JS-Dev-101 Fragen Und Antworten, JS-Dev-101 Online Prüfungen

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Salesforce JS-Dev-101 Prüfungsplan:
| Thema | Einzelheiten |
|---|
| Thema 1 | - Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
|
| Thema 2 | - Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
|
| Thema 3 | - Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
|
| Thema 4 | - Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
- falsy evaluations.
|
| Thema 5 | - Browser and Events: Covers DOM manipulation, event handling and propagation, browser-specific APIs, and using Browser Developer Tools to inspect code behavior.
|
>> JS-Dev-101 Fragen Und Antworten <<
JS-Dev-101 Online Prüfungen & JS-Dev-101 Tests
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Salesforce Certified JavaScript Developer - Multiple Choice JS-Dev-101 Prüfungsfragen mit Lösungen (Q88-Q93):
88. Frage
Correct implementation of try...catch for countsDeep():
- A. try {
countsDeep();
} handleError (e){
catch(e);
} - B. setTimeout(function() {
try {
countsDeep();
} catch (e) {
handleError(e);
}
}, 1000); - C. try {
setTimeout(function() {
countsDeep();
}, 1000);
} catch (e) {
handleError(e);
} - D. try {
setTimeout(function() {
countsDeep();
}, 1000);
} catch (e) {
handleError(e);
}
Antwort: B
Begründung:
The correct answer is B because countsDeep() is executed inside the callback function passed to setTimeout(), and the try...catch block is also placed inside that same callback.
In JavaScript, setTimeout() schedules a function to run later. The outer code finishes first, and the callback runs asynchronously after the delay. Because of this, a try...catch block placed outside setTimeout() cannot catch errors thrown later inside the callback.
Correct logic:
setTimeout(function() {
try {
countsDeep();
} catch (e) {
handleError(e);
}
}, 1000);
Here, when countsDeep() runs after 1000 milliseconds, any error thrown by countsDeep() happens inside the try block. Therefore, the catch (e) block can catch that error and pass it to handleError(e).
Why the other options are incorrect:
A is incorrect because the syntax is invalid JavaScript. A valid try...catch structure must be:
try {
// code
} catch (e) {
// handle error
}
Option A incorrectly writes:
} handleError (e){
catch(e);
}
That is not valid try...catch syntax.
C is incorrect because the try...catch surrounds only the call to setTimeout(), not the later execution of countsDeep(). If countsDeep() throws an error after the timer expires, the outer catch block will not catch it.
D is incorrect for the same reason as C. In the original question, D also had a typing error: it used countSheep() instead of countsDeep(). Even after correcting that typing error, D is still incorrect because the try...catch is outside the asynchronous callback.
89. Frage
Refer to the following code:

Which statement should be added to line 09 for the code to display. The boat has a capacity of 10 people?
- A. super.size = size;
- B. this.size = size;
- C. ship.size size;
- D. super (size);
Antwort: B
90. Frage
Given HTML below:
<div>
<div id ="row-uc"> UniversalContainer</div>
<div id ="row-aa">Applied Shipping</div>
<div id ="row-bt"> Burlington Textiles </div>
</div>
Which statement adds the priority = account CSS class to the universal Containers row ?
- A. Document .querySelector('#row-uc').classes.push('priority-account');
- B. Document .queryElementById('row-uc').addclass('priority-account');
- C. Document .querySelector('#row-uc').classList.add('priority-account');
- D. Document .querySelectorALL('#row-uc').classList.add('priority-account');
Antwort: B
91. Frage
Given the JavaScript below:
function onLoad() {
console.log("Page has loaded!");
}
Where can the developer see the log statement after loading the page in the browser?
- A. In the browser performance tools log
- B. On the terminal console running the web server
- C. On the webpage console log
- D. On the browser JavaScript console
Antwort: D
Begründung:
console.log() in browser-side JavaScript writes output to the browser's JavaScript console, which is available in the browser's Developer Tools.
In a typical browser (Chrome, Firefox, Edge, etc.), you open DevTools and go to the Console tab.
Any console.log("Page has loaded!"); executed in page JavaScript will appear there.
Why A is correct:
The function onLoad is a client-side function (runs in the browser).
When it executes, the console.log call goes to the browser's JavaScript console, not the server.
Why the others are incorrect:
B . On the terminal console running the web server
That console shows logs from the server-side runtime (e.g., Node.js logs).
This code is clearly browser-side JavaScript (no Node.js or server context shown).
Therefore, the output does not appear in the terminal.
C . In the browser performance tools log
Performance tools (Timeline, Performance tab, etc.) show metrics about rendering, CPU time, network, etc., not generic console.log messages.
console.log messages appear in the Console tab, not in performance logs.
D . On the webpage console log
There is no built-in concept of a "webpage console log" UI rendered on the page itself by default.
Unless you explicitly code something to display logs in the DOM, console.log output is not visible on the page, only in Developer Tools.
Therefore, the correct place to see that log is:
Answe r: A
JavaScript knowledge / Study Guide references (concept names only, no links):
Browser Developer Tools - Console tab
console.log() in client-side JavaScript
Difference between client-side logs and server-side logs
92. Frage
A developer has two ways to write a function:
Option A:
01 function Monster() {
02 this.growl = () => {
03 console.log("Grr!");
04 }
05 }
Option B:
01 function Monster() {};
02 Monster.prototype.growl = () => {
03 console.log("Grr!");
04 }
After deciding on an option, the developer creates 1000 monster objects. How many growl methods are created with Option A and Option B?
- A. 1000 growl methods are created for Option A. 1 growl method is created for Option B.
- B. 1 growl method is created regardless of which option is used.
- C. 1000 growl methods are created regardless of which option is used.
- D. 1 growl method is created for Option A. 1000 growl methods are created for Option B.
Antwort: A
Begründung:
Option A:
this.growl = () => { ... } inside the constructor creates a new function per instance.
For 1000 new Monster(), you get 1000 distinct growl functions, each stored on the instance itself.
Option B:
Monster.prototype.growl = () => { ... } attaches growl to the prototype.
All instances share the same single growl function via the prototype chain.
For 1000 instances, only 1 growl method exists in memory.
So: Option A → 1000; Option B → 1.
93. Frage
......
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