Applied-Algebra Latest Exam Dumps - Related Applied-Algebra Exams

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WGU Applied-Algebra Exam Syllabus Topics:

SectionObjectives
Topic 1: Linear Functions and Systems- Linear Equations
  • 1. Slope-intercept form
    • 2. Point-slope form
      - Systems of Equations
      • 1. Elimination method
        • 2. Substitution method
          Topic 2: Functions and Graphs- Function Concepts
          • 1. Function notation
            • 2. Domain and range
              - Graphing Functions
              • 1. Coordinate plane interpretation
                • 2. Transformations of graphs
                  Topic 3: Polynomial and Rational Expressions- Rational Expressions
                  • 1. Simplification
                    • 2. Restrictions on variables
                      - Polynomials
                      • 1. Operations with polynomials
                        • 2. Factoring techniques
                          Topic 4: Exponential and Logarithmic Concepts- Logarithmic Basics
                          • 1. Conversion between exponential and logarithmic form
                            • 2. Logarithm properties
                              - Exponential Functions
                              • 1. Growth and decay models
                                • 2. Exponential equations
                                  Topic 5: Foundations of Algebra- Equations and Inequalities
                                  • 1. Inequalities and interval notation
                                    • 2. Linear equations in one variable
                                      - Algebraic Expressions
                                      • 1. Order of operations
                                        • 2. Evaluating expressions
                                          • 3. Simplifying expressions

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                                            100% Pass-Rate Applied-Algebra Latest Exam Dumps bring you Fast-download Related Applied-Algebra Exams for WGU WGU Applied Algebra FXO2 PFXP C957

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                                            WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q90-Q95):

                                            NEW QUESTION # 90
                                            The function f(z) represents the relationship between the number of units in two inventories, where z is the number of units in inventory A and f(z) is the number of units in inventory B. The number of units in inventory B is 2 more than the number of units in inventory A. Which function represents this situation?

                                            Answer: A

                                            Explanation:
                                            This problem translates a verbal statement into function notation. The variable z represents the number of units in inventory A, and f(z) represents the number of units in inventory B. The phrase "2 more than" tells us to add 2 to the number of units in inventory A. That gives the rule f(z)=z+2. For example, if inventory A has
                                            10 units, then inventory B has f(10)=12 units. Option A subtracts 2, option C multiplies by 2, and option D divides by 2, so those do not match the stated relationship. Because inventory B is always exactly 2 more than inventory A, the correct function is f(z)=z+2. Therefore, the answer is B.


                                            NEW QUESTION # 91
                                            The function V(t)represents the number of travelers, V, in a travel depot thours after 7:00 a.m. The graph of V (t)is shown.

                                            What does V(2)represent?

                                            Answer: A

                                            Explanation:
                                            The function V(t)represents the number of travelers in the travel depot.
                                            The input trepresents:
                                            " hours after 7:00 a.m. "
                                            The output V(t)represents:
                                            " number of travelers "
                                            So V(2)means the number of travelers in the depot:
                                            2 " hours after 7:00 a.m. "
                                            From the graph, when:
                                            t=2
                                            the value of V(t)is approximately:
                                            79.2
                                            Since V(t)measures travelers, not hours, V(2)represents:
                                            79.2 " travelers "
                                            Therefore, the correct answer is:
                                            # ( " D " )


                                            NEW QUESTION # 92
                                            The data in the scatterplot represents the number of monthly train crossings at a particular intersection over time.

                                            Which type of function should be used to model the data?

                                            Answer: D

                                            Explanation:
                                            The scatterplot shows the number of monthly train crossings decreasing over time. The decrease is not constant from one year to the next, so a linear model is not the best choice. Instead, the data decreases quickly at first and then begins to level off, which is characteristic of exponential decay. Exponential models are appropriate when a quantity changes by a repeated factor or percentage over equal time intervals. A logistic model would usually show an S-shaped pattern with a carrying capacity, and a polynomial model would be more appropriate for turning points or more complex curvature. Since the points show a smooth decreasing curve that flattens over time, an exponential function best models the data. Therefore, the correct answer is B.


                                            NEW QUESTION # 93
                                            The growth of an animal population is shown in the graph. The instantaneous rate of change at point Pis 3.74.

                                            Which interpretation of the instantaneous rate of change is correct?

                                            Answer: A

                                            Explanation:
                                            The graph shows population in thousands, and the horizontal axis represents:
                                            " years since 1995 "
                                            Point Pis located at approximately:
                                            x=12
                                            Since xrepresents years since 1995:
                                            1995+12=2007
                                            So point Pcorresponds to the year:
                                            2007
                                            The instantaneous rate of change at point Pis:
                                            3.74
                                            Because the vertical axis is measured in thousands, this means:
                                            3.74 " thousand animals per year "
                                            Convert thousands to actual animals:
                                            3.74×1000=3740
                                            So in 2007, the population was increasing by approximately:
                                            3,740 " animals per year "


                                            NEW QUESTION # 94
                                            The graph shows the number of people watching a live video. The number of minutes since the video began is on the horizontal axis, and the number of viewers is on the vertical axis. When were there 432 viewers?
                                            Exhibit:

                                            Answer: A

                                            Explanation:
                                            This problem requires reading a value from a graph. The horizontal axis gives time in minutes, and the vertical axis gives the number of viewers. To solve it, find 432 on the vertical axis, locate where the graph reaches that value, and then move down to the horizontal axis. From the exhibit, the graph reaches 432 viewers at minute 1. That means the ordered pair is approximately (1, 432), so the input is 1 minute and the output is 432 viewers. The other listed minutes correspond to different viewer counts on the graph. In graphical depictions, matching the correct input-output pair is the key step. Therefore, the correct answer is B.


                                            NEW QUESTION # 95
                                            ......

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