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| Section | Objectives |
|---|---|
| Topic 1: Regression and Correlation | - Relationship analysis
|
| Topic 2: Probability Distributions | - Continuous distributions
|
| Topic 3: Statistical Inference | - Hypothesis testing
|
| Topic 4: Descriptive Statistics | - Data summarization
|
| Topic 5: Probability | - Probability rules
|
>> Applied-Probability-and-Statistics復習テキスト <<
Xhs1991は長い歴史を持っているWGUのApplied-Probability-and-Statisticsトレーニング資料が提供されるサイトです。IT領域で長い時間に存在していますから、現在のよく知られていて、知名度が高い状況になりました。これは受験生の皆様を助けた結果です。Xhs1991が提供したWGUのApplied-Probability-and-Statisticsトレーニング資料は問題と解答に含まれていて、IT技術専門家たちによって開発されたものです。WGUのApplied-Probability-and-Statistics認定試験を受けたいのなら、Xhs1991を選ぶのは疑いないことです。
質問 # 86
There are 12 cell phone charging cords available at a store for purchase. The length of each charging cord in inches is reflected as 3, 3, 4, 6, 6, 6, 6, 7, 10, 10, 11, and 12, respectively.
What are the mean of these data?
正解：C
解説：
The mean is the arithmetic average of a data set. To find it, add all values and divide by the number of values.
The cord lengths are 3, 3, 4, 6, 6, 6, 6, 7, 10, 10, 11, and 12. Their sum is 84. Since there are 12 charging cords, divide 84 by 12 to obtain 7. Therefore, the mean cord length is 7 inches. This value represents the balance point of the distribution, not necessarily a value that must occur most often. In this data set, 6 appears most frequently, so 6 is the mode, but the question asks for the mean. Option B, 8, and option C, 9, are too large because several values are below 7. Option D, 6, identifies the most common value rather than the average. References/topics from the Study Guide: mean, measures of center, quantitative data, arithmetic average.
質問 # 87
A standard deck of 52 playing cards, 13 with hearts, 13 with diamonds, 13 with clovers, and 13 with spades, is shuffled, and one card is drawn at random.
What is the probability of drawing a heart?
正解：A
解説：
The probability of a simple event is calculated by dividing the number of favorable outcomes by the total number of equally likely outcomes. A standard deck contains 52 cards. The favorable outcomes are the hearts, and the question states that there are 13 hearts in the deck. Therefore, the probability of drawing a heart is 13
/52. This fraction simplifies by dividing both numerator and denominator by 13, giving 1/4. Option A, 1/13, would incorrectly treat one card as favorable out of 13 rather than 13 favorable hearts out of 52 total cards.
Option B, 1/2, would imply that half the deck consists of hearts, which is false. Option D, 1/3, does not correspond to the four equally sized suits in a standard deck. Since the four suits are equally represented, each suit has probability one out of four. References/topics from the Study Guide: theoretical probability, equally likely outcomes, fractions, sample spaces.
質問 # 88
A road safety research group wants to enhance road safety by analyzing the stopping distance of a car at different speeds. The group has recorded their data in the following scatterplot.
What is true about the outlier in the scatterplot?
正解：B
解説：
An outlier is a data point that does not follow the general pattern of the remaining data. In this scatterplot, most points show a clear increasing relationship: as speed increases, stopping distance also increases. The main cluster follows a smooth upward trend, with stopping distances gradually rising as speed increases. One point, however, is far above the rest of the pattern. That point is located at approximately 40 mph and 560 feet, making it unusually high compared with the expected stopping distance at that speed. This is why option D correctly identifies the outlier. Option A describes a low-speed point that fits the lower end of the trend.
Option B describes a high-speed point near the upper end of the general pattern, not an unusual deviation.
Option C describes a point around 30 mph and 190 feet, which lies within the main cluster of observations.
The outlier is not merely an extreme x-value or y-value; it is unusual relative to the trend. References/topics from the Study Guide: scatterplots, outliers, bivariate data, association patterns.
質問 # 89
Dataset: 3, 6, 9. Median?
正解：D
解説：
The median is the middle value of a data set after the values are placed in ascending order. The dataset is 3, 6,
9, which is already ordered from least to greatest. Since there are three observations, the median is the second value, because one value lies below it and one value lies above it. Therefore, the median is 6. The median is a measure of center and is especially useful when data may be skewed or contain outliers because it depends on position rather than the magnitude of every value. The mean for this dataset is also 6, since (3 + 6 + 9) ÷ 3 =
6, but the question specifically asks for the median. Options B and C are not values in the dataset, and option D is the minimum value, not the middle. Study Guide references/topics: median, ordered data, measures of central tendency, descriptive statistics.
質問 # 90
Probability of drawing red or black card = ?
正解：A
解説：
In a standard deck of playing cards, every card is either red or black. Red cards consist of hearts and diamonds, and black cards consist of clubs and spades. There are 26 red cards and 26 black cards, for a total of 52 cards. The event "red or black" includes all possible cards in the deck. Therefore, the probability is 52 favorable outcomes out of 52 total outcomes, which equals 1. A probability of 1 means the event is certain.
Option B, 1/2, would be the probability of drawing a red card alone or a black card alone, not red or black.
Option C would mean the event is impossible, which is false. Option D would correspond to one suit out of four, such as hearts only. The word "or" combines both color categories, covering the entire sample space.
Study Guide references/topics: sample space, certainty, addition rule, card probability.
質問 # 91
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