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| Section | Weight | Objectives |
|---|---|---|
| Routing | 9% | - Static routing configuration - Dynamic routing protocols - Routing topology design |
| Management and Monitoring | 7% | - Aruba Central management platform - Network monitoring tools - Health and performance assessment |
| Network Resiliency and Virtualization | 8% | - Redundancy and fault tolerance - Virtual switching concepts - Infrastructure device management |
| Connectivity | 10% | - Foundational networking architectures - Infrastructure deployment principles |
| Authentication and Authorization | 6% | - AAA concepts and operation - Access control methods |
| Switching | 19% | - VLANs, trunking and STP - Layer 2/Layer 3 technologies - Campus architecture design - Aruba CX switch configuration |
| WLAN | 18% | - Roaming and mobility basics - Radio Frequency (RF) attributes - AP configuration and groups - WLAN security and SSID setup |
| Performance Optimization | 3% | - QoS principles and implementation |
| Security | 9% | - Security standards and concepts - Wired and wireless security policies - ACLs and traffic filtering - ClearPass integration basics |
| Network Stack | 7% | - OSI Model layers and architectural elements - TCP/IP stack concepts |
| Troubleshooting | 4% | - Common network issues resolution - Troubleshooting methodologies |
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NEW QUESTION # 34
How does a single Aruba CX 6300M switch configuration use L3 connectivity to establish routing traffic between switch virtual interfaces 120 and 130?
Answer: A
Explanation:
On an Aruba CX 6300M switch, routing between Switch Virtual Interfaces (SVIs) is enabled by default. Therefore, traffic between SVIs, like 120 and 130, can be routed internally without the need for additional configuration such as route leaking or static routes, as long as there is no 'no routing' configuration present on the SVIs.
NEW QUESTION # 35
What is the correct command to add a static route to a class-c-network 10.2.10.0 via a gateway of
172.16.1.1?
Answer: B
Explanation:
The correct command to add a static route to a class-c-network 10.2.10.0 via a gateway of 172.16.1.1 is ip-route 10.2.10.0/24 172.16.1.1. This command specifies the destination network address (10.2.10.0) and prefix length (/24) and the next-hop address (172.16.1 .1) for reaching that network from the switch.
The other commands are either incorrect syntax or incorrect parameters for adding a static route.
References: https://www.arubanetworks.com/techdocs/AOS-CX_10_04/NOSCG/Content/cx-noscg/ip- routing/sta
NEW QUESTION # 36
When using the OSPF dynamic routing protocol on an Aruba CX switch, what must match on the neighboring devices to exchange routes?
Answer: B
Explanation:
OSPF Open Shortest Path First. OSPF is a link-state routing protocol that uses a hierarchical structure to create a routing topology for IP networks. OSPF routers exchange routing information with their neighbors using Hello packets, which are sent periodically on each interface. To establish an adjacency Adjacency is a relationship formed between selected neighboring routers for the purpose of exchanging routing information., OSPF routers must agree on several parameters, including Hello timers, which specify how often Hello packets are sent on an interface. If the Hello timers do not match between neighboring routers, they will not form an adjacency and will not exchange routes. References:https://www.arubanetworks.com/techdocs
/ArubaOS_86_Web_Help/Content/arubaos-solutions/osfp/osfp.htm
NEW QUESTION # 37
Which flew in a Layer 3 IPv4 packet header is used to mitigate Layer 3 route loops?
Answer: C
Explanation:
The field in a Layer 3 IPv4 packet header that is used to mitigate Layer 3 route loops is Time To Live (TTL).
