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WGU Applied-Algebra Exam Syllabus Topics:

SectionObjectives
Topic 1: Validity of Models- Determine validity
- Examine utility
- Determine fit
Topic 2: Functions and Algebra of Functions- Derive conclusions based on notation
- Derive conclusions based on data
- Derive conclusions based on graphs
Topic 3: Polynomial Functions- Interpret rates of change for polynomial functions
- Interpret inputs and outputs for polynomial functions
- Interpret concavity for polynomial functions
Topic 4: Graphical Depictions- Interpret maximum and minimum for situations
- Interpret concavity for situations
- Interpret inputs and outputs for situations
- Interpret rates of change for situations
- Interpret asymptotes for situations
Topic 5: Exponential Functions- Interpret concavity for exponential functions
- Interpret rates of change for exponential functions
- Interpret inputs and outputs for exponential functions
Topic 6: Linear Functions- Interpret inputs and outputs of linear functions
- Interpret rates of change for linear functions
Topic 7: Logistic Functions- Interpret rates of change for logistic functions
- Interpret inputs and outputs for logistic functions
- Interpret asymptotes for logistic functions

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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q109-Q114):

NEW QUESTION # 109
The graph shows the number of trees sold by a nursery, where the number of days since the beginning of the month is along the horizontal axis and the number of trees sold per day is along the vertical axis. The greatest number of trees are sold when the temperature is over 70°F.

When was the temperature likely over 70°F?

Answer: A

Explanation:
The problem states that the greatest number of trees are sold when the temperature is over 70°F. Therefore, we need to identify the days on the graph when tree sales are highest. The graph shows two major peaks in the number of trees sold per day. These peaks occur around day 2 and day 10. Since higher tree sales are linked to temperatures over 70°F, those two days are the most likely days when the temperature exceeded 70°F. Day 6 appears near a low point, so it is not likely associated with high temperature based on the given relationship.
Day 12 also does not match the main peaks. Therefore, the correct answer is C.


NEW QUESTION # 110
The graph shows the estimated wait time, in minutes, based on the number of hours after 7:00 a.m.
What is the average rate of change of the wait time from point Ato point B?

Answer: C

Explanation:
The average rate of change tells us how much the output changes, on average, for each 1-unit increase in the input.
Here:
x= " hours after 7:00 a.m. "
and
y= " estimated wait time in minutes "
From the graph, point Ais approximately:
A=(5,88.3)
and point Bis approximately:
B=(9,65)
Now use the average rate of change formula:
" Average rate of change " =(y_2-y_1)/(x_2-x_1 )
Substitute the values:
(65-88.3)/(9-5)
=(-23.3)/4
=-5.825
Rounded to two decimal places:
-5.83
The negative sign means the estimated wait time is decreasing from point Ato point B.
So the average rate of change is approximately:
-5.83 " minutes per hour "


NEW QUESTION # 111
A team was assembled at a manufacturing plant in order to boost productivity. The team was tasked with producing as many widgets each day as possible. The results are shown in the graph.

What is the correct interpretation of the average rate of change from day 6 to day 14?

Answer: C

Explanation:
The graph models the number of widgets the team can produce each day.
The horizontal axis represents:
" days "
The vertical axis represents:
" widgets "
The graph gives two labeled points:
(6#3.4)
and
(14#23)
The average rate of change is:
" change in widgets " / " change in days "
Substitute the values:
(23-3.4)/(14-6)
=19.6/8
=2.45
Rounded to the nearest tenth:
2.5
This means the team increased production by an average of approximately:
2.5 " widgets each day "
Therefore, the correct answer is:
# ( