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| Section | Objectives |
|---|
| Topic 1: Subqueries and Advanced SQL | - Single-row and multi-row subqueries - Correlated subqueries and nested queries
|
| Topic 2: SQL Functions | - Single-row functions
- 1. Character, numeric, date functions
- Conversion and conditional functions
- 1. TO_CHAR, TO_NUMBER, CASE expressions
|
| Topic 3: SQL Retrieval | - SELECT statements and filtering data
- 1. WHERE clause and conditions
- 2. ORDER BY and row limiting
- Joins and set operations
- 1. UNION, INTERSECT, MINUS
- 2. INNER, OUTER, CROSS joins
|
| Topic 4: Data Manipulation and Schema Objects | - DML operations
- 1. INSERT, UPDATE, DELETE, MERGE
- DDL operations
- 1. CREATE, ALTER, DROP tables and constraints
|
| Topic 5: Relational Database Concepts | - Data types and database objects overview - Tables, rows, columns, and relational model basics
|
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Oracle Database SQL Sample Questions (Q120-Q125):
NEW QUESTION # 120
Examine the SQL statement used to create the TRANSACTION table. (Choose the best answer.) SQL > CREATE TABLE transaction (trn_id char(2) primary key,
Start_date date DEFAULT SYSDATE,
End_date date NOT NULL);
The value 'A1' does not exist for trn_id in this table.
Which SQL statement successfully inserts a row into the table with the default value for START_DATE?
- A. INSERT INTO transaction (trn_id, end_date) VALUES ('A1', '10-DEC-2014')
- B. INSERT INTO transaction VALUES ('A1', DEFAULT, TO_DATE('SYSDATE+10'))
- C. INSERT INTO transaction VALUES ('A1', DEFAULT, TO_DATE(DEFAULT+10))
- D. INSERT INTO transaction (trn_id, start_date, end_date) VALUES ('A1', , '10-DEC-2014')
Answer: A
NEW QUESTION # 121
View the Exhibit and examine the structure of the CUSTOMERS table.

Which two tasks would require subqueries or joins to be executed in a single statement? (Choose two.)
- A. listing of those customers whose credit limit is the same as the credit limit of customers residing in the city 'Tokyo'
- B. finding the average credit limit of male customers residing in 'Tokyo' or 'Sydney'
- C. finding the number of customers, in each city, whose marital status is 'married'
- D. finding the number of customers, in each city, whose credit limit is more than the average credit limit of all the customers
- E. listing of customers who do not have a credit limit and were born before 1980
Answer: A,D
Explanation:
Describe the Types of Problems That the Subqueries Can Solve
There are many situations where you will need the result of one query as the input for
another.
Use of a Subquery Result Set for Comparison Purposes
Which employees have a salary that is less than the average salary? This could be
answered by two statements, or by a single statement with a subquery. The following
example uses two statements:
select avg(salary) from employees;
select last_name from employees where salary < result_of_previous_query ;
Alternatively, this example uses one statement with a subquery:
select last_name from employees where salary < (select avg(salary)from employees);
In this example, the subquery is used to substitute a value into the WHERE clause of the
parent query: it is returning a single value, used for comparison with the rows retrieved by
the parent query.
The subquery could return a set of rows. For example, you could use the following to find
all departments that do actually have one or more employees assigned to them:
select department_name from departments where department_id in
(select distinct(department_id) from employees);
NEW QUESTION # 122
In the EMPLOYEEStable there are 1000 rows and employees are working in the company for more than 10 years.
Evaluate the following SQL statement:

What would be the result?
- A. It executes successfully but no rows updated.
- B. It gives an error because multiple NVLfunctions are used in an expression.
- C. It gives an error because NVLfunction cannot be used with UPDATE.
- D. It executes successfully and updates the records of those employees who have been working in the company for more than 600 days.
Answer: D
NEW QUESTION # 123
n the customers table, the CUST_CITY column contains the value 'Paris' for the CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:
What would be the outcome?
- A. An error message
- B. Abigail PA
- C. Abigail Pa
- D. Abigail IS
Answer: C
NEW QUESTION # 124
Which two are true about the precedence of opertors and condtions
- A. AND and OR have the same order of precedence in a condition
- B. || has a higher order of precedence than +(addition)
- C. Operators are evaluated before conditions.
- D. + (addition) has a higher order of precedence than * (mliplpition)
- E. NOT has a higher order of precedence than AND and OR in a condition.
Answer: B,E
Explanation:
Regarding the precedence of operators and conditions in Oracle Database 12c:
* Option B: NOT has a higher order of precedence than AND and OR in a condition.
* In logical operations, NOT is evaluated first, followed by AND and then OR.
* Option E: || has a higher order of precedence than +(addition).
* The string concatenation operator || has a higher precedence than the arithmetic + operator.
Options A, C, and D are incorrect because:
* Option A: Multiplication (*) has a higher precedence than addition (+).
* Option C: AND has a higher precedence than OR.
* Option D: Conditions (which may contain operators) are evaluated according to the rules of operator precedence.
NEW QUESTION # 125
......
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