2026 Itcertkr 최신 CEM PDF 버전 시험 문제집과 CEM 시험 문제 및 답변 무료 공유: https://drive.google.com/open?id=1UF2Hnq0p7B0sx9v5xUtXKkKJoq7_c0V-
Itcertkr의 완벽한 AEE인증 CEM덤프는 고객님이AEE인증 CEM시험을 패스하는 지름길입니다. 시간과 돈을 적게 들이는 반면 효과는 십점만점에 십점입니다. Itcertkr의 AEE인증 CEM덤프를 선택하시면 고객님께서 원하시는 시험점수를 받아 자격증을 쉽게 취득할수 있습니다.
| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Facilities Management | 8-12% | - Preventive maintenance programs - Commissioning and re-commissioning - Operations and maintenance best practices - Building automation systems (BAS) - Monitoring and targeting (M&T) |
| Topic 2: Energy Project Implementation | 8-12% | - Energy service companies (ESCOs) - Performance contracting (ESPC) - Implementation strategies - Measurement and verification (M&V) - Project risk management - Project financing models |
| Topic 3: Renewable Energy Technologies | 8-12% | - Solar photovoltaic systems - Energy storage technologies - Geothermal systems - Biomass and bioenergy - Wind energy systems - Solar thermal systems |
| Topic 4: Electric Power Systems | 10-15% | - Power distribution systems - Motors and drives - Harmonics and power quality - Power factor correction - Lighting systems and controls - Standby power systems |
| Topic 5: Heating, Ventilating, and Air Conditioning (HVAC) | 12-18% | - Indoor air quality - Equipment efficiency ratings - Load calculations - Controls and optimization - Psychrometrics - Heat transfer principles - HVAC system types and components |
| Topic 6: Building Envelope | 8-12% | - Insulation types and R-values - Windows and glazing systems - Daylighting and shading - Thermal envelope analysis - Air leakage and infiltration |
| Topic 7: Energy Auditing | 15-20% | - Audit report writing - Baseline establishment - Audit procedures and methodologies - Data collection and analysis - Metering and measurement equipment - Types of energy audits (preliminary, detailed, investment-grade) |
| Topic 8: Environmental and Regulatory Compliance | 5-10% | - EPA regulations (Clean Air Act, Clean Water Act) - Carbon footprint calculation - Green building standards (LEED, ENERGY STAR) - Sustainability reporting - Energy reporting requirements |
| Topic 9: Energy Accounting and Economics | 10-15% | - Energy price forecasting - Utility rate structures and tariffs - Energy cost accounting and allocation - Life cycle cost analysis (LCCA) - Financial analysis techniques (ROI, NPV, IRR) |
Itcertkr 의 엘리트는 다년간 IT업계에 종사한 노하우로 높은 적중율을 자랑하는 AEE CEM덤프를 연구제작하였습니다. 한국어 온라인서비스가 가능하기에 AEE CEM덤프에 관하여 궁금한 점이 있으신 분은 구매전 문의하시면 됩니다. AEE CEM덤프로 시험에서 좋은 성적 받고 자격증 취득하시길 바랍니다.
질문 # 135
Which of the advantages listed below, makes an ice TES system more preferred over a water TES system, when a load shifting strategy is considered?
정답:C
설명:
To determine which advantage makes an ice Thermal Energy Storage (TES) system more preferred over a water TES system for a load shifting strategy, we need to evaluate each option based on the principles of thermal energy storage as outlined in the Association of Energy Engineers (AEE) Certified EnergyManager (CEM) training materials. Load shifting involves storing energy (cooling capacity) during off-peak periods and releasing it during peak demand, making storage efficiency and capacity critical. Let's analyze each option step-by-step.
Step 1: Understand Ice TES vs. Water TES in Load Shifting
* Ice TES: Uses the latent heat of fusion of water (ice melting) to store cooling energy. Ice is formed during off-peak hours (e.g., overnight) and melted during peak hours to provide cooling.
* Water TES: Uses the sensible heat capacity of water, storing chilled water (typically 4-6°C) to provide cooling.
* Load Shifting Goal: Maximize cooling storage in minimal space and cost, shifting electrical demand from peak to off-peak periods.
* CEM Reference: CEM materials in the "Thermal Energy Storage" section highlight ice TES for its high energy density and compact storage, contrasted with water TES for simpler operation but larger volume requirements.
Step 2: Evaluate Each Option
Option A: Ice-storage systems operate with a higher coefficient of performance (COP)
* Analysis:
* COP Definition: COP = (Cooling Output) / (Energy Input). For TES, this relates to the chiller's efficiency.
* Ice TES: Requires chillers to operate at lower temperatures (e.g., -5°C to 0°C) to freeze water, which typically reduces chiller COP (e.g., 3-4) compared to water TES chillers operating at 4-6° C (COP ~5-6).
* Reality: Ice TES systems often have a lower COP due to the additional energy needed for phase change, though total system efficiency may improve with load shifting benefits.
* CEM Reference: CEM notes that ice TES energy input is higher per unit of cooling due to lower evaporating temperatures, contradicting a "higher COP" claim.
* Conclusion: This statement is incorrect and not an advantage for ice TES in load shifting.
Option B: Ice-storage systems require smaller storage tanks since ice has a higher energy storage density
* Analysis:
* Energy Storage Density:
* Ice TES: Relies on latent heat of fusion = 334 kJ/kg (80 kcal/kg or ~144 Btu/lb). This is the energy absorbed/released when water freezes/melts, far exceeding sensible heat.
* Water TES: Relies on sensible heat = cp##T c_p \cdot \Delta T cp##T, where cp=4.18 kJ
/kg\cdotp°C c_p = 4.18 \, \text{kJ/kg °C} cp=4.18kJ/kg\cdotp°C (1 Btu/lb °F). For a typical #T=10°C\Delta T = 10°C#T=10°C (e.g., 4°C to 14°C), energy stored = 4.18×10=41.