TTL is an 8-bit field that indicates the maximum number of hops that a packet can traverse before being discarded. TTL is set by the source device and decremented by one by each router that forwards the packet. If TTL reaches zero, the packet is dropped and an ICMP Internet Control Message Protocol (ICMP) Internet Control Message Protocol (ICMP) is a network protocol that provides error reporting and diagnostic functions for IP networks. ICMP is used to send messages such as echo requests and replies (ping), destination unreachable, time exceeded, parameter problem, source quench, redirect, etc. ICMP messages are encapsulated in IP datagrams and have a specific format that contains fields such as type, code, checksum, identifier, sequence number, data, etc. ICMP messages can be verified by using commands such as ping , traceroute , debug ip icmp , etc . message is sent back to the source device. TTL is used to mitigate Layer 3 route loops because it prevents packets from circulating indefinitely in a looped network topology. TTL also helps to conserve network resources and avoid congestion caused by looped packets.
The other options are not fields in a Layer 3 IPv4 packet header because:
* Checksum: Checksum is a 16-bit field that is used to verify the integrity of the IP header. Checksum is calculated by the source device and verified by the destination device based on the values of all fields in the IP header. Checksum does not mitigate Layer 3 route loops because it does not limit the number of hops that a packet can traverse.
* Protocol: Protocol is an 8-bit field that indicates the type of payload carried by the IP datagram.
Protocol identifies the upper-layer protocol that uses IP for datatransmission, such as TCP Transmission Control Protocol (TCP) Transmission Control Protocol (TCP) is a connection-oriented transport layer protocol that provides reliable, ordered, and error-checked delivery of data between applications on different devices . TCP uses a three-way handshake to establish a connection between two endpoints , and uses sequence numbers , acknowledgments , and windowing to ensure data delivery and flow control . TCP also uses mechanisms such as retransmission , congestion avoidance , and fast recovery to handle packet loss and congestion . TCP segments data into smaller units called segments , which are encapsulated in IP datagrams and have a specific format that contains fields such as source port , destination port , sequence number , acknowledgment number , header length , flags , window size , checksum , urgent pointer , options , data , etc . TCP segments can be verified by using commands such as telnet , ftp , ssh , debug ip tcp transactions , etc . , UDP User Datagram Protocol (UDP) User Datagram Protocol (UDP) is a connectionless transport layer protocol that provides
NEW QUESTION # 38
Which statement is correct when comparing 5 GHz and 6 GHz channels with identical channel widths?
Answer: D
Explanation:
The correct statement when comparing 5 GHz and 6 GHz channels with identical channel widths is that 5 GHz channels travel different distances and provide different throughputs to clients compared to 6 GHz channels. This statement reflects the fact that higher frequency signals tend to have higher attenuation Attenuation is a general term that refers to any reduction in signal strength during transmission over distance or through an object or medium. Higher attenuation means that higher frequency signals have shorter range and lower throughput than lower frequency signals.
Some facts about this statement are:
- 5 GHz channels have lower frequency than 6 GHz channels, which means they have lower attenuation than 6 GHz channels.
- Lower attenuation means that 5 GHz channels can travel longer distances and provide higher throughputs to clients than 6 GHz channels with identical channel widths.
- However, the difference in distance and throughput between 5 GHz and 6 GHz channels may not be significant in indoor environments where there are many obstacles and reflections that affect signal propagation.
- The advantage of using 6 GHz channels over 5 GHz channels is that they offer more spectrum availability, less interference, and more non-overlapping channels than 5 GHz channels.
The other options are not correct because:
- 5 GHz channels travel the same distances and provide different throughputs to clients compared to 6 GHz channels: This option is false because 5 GHz channels do not travel the same distances as 6 GHz channels due to higher attenuation of higher frequency signals.
- 5 GHz channels travel the same distances and provide the same throughputs to clients compared to 6 GHz channels: This option is false because 5 GHz channels do not travel the same distances or provide the same throughputs as 6 GHz channels due to higher attenuation of higher frequency signals.
- 5 GHz channels travel different distances and provide the same throughputs to clients compared to 6 GHz channels: This option is false because 5 GHz channels do not provide the same throughputs as 6 GHz channels due to higher attenuation of higher frequency signals.
NEW QUESTION # 39
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