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| Section | Weight | Objectives |
|---|
| Topic 1: Data Transformation and Data Modeling | 22%-30% | - Design data models
- 1. Data vault models
- 2. Star schema design
- 3. Snowflake schema design
- Transform data using SQL
- 1. Window functions
- 2. QUALIFY clauses
- 3. Common Table Expressions (CTEs)
- 4. PIVOT/UNPIVOT operations
|
| Topic 2: Data Ingestion and Data Preparation | 15%-20% | - Perform data discovery to identify what is needed from available datasets
- 1. Evaluate required transformations (table joins, set operations, ASOF JOINS)
- 2. Determine the level of data granularity required
- 3. Query tables to assess data elements and statistics maintained by Snowflake
- 4. Use commands to read metadata or alter context (DESCRIBE, SHOW, USE)
- 5. Identify elements required for business goals using BI reports or SQL analysis
- Enrich data by identifying and accessing relevant data from the Snowflake Marketplace
- 1. Find external data sets that correlate with available data
- 2. Create tables and views
- 3. Use Secure Data Sharing (Marketplace, Internal Marketplace, Private Listings, Listings)
- Prepare data and load into Snowflake
- 1. Load files using Snowsight
- 2. Load data from external/internal stages into a table
- Use best practice considerations relating to data integrity structures
- 1. Perform table joins between parent/child tables
- 2. Define primary keys for tables
- 3. Implement constraints
- Implement data processing solutions
- 1. Automate and implement data pipelines (scheduling)
- 2. Use logging and monitoring solutions (auditing, data lineage)
- 3. Respond to processing failures
- 4. Cleanse, conform, and enrich data
- Use a collection system to retrieve data
- 1. Retrieve data from semi-structured sources (Parquet, Avro, ORC, JSON, XML)
- 2. Synthetic Data Generation
- 3. Retrieve data from unstructured sources
- 4. Retrieve data from structured sources (CSV)
|
| Topic 3: Data Analysis | 30%-32% | - Perform advanced analytics using SQL
- 1. Time-series analysis
- 2. Aggregate functions
- 3. Snowflake-specific analytical features
|
| Topic 4: Data Presentation and Data Visualization | 28%-29% | - Create dashboards
- 1. Snowsight dashboards
- 2. Present analytical results
- Integrate with BI tools
- 1. Other partner visualization tools
- 2. Tableau integration
- 3. Power BI integration
|
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Snowflake SnowPro Advanced: Data Analyst Certification Exam Sample Questions (Q38-Q43):
NEW QUESTION # 38
A Snowflake data analyst needs to identify the top 5 most common errors occurring in a data loading pipeline over the past week. The error messages are stored in a table named 'LOAD ERRORS' with columns 'error_timestamp' (TIMESTAMP NTZ) and 'error message' (VARCHAR). Which SQL query provides the most efficient and accurate way to retrieve this information, ordered by frequency?

- A. Option E
- B. Option D
- C. Option A
- D. Option B
- E. Option C
Answer: C
Explanation:
Option A is the most efficient and accurate. It uses 'DATEADD with to ensure the correct time frame is considered (including the current time), and 'GROUP BY and 'ORDER BY are used correctly to find the top 5 most frequent errors. Option B excludes errors happening today by using 'CURRENT_DATE(Y. Option C casts error_timestamp to DATE which can impact performance and might cause issues if the index is available on error_timestamp, but not DATE(error_timestamp). Option D only shows errors from the current week. Option E is incorrect. It returns error_timestamp which is a date, therefore its incorrect
NEW QUESTION # 39
You are analyzing customer order data in Snowflake and need to determine if there is a statistically significant correlation between the number of items in an order ('ITEM COUNT) and the total order value CORDER VALUE'). You have a table named 'ORDERS' with columns 'ORDER ID', 'ITEM COUNT', and 'ORDER VALUE'. Which of the following Snowflake functions or methods, used in combination, would be the MOST appropriate and statistically sound for calculating the correlation coefficient between these two variables, taking into account the need to handle potential NULL values appropriately?
- A. Use 'AVG' and 'STDDEV_POP functions to calculate the mean and standard deviation for both and Then, manually compute the correlation coefficient using these statistics.
- B. Use 'QUALIFY Clause with 'CORR function to determine the coefficient values, and then apply statistical significance tests manually by calculating p-values.
- C. First, replace NULL values in both 'ITEM COUNT and 'ORDER _ VALUE with 0 using 'COALESCE, then apply the 'CORR function.
- D. Use the 'CORR function directly on the 'ITEM_COUNT and 'ORDER_VALUE columns. No special handling is needed for NULL values as 'CORR automatically ignores them.
- E. Use a combination of 'WHERE clause to filter out rows where either 'ITEM COUNT or 'ORDER VALUE is NULL, and then apply the 'CORR function to the filtered data.