8 kJ/kg 4.18 \times 10 = 41.8 \, \text{kJ/kg} 4.18×10=41.8kJ/kg (~20 Btu/lb).
* Comparison: Ice stores ~8 times more energy per kg than water for a 10°C range (334 vs.
41.8 kJ/kg).
* Volume Impact: Ice's density (~917 kg/m³) is slightly less than water (~1000 kg/m³), but the latent heat advantage dominates, reducing required tank volume significantly.
* Load Shifting: Smaller tanks mean less space and potentially lower capital costs, a key advantage for peak load management.
* CEM Reference: CEM training emphasizes ice TES's high energy density as a primary reason for its preference in space-constrained load shifting applications.
* Conclusion: This statement is correct and a clear advantage for ice TES.
Option C: Water-storage systems require smaller storage tanks since water has a higher density than ice
* Analysis:
* Density: Water = 1000 kg/m³; Ice = 917 kg/m³. Water is denser, but density alone doesn't determine storage size in TES.
* Energy Storage: As calculated, water's sensible heat capacity (e.g., 41.8 kJ/kg for 10°C) is much lower than ice's latent heat (334 kJ/kg). To store the same cooling capacity, water TES requires
~8 times more mass and thus larger tanks (even accounting for density differences).
* Implication: Water TES tanks are larger, not smaller, contradicting the statement.
* CEM Reference: CEM materials note water TES's larger volume requirements as a disadvantage compared to ice TES.
* Conclusion: This statement is incorrect and not an advantage for ice TES (it favors water TES incorrectly).
Option D: Ice-storage systems require lower maintenance due to lower pumping volume
* Analysis:
* Pumping Volume: Ice TES often uses glycol or brine solutions to transfer heat at lower temperatures, requiring pumps sized for smaller volumes due to concentrated coolingcapacity.
Water TES circulates larger volumes of chilled water. However, "lower pumping volume" doesn' t directly translate to "lower maintenance."
* Maintenance: Ice TES systems are more complex (ice-making equipment, heat exchangers), potentially increasing maintenance (e.g., defrost cycles, corrosion from brine). Water TES is simpler, often with lower maintenance needs.
* CEM Reference: CEM discusses ice TES complexity as a trade-off for its density advantage, not a maintenance benefit.
* Conclusion: This statement is questionable and not a primary advantage for load shifting.
Step 3: Identify the Key Advantage for Load Shifting
* Load Shifting Context: The goal is to store maximum cooling capacity efficiently during off-peak hours. Option B (smaller tanks due to higher energy storage density) directly supports this by reducing space and installation costs, a critical factor in TES design per CEM guidelines.
* Elimination:
* A: Incorrect (lower COP, not higher).
* C: Incorrect (water TES tanks are larger).
* D: Weak (maintenance isn't clearly lower; not the primary driver).
* B: Correct and relevant.
질문 # 136
What type of passive heat exchanger can wrap around an evaporator coil to precool entering air and reheat the air after the cooling coil without adding more moisture to the supply air stream?
정답:E
질문 # 137
If the initial design process includes group relamping, how can this reduce the number of lamps required to illuminate a space?
정답:D
질문 # 138
In a chilled water thermal energy storage system, chilled water is stored at 4°C and used for supply water.
Chilled water return is 14°C. Calculate the storage capacity required to hold 50 GJ of thermal cooling. (The specific heat of water (C) is 4.2 kJ/kg-°C. Assume no system losses.)
정답:A
설명:
1) Define what is being asked (CEM context)
For a chilled-water thermal energy storage (TES) system, AEE CEM guidance states that storage capacity is determined from:
Where:
* = stored thermal energy
* = mass of water
* = specific heat of water
* = temperature difference between supply and return
This equation is explicitly used in CEM thermal energy storage sizing problems (AEE CEM Body of Knowledge - Cooling Systems & Thermal Storage).
2) Given data
* Required cooling storage:
* Chilled water supply temperature = 4°C
* Chilled water return temperature = 14°C
* Temperature difference:
* Specific heat of water:
* Density of water (CEM standard assumption):
3) Solve for required water mass
4) Convert mass to volume
Using water density:
질문 # 139
Calculate the monthly electric bill for a customer that used 400 kW and 75,000 kwh during one month. Use the following declining block structure for a monthly bill:
SELECT THE CORRECT ANSWER
정답:B
설명:
We need to calculate the monthly electric bill based on the given pricing structure.
Step 1: Identify Charges from the Table
* Customer charge:$50/month
* Peak demand charge:$10/kW-month
* Electric consumption charges:
* First25,000 kWh@$0.06/kWh
* Excess(75,000 - 25,000) = 50,000 kWh@$0.05/kWh
* Tax:20% of total
A screenshot of a calculator AI-generated content may be incorrect.
질문 # 140
......
AEE CEM인증시험은 현재IT업계에서 아주 인기 있는 시험입니다.많은 IT인사들이 관연 자격증을 취득하려고 노력하고 있습니다.AEE CEM인증시험에 대한 열기는 식지 않습니다.AEE CEM자격증은 여러분의 사회생활에 많은 도움이 될 것이며 연봉상승 등 생활보장에 업그레이드 될 것입니다.
CEM최신 업데이트 덤프문제: https://www.itcertkr.com/CEM_exam.html
그리고 Itcertkr CEM 시험 문제집의 전체 버전을 클라우드 저장소에서 다운로드할 수 있습니다: https://drive.google.com/open?id=1UF2Hnq0p7B0sx9v5xUtXKkKJoq7_c0V-