION # 49
Refer to the code below:
01 const objBook = {
02 title: 'JavaScript',
03 };
04 Object.preventExtensions(objBook);
05 const newObjBook = objBook;
06 newObjBook.author = 'Robert';
What are the values of objBook and newObjBook respectively?

Answer: A

Explanation:
Object.preventExtensions(obj)
This built-in JavaScript method marks an object so that no new properties can be added to it.
Existing properties can still be read and updated, but adding new ones is disallowed.
const newObjBook = objBook;
Both variables reference the same object in memory. JavaScript objects are assigned by reference, not copied.
newObjBook.author = "Robert";
Because the object has been marked as non-extensible, JavaScript will not allow new properties to be added.
The behavior depends on mode:
In non-strict mode: the assignment silently fails and does nothing.
In strict mode: this would throw a TypeError.
Since nothing indicates strict mode, this is non-strict behavior, making the assignment fail silently.
Therefore, the object remains:
{ title: "JavaScript" }
Both objBook and newObjBook point to the same unchanged object.
This matches option A.
JavaScript knowledge references (text-only)
Object.preventExtensions() prevents adding new properties.
Assigning an object to another variable copies the reference, not the object.
Adding a property to a non-extensible object silently fails in non-strict mode.


NEW QUESTION # 50
......

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