Answer: E
Explanation:
The 'CORR function in Snowflake can calculate the Pearson correlation coefficient. However, NULL values can affect the result. Option E correctly handles this by explicitly filtering out rows containing NULL values in either column using a 'WHERE' clause, ensuring that the 'CORR function is applied only to complete pairs of data. Replacing NULL with zero can skew the distribution. Manual computation using AVG and STDDEV POP are more error prone and time taking.
NEW QUESTION # 40
You are building a sales performance dashboard in Snowflake. You need to incorporate a custom metric called 'Sales Efficiency', which is calculated as (Total Sales Revenue / Number of Sales Representatives) 1000. You want to expose this metric in your dashboard and allow users to filter data based on specific Sales Efficiency ranges. You also want to allow filtering by region and quarter. Which of the following approaches would be MOST performant and maintainable in Snowflake?
- A. Create a Snowflake view that calculates 'Sales Efficiency'. The dashboard queries filter this view using standard WHERE clauses for region and quarter. No indexes or partition keys are created.
- B. Calculate 'Sales Efficiency' directly in the dashboard tool for each query using its expression engine. Implement region and quarter filtering within the dashboard tool.
- C. Create a Snowflake stored procedure that calculates 'Sales Efficiency' based on the selected Region and Quarter. The dashboard calls the stored procedure and displays the returned result set.
- D. Create a Snowflake user-defined function (IJDF) in JavaScript to calculate 'Sales Efficiency'. Use this IJDF in the dashboard queries, along with standard WHERE clauses for region and quarter filtering.
- E. Create a materialized view in Snowflake that pre-calculates 'Sales Efficiency', region, and quarter. Include appropriate indexes and partition keys on the view. Expose the materialized view to the dashboard.
Answer: E
Explanation:
A materialized view (option C) is the most performant option. It pre-calculates the 'Sales Efficiency' metric and stores the results, allowing for fast retrieval. Proper indexing and partitioning further optimize query performance. Performing the calculation in the dashboard tool (option A) is inefficient for large datasets. IJDFs (option B) can be slower than native SQL. A regular view (option D) does not store the pre- calculated data, so the calculation is performed every time the view is queried. Stored procedures are typically less efficient for dashboard queries than materialized views, as they need to be executed each time.
NEW QUESTION # 41
You are preparing data for analysis in Snowflake. You have two tables: 'Products' (ProductlD, ProductName, CategorylD) and 'Categories' (CategorylD, CategoryName). You need to create a view that combines product and category information, but also needs to efficiently handle situations where a 'ProductlD' might be missing a 'CategorylD' assignment in the 'Products' table. Furthermore, you need to ensure the view performs optimally for ad-hoc querying by analysts. Which of the following SQL statements creates the MOST performant and robust view, ensuring minimal impact from missing 'CategorylD' values?
- A. CREATE VIEW ProductCategories AS SELECT ProductlD, ProductName, (SELECT CategoryName FROM Categories WHERE CategorylD =Products.CategorylD) AS CategoryName FROM Products;
- B. CREATE VIEW ProductCategories AS SELECT p.ProductlD, p.ProductName, NVL(c.CategoryName, 'Unknown') AS CategoryName FROM Products p LEFT JOIN Categories c ON p.CategorylD = c.CategorylD;
- C. CREATE OR REPLACE VIEW ProductCategories AS SELECT p.ProductlD, p.ProductName, CASE WHEN c.CategoryName IS NULL THEN 'Unknown' ELSE c.CategoryName END AS CategoryName FROM Products p LEFT JOIN Categories c ON p.CategorylD = c.CategorylD;
- D. CREATE VIEW ProductCategories AS SELECT p.ProductlD, p.ProductName, c.CategoryName FROM Products p INNER JOIN Categories c ONp.CategorylD = c.CategorylD;
- E. CREATE VIEW ProductCategories AS SELECT p.ProductlD, p.ProductName, c.categoryName FROM Products p FULL OUTER JOIN categories c ON p.CategorylD = c.CategorylD;
Answer: B
Explanation:
The best option is B. It uses a 'LEFT JOIN' to ensure all products are included, even those without a 'CategorylD' in the 'Categories' table. ' NVL' efficiently handles 'NULL' values in 'CategoryName' by replacing them with 'Unknown'. A 'FULL OUTER JOIN' (option A) is not appropriate as we specifically need all Products. Using 'CASE WHEN' (option C) is functionally equivalent to 'NVL' but often less efficient. 'INNER JOIN' (option D) will exclude products without a matching 'Categoryl[Y. The subquery approach (option E) is highly inefficient and will not perform well, especially with large tables.
NEW QUESTION # 42
What distinguishes exploratory ad-hoc analyses from routine analysis?
- A. Ad-hoc analyses rely heavily on predefined queries.
- B. Ad-hoc analyses focus solely on anomalies and established trends.
- C. Ad-hoc analyses explore patterns and anomalies beyond established routines.
- D. They involve querying known patterns without further exploration.
Answer: C
Explanation:
Ad-hoc analyses explore patterns and anomalies beyond established routines.
NEW QUESTION # 43
......
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