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Oracle 1z0-071 Exam Syllabus Topics:

Section	Weight	Objectives
Managing Views		- Updatable and read-only views - Create, modify and drop views
Working with Time Zones and Date/Time Data		- Time zone conversion functions - TIMESTAMP, INTERVAL data types
Managing Indexes, Synonyms and Sequences		- Create and use synonyms - Create and maintain indexes - Create and use sequences
Using SET Operators		- Ordering results with set operations - UNION, UNION ALL, INTERSECT, MINUS operators
Retrieving Data Using SQL SELECT Statement	20%	- Column aliases, concatenation, literals and DISTINCT - SELECT statement syntax and usage - Arithmetic operations and NULL handling
Using Data Dictionary Views		- Retrieve metadata and object information
Controlling User Access		- System and object privileges - Roles, granting and revoking privileges
Displaying Data from Multiple Tables	15%	- Equijoins and non-equijoins - Cartesian products - Self-joins and outer joins
Restricting and Sorting Data	15%	- ORDER BY clause and sorting rules - WHERE clause and filtering conditions - Operator precedence - Substitution variables, DEFINE and VERIFY commands
Relational Database Concepts	10%	- Theoretical and physical aspects of relational databases - Relationship between database and SQL - ERD and SQL statement mapping
Aggregating Data Using Group Functions	10%	- Handling NULLs in group functions - SUM, AVG, COUNT, MAX, MIN functions - GROUP BY and HAVING clauses
Manipulating Data and Managing Transactions		- Transaction control: COMMIT, ROLLBACK, SAVEPOINT - Multi-table inserts - INSERT, UPDATE, DELETE, MERGE statements
Using Single-Row Functions to Customize Output	20%	- Nested functions usage - Character, number, and date functions
Managing Tables and Constraints		- Temporary and external tables - Constraints: primary key, foreign key, unique, check, not null - Data types, creating/altering/dropping tables
Conversion Functions and Conditional Expressions	10%	- Implicit and explicit data type conversion - NVL, NULLIF, COALESCE and CASE expressions - TO_CHAR, TO_NUMBER, TO_DATE functions
Using Subqueries to Solve Queries		- Single-row and multi-row subqueries - Correlated subqueries for update/delete

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Oracle Database SQL Sample Questions (Q356-Q361):

NEW QUESTION # 356
Which two statements are true regarding a SAVEPOINT? (Choose two.)

A. Only one SAVEPOINTmay be issued in a transaction
B. A SAVEPOINTdoes not issue a COMMIT
C. Rolling back to a SAVEPOINTcan undo a CREATE INDEX statement
D. Rolling back to a SAVEPOINT can undo a TRUNCATEstatement
E. Rolling back to a SAVEPOINTcan undo a DELETEstatement

Answer: B,E

NEW QUESTION # 357
Which three statements are true about multiple row subqueries? (Choose three.)

A. They can return multiple columns.
B. They can contain HAVING clauses.
C. Two or more values are always returned from the subquery.
D. They can contain GROUP BY clauses.
E. They cannot contain a subquery.

Answer: A,B,D

Explanation:
https://www.w3resource.com/sql/subqueries/multiplee-row-column-subqueries.php

NEW QUESTION # 358
Evaluate the following SQL statements that are issued in the given order: CREATE TABLE emp
(emp_no NUMBER(2) CONSTRAINT emp_emp_no_pk PRIMARY KEY,
enameVARCHAR2(15),
salary NUMBER(8,2),
mgr_no NUMBER(2) CONSTRAINT emp_mgr_fk REFERENCES emp);
ALTER TABLE emp
DISABLE CONSTRAINT emp_emp_no_pk CASCADE;
ALTER TABLE emp
ENABLE CONSTRAINT emp_emp_no_pk;
What would be the status of the foreign key EMP_MGR_FK?

A. It would be automatically enabled and deferred.
B. It would be automatically enabled and immediate.
C. It would remain disabled and can be enabled only by dropping the foreign key constraint and re-creating it.
D. It would remain disabled and has to be enabled manually using the ALTER TABLE command.

Answer: A,B,C

NEW QUESTION # 359
View the Exhibit and examine the structure of the PRODUCT_INFORMATIONand INVENTORIEStables.

You have a requirement from the supplies department to give a list containing PRODUCT_ID, SUPPLIER_ID, and QUANTITY_ON_HANDfor all the products wherein QUANTITY_ON_HANDis less than five.
Which two SQL statements can accomplish the task? (Choose two.)
SELECT i.product_id, i.quantity_on_hand, pi.supplier_id

A. FROM product_information pi JOIN inventories i
ON (pi.product_id=i.product_id)
WHERE quantity_on_hand < 5;
SELECT product_id, quantity_on_hand, supplier_id
B. FROM product_information
NATURAL JOIN inventories AND quantity_on_hand < 5;
SELECT i.product_id, i.quantity_on_hand, pi.supplier_id
C. FROM product_information pi JOIN inventories i
ON (pi.product_id=i.product_id) AND quantity_on_hand < 5;
SELECT i.product_id, i.quantity_on_hand, pi.supplier_id
D. FROM product_information pi JOIN inventories i
USING (product_id) AND quantity_on_hand < 5;

Answer: A,C

NEW QUESTION # 360
View the Exhibits and examine the structure of the COSTS and PROMOTIONS tables.
You want to display PROD IDS whose promotion cost is less than the highest cost PROD ID in a pro motion time interval.
Examine this SQL statement:
SELECT prod id
FROM costs
WHERE promo id IN
(SELECT promo id
FROM promotions
WHERE promo_cost < ALL
(SELECT MAX (promo cost)
FROM promotions
GROUP BY (promo_end date-promo_begin_date)) );
What will be the result?

A. It gives an error because the ALL keyword is not valid.
B. It executes successfully but does not give the required result.
C. It gives an error because the GROUP BY clause is not valid
D. It executes successfully and gives the required result.

Answer: D

Explanation:
This SQL query checks for product IDs (prod_id) from the costs table where the promotion ID (promo_id) is associated with promotions whose costs are less than the maximum promotional cost of all promotions, grouped by the duration of each promotion (calculated as promo_end_date - promo_begin_date). The query is correctly written to fulfill these conditions.
* The subquery SELECT MAX(promo_cost) FROM promotions GROUP BY (promo_end_date - promo_begin_date) computes the maximum cost of promotions grouped by their duration, returning the highest cost for each distinct promotion length.
* The WHERE promo_cost < ALL (...) clause then filters out the promotions where the promo_cost is less than all of the maximum costs returned by the subquery, ensuring that only promo_ids associated with costs less than the highest cost for any promotion length are considered.
* Since this logical structure correctly implements the given requirement, the statement executes successfully and yields the correct results.

NEW QUESTION # 361
......

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