WGU Applied Algebra FXO2 PFXP C957 Exam Simulator - Applied-Algebra Free Demo & Applied-Algebra Training Pdf

If you are busy with your work or study and have little time to prepare for your exam, then our exam dumps will be your best choice. Applied-Algebra exam braindumps are high quality, you just need to spend about 48 to 72 hours on practicing, and you can pass the exam just one time. In addition, we are pass guarantee and money back guarantee for Applied-Algebra Exam Materials, if you fail to pass the exam, and we will give you full refund. We have online and offline service, and if you have any questions for Applied-Algebra training materials, you can consult us, and we will give you reply as soon as possible.

WGU Applied-Algebra Exam Syllabus Topics:

Section	Objectives
Topic 1: Linear Functions and Systems	- Systems of Equations 1. Elimination method 2. Substitution method - Linear Equations 1. Slope-intercept form 2. Point-slope form
Topic 2: Polynomial and Rational Expressions	- Rational Expressions 1. Restrictions on variables 2. Simplification - Polynomials 1. Factoring techniques 2. Operations with polynomials
Topic 3: Foundations of Algebra	- Algebraic Expressions 1. Simplifying expressions 2. Evaluating expressions 3. Order of operations - Equations and Inequalities 1. Linear equations in one variable 2. Inequalities and interval notation
Topic 4: Exponential and Logarithmic Concepts	- Exponential Functions 1. Exponential equations 2. Growth and decay models - Logarithmic Basics 1. Conversion between exponential and logarithmic form 2. Logarithm properties
Topic 5: Functions and Graphs	- Graphing Functions 1. Transformations of graphs 2. Coordinate plane interpretation - Function Concepts 1. Domain and range 2. Function notation

>> Applied-Algebra Examcollection Questions Answers <<

High-quality Applied-Algebra Examcollection Questions Answers - Find Shortcut to Pass Applied-Algebra Exam

While making revisions and modifications to the WGU Applied-Algebra practice exam, our team takes reports from over 90,000 professionals worldwide to make the WGU Applied-Algebra Exam Questions foolproof. To make you capable of preparing for the Applied-Algebra exam smoothly, we provide actual WGU Applied-Algebra exam dumps.

WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q107-Q112):

NEW QUESTION # 107
A coach is placing an order for team shirts. The graph shows the total cost based on the number of shirts.
What is the cost of each additional shirt?
Exhibit:

A. $49.00
B. $3.90
C. $10.00
D. $13.90

Answer: C

Explanation:
This question asks for the cost of each additional shirt, which is the slope of the linear graph. The slope tells how much the total cost increases for each increase of 1 shirt. From the exhibit, the graph shows a starting cost near $39 and a point near (10, 139). The increase in cost from 0 shirts to 10 shirts is 139#39=100 dollars.
Dividing by 10 shirts gives a rate of 10 dollars per shirt. The fixed starting cost is not the cost of a shirt; it is the initial fee or setup cost. Since the graph rises by $10 for each additional shirt, the cost per additional shirt is $10.00. Therefore, the answer is B.

NEW QUESTION # 108
A person makes down quilts to sell.

The graph shows the functions that model the cost and revenue.
How many down quilts need to sell to break even/start making a profit?

A. 0
B. 1
C. 2
D. 3

Answer: A

Explanation:
This question asks us to interpret a graph showing cost and revenue.
In Applied Algebra, the break-even point is where:
" Revenue " = " Cost "
On a graph, this happens where the revenue line and the cost line intersect.
From the graph:
The solid blue line represents revenue.
The dashed blue line represents cost.
The break-even point occurs where these two lines cross.
Looking carefully at the graph, the two lines intersect at approximately:
x=6
The horizontal axis represents the number of units, meaning the number of down quilts sold.
So the person needs to sell about:
6 " quilts "
to break even.
After selling more than 6 quilts, the revenue line is above the cost line, meaning the person begins making a profit.

NEW QUESTION # 109
A new company just launched and is using the function M(t)to predict its market share after tyears. The graph of M(t)is shown.

When should the company expect to have a market share of 60%?

A. After 6 years
B. After 6.6 years
C. After 5 years
D. After 2 years

Answer: B

Explanation:
The function M(t)represents the company's predicted market share after tyears.
The horizontal axis represents:
t= " time in years "
The vertical axis represents:
M(t)= " market share percentage "
We need to find when the company's market share reaches:
60%
To answer this from the graph:
Locate 60on the vertical axis.
Move horizontally until reaching the blue curve.
Move downward to the horizontal axis to read the corresponding time.
From the graph, the blue curve reaches 60%a little after 6years, approximately at:
t=6.6
So the company should expect to have a market share of 60%after about:
6.6 " years "

NEW QUESTION # 110
The graph shows the number of customers, C(t), showing up to a store, where the number of hours since opening is along the horizontal axis and the number of customers showing up to the store each hour is along the vertical axis.

How can the concavity be described from t=6.2to t=10.1?

A. The number of customers increases slower and slower and then increases faster and faster.
B. The number of customers increases faster and faster and then increases slower and slower.
C. The number of customers decreases slower and slower and then increases faster and faster.
D. The number of customers increases slower and slower and then decreases faster and faster.

Answer: D

Explanation:
From t=6.2to about t=8.5, the graph is increasing, but it is becoming less steep as it approaches a local maximum.
That means the number of customers is:
" increasing slower and slower "
After the local maximum, from about t=8.5to t=10.1, the graph begins to decrease and becomes steeper downward.
That means the number of customers is:
" decreasing faster and faster "
So the full description is:
" The number of customers increases slower and slower and then decreases faster and faster. " Therefore, the correct answer is:
# ( " D " )

NEW QUESTION # 111
An investment account accrues interest every year, and the value of the account is given by G(x). The graph of this function is shown.

What represents the value of the account after 4 years?

A. $711.28
B. $584.62
C. $1,052.87
D. $480.52

Answer: C

Explanation:
The graph represents the value of an investment account over time. The horizontal axis gives time in years, and the vertical axis gives the total account value in dollars. To find the value after 4 years, locate x=4 on the horizontal axis and read the corresponding G(x)-value on the graph. The plotted exponential growth curve is slightly above $1,000 at 4 years, closest to $1,052.87. Because the graph shows an increasing exponential trend, values such as $480.52, $584.62, and $711.28 are too low for the account value at x=4. The correct interpretation is that after 4 years, the investment account is worth approximately $1,052.87. Therefore, the correct answer is D.

NEW QUESTION # 112
......

We have always taken care to provide our customers with the very best. So we provide numerous benefits along with our WGU WGU Applied Algebra FXO2 PFXP C957 exam study material. We provide our customers with the demo version of the WGU Applied-Algebra Exam Questions to eradicate any doubts that may be in your mind regarding the validity and accuracy. You can test the product before you buy it.

Applied-Algebra Test Pdf: https://www.testkingit.com/WGU/latest-Applied-Algebra-exam-dumps.html