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Oracle 1z0-071 Exam Syllabus Topics:

Section	Weight	Objectives
Using DDL Statements to Create and Manage Tables	14%	- Categorize the main database objects - Review the table structure - Describe the data types that are available for columns - Alter table definitions - Create a simple table - Drop, rename, and truncate tables
Working with Oracle Database SQL	8%	- Describe the Oracle Database architecture - Start up and shut down a database - Explain the installation of Oracle Database software - Create a container database
Using Conversion Functions and Conditional Expressions	10%	- Describe implicit and explicit data type conversion - Use conditional IF THEN ELSE logic in a SELECT statement - Use the TO_CHAR, TO_NUMBER, and TO_DATE conversion functions - Apply the NVL, NULLIF, and COALESCE functions to data
Manipulating Data	14%	- Insert rows into a table - Delete rows from a table - Control transactions - Describe each data manipulation language (DML) statement - Update rows in a table
Displaying Data from Multiple Tables Using Joins	15%	- Join a table to itself by using a self-join - Cross join tables - View data that does not meet a join condition by using outer joins - Write SELECT statements to access data from more than one table using equijoins and non-equijoins
Reporting Aggregated Data Using Group Functions	15%	- Include or exclude grouped rows by using the HAVING clause - Group data by using the GROUP BY clause - Identify the available group functions - Describe the use of group functions
Restricting and Sorting Data	6%	- Use ampersand substitution to restrict and sort output at runtime - Limit the rows that are retrieved by a query - Sort the rows that are retrieved by a query - Use DEFINE and UNDEFINE commands
Retrieving Data Using the SQL SELECT Statement	5%	- List the capabilities of SQL SELECT statements - Execute a basic SELECT statement - Differentiate between SQL statements and SQL*Plus commands
Creating Other Schema Objects	10%	- Create synonyms for database objects - Create, maintain, and use sequences - Create and maintain indexes - Create, modify, and retrieve data from a view
Using Subqueries to Solve Queries	15%	- Define subqueries - Describe the types of problems that subqueries can solve - List the types of subqueries - Write single-row and multi-row subqueries
Controlling User Access	5%	- Grant privileges on tables and on a view - Differentiate system privileges from object privileges - Distinguish between granting privileges and roles
Using Single-Row Functions to Customize Output	10%	- Describe the differences between single-row and multiple-row functions - Manipulate numbers with the ROUND, TRUNC, and MOD functions - Perform arithmetic with date data - Manipulate strings with character function in the SELECT and WHERE clauses - Manipulate dates with the date functions
Using Set Operators	5%	- Describe set operators - Use a set operator to combine multiple queries into a single query - Describe the order of precedence when the set operators are used

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Oracle Database SQL Sample Questions (Q125-Q130):

NEW QUESTION # 125
You need to display the first names of all customers from the CUSTOMERS table that contain the character 'e' and have the character 'a' in the second last position.
Which query would give the required output?

A. SELECT cust_first_name
FROM customers
WHERE INSTR(cust_first_name, 'e')IS NOT NULL AND
SUBSTR(cust_first_name, 1, -2)='a';
B. SELECT cust_first_name
FROM customers
WHERE INSTR(cust_first_name, 'e')<>'' AND
SUBSTR(cust_first_name, -2, 1)='a';
C. SELECT cust_first_name
FROM customers
WHERE INSTR(cust_first_name, 'e')<>0 AND
SUBSTR(cust_first_name, LENGTH(cust_first_name), -2)='a';
D. SELECT cust_first_name
FROM customers
WHERE INSTR(cust_first_name, 'e')<>0 AND
SUBSTR(cust_first_name, -2, 1)='a';

Answer: D

NEW QUESTION # 126
Choose two
Examine the description of the PRODUCT DETALS table:

A. EXPIRY_DATE contains the SYSDATE by default if no date is assigned to it
B. PRODUCT_NAME cannot contain duplicate values.
C. PRODUCT_PRICE can be used in an arithmetic expression even if it has no value stored in it
D. PRODUCT_ID can be assigned the PEIMARY KEY constraint.
E. PRODUCT_PRICE contains the value zero by default if no value is assigned to it.
F. EXPIRY_DATE cannot be used in arithmetic expressions.

Answer: C,D

NEW QUESTION # 127
Which two are true about the data dictionary?

A. All users have permissions to access all information in the data dictionary by default.
B. The SYS user owns all base tables and user-accessible views in the data dictionary.
C. The data dictionary is constantly updated to reflect changes to database objects, permissions, and data.
D. All user actions are recorded in the data dictionary.
E. Base tables in the data dictionary have the prefix DBA_.

Answer: B,E

NEW QUESTION # 128
In your session NLS_ DATE_ FORMAT is set to DD-MON_RR.
Which two queries display the year as four digits?

A. SELECT TO_CHAR (ADD_MONTHS (SYSDATE,6)) FROM DUAL;
B. SELECT TO_DATE (SYSDATE, 'RRRR-MM-DD') FROM DUAL;
C. SELECT TO_CHAR (SYSDATE, 'MM/DD/YYYY') FROM DUAL;
D. SELECT TO_DATE (ADD_MONTHS(SYSDATE,6), 'dd-mon-yyyy') FROM DUAL;
E. SELECT TO_CHAR (ADD_MONTHS (SYSDATE, 6), 'dd-mon-yyyy') FROM DUAL;
F. SELECT TO_DATE(TO_CHAR(SYSDATE,'MM/DD/YYYY'),'MM/DD/YYYY') FROM DUAL;

Answer: C,F

Explanation:
A). True. The TO_CHAR function will convert SYSDATE to a string using the format 'MM/DD/YYYY', which displays the year as four digits. Then TO_DATE will convert this string back to a date without changing its appearance because the format matches.
E). True. The TO_CHAR function with the format 'MM/DD/YYYY' will display the date with the year as four digits, regardless of the NLS_DATE_FORMAT setting.
B, C, D, and F are incorrect because they either do not specify the format model needed to display the year as four digits or use TO_DATE which does not format the output but rather interprets the input.

NEW QUESTION # 129
View the Exhibit and examine the structure of the PORDUCT_INFORMATION table. (Choose the best answer.)

PRODUCT_ID column is the primary key.
You create an index using this command:
SQL > CREATE INDEX upper_name_idx
ON product_information(UPPER(product_name));
No other indexes exist on the PRODUCT_INFORMATION table.
Which query would use the UPPER_NAME_IDX index?

A. SELECT UPPER(product_name)
FROM product_information;
B. SELECT UPPER(product_name)
FROM product_information
WHERE product_id = 2254;
C. SELECT product_id, UPPER(product_name)
FROM product_information
WHERE UPPER(product_name) = 'LASERPRO' OR list_price > 1000;
D. SELECT product_id
FROM product_information
WHERE UPPER(product_name) IN ('LASERPRO', 'CABLE');

Answer: D

NEW QUESTION # 130
......

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