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Oracle 1z0-071 Exam Overview:

Certification Vendor:	Oracle
Exam Name:	Oracle Database SQL
Exam Number:	1Z0-071
Available Languages:	Chinese (Simplified), Spanish, Japanese, Portuguese, English
Exam Format:	Proctored exam, Computer-based exam, Multiple Response, Multiple Choice
Related Certifications:	Oracle Database Development certifications Oracle Database Administrator Certified Associate
Certificate Validity Period:	Non-expiring (Oracle certification policy subject to change)
Exam Price:	USD 245 (varies by country/region)
Exam Duration:	120 minutes
Recommended Training:	Oracle Database SQL Training
Exam Registration:	Oracle Certification Registration
Sample Questions:	Oracle 1z0-071 Sample Questions
Exam Way:	Online proctored or test center delivery depending on region
Pre Condition:	No formal prerequisites required; basic knowledge of relational databases and SQL recommended.
Official Syllabus URL:	https://education.oracle.com/oracle-database-sql/pexam_1Z0-071

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New 1z0-071 Exam Objectives - Valid 1z0-071 Test Pass4sure

The Oracle 1z0-071 certification exam is one of the valuable credentials designed to demonstrate a candidate's technical expertise in information technology. They can remain current and competitive in the highly competitive market with the 1z0-071 certificate. For novices as well as seasoned professionals, the Oracle Database SQL Questions provide an excellent opportunity to not only validate their skills but also advance their careers.

Oracle 1z0-071 Exam, also known as the Oracle Database SQL exam, is a certification that validates an individual's skills in working with Oracle databases. 1z0-071 exam is designed for individuals who work with databases and need to demonstrate their knowledge of SQL programming, database design, and data modeling concepts. Oracle Database SQL certification is recognized globally and is highly regarded in the IT industry.

Oracle Database SQL Sample Questions (Q346-Q351):

NEW QUESTION # 346
Evaluate the following two queries:

Which statement is true regarding the above two queries?

A. There would be no change in performance.
B. Performance would improve query 2 only if there are null values in the CUST__CREDIT__LIMIT column.
C. Performance would degrade in query 2.
D. Performance would improve in query 2.

Answer: A

NEW QUESTION # 347
View the exhibit and examine the description of the PRODUCT_INFORMATIONtable.

Which SQL statement would retrieve from the table the number of products having LIST_PRICEas NULL?
SELECT COUNT (DISTINCT list_price)

A. FROM product_information
WHERE list_price is NULL
B. FROM product_information
WHERE list_price is NULL
SELECT COUNT (list_price)
C. FROM product_information
WHERE list_price is NULL
SELECT COUNT (NVL(list_price, 0))
D. FROM product_information
WHERE list_price i= NULL
SELECT COUNT (list_price)

Answer: B

NEW QUESTION # 348
Examine the description of the EMPLOYEES table:

You write this failing statement:
SELECT dept_no AS department_id, MAX (salary) As max_sal
FROM employees
WHERE salary >10000
GROUP BY department_id
ORDER BY max_sal;
Which clause causes the error?

A. SELECT
B. GROUP BY
C. WHERE
D. ORDER BY

Answer: B

NEW QUESTION # 349
The SALES table has columns PROD_IDand QUANTITY_SOLDof data type NUMBER.
Which two queries execute successfully? (Choose two.)
SELECT prod_id FROM sales WHERE quantity_sold > 55000 GROUP BY prod_id HAVING

A. SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND COUNT(*) > 10 GROUP
B.
C. COUNT(*) > 10;
SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND COUNT(*) > 10 GROUP
D. BY prod_id HAVING COUNT(*) > 10;
SELECT COUNT(prod_id) FROM sales WHERE quantity_sold > 55000 GROUP BY prod_id;
E. BY COUNT(*) > 10;
SELECT COUNT(prod_id) FROM sales GROUP BY prod_id WHERE quantity_sold > 55000;

Answer: A,C

NEW QUESTION # 350
View the Exhibit and examine the structure of the PROMOTION table.

You have to generate a report that displays the promo named start data for all promos that started after that last promo in the 'INTTERNET' category.

A. SELECT promo-name, promo-being_date FROM promotion
WHERE promo-being-date IN (SELECT promo_biing_date
FROM promotions
WHERE promo_category='INTYERNET');
B. SELECT promo_neme, promo_being_date FROM promotions
WHERE promo_being_date > All (SELECT promo_beinjg-date
FROM promotions
WHERE promo_category ='INTERNET' );
C. SELECT promo-name, promo-being _date FROM promotions
Where promo_being_data >ALL (SELECT MAX (promo_being-date)
FROM promotions ) AND
Promo-category ='INTERNET';
D. Select promo_name, promo_being_date FROM promoptions
WHERE promo_being_data > ANY (SELCT promo_being-date
FROM promotions
WHERE promo_category = 'INTERNET'

Answer: B

NEW QUESTION # 351
......

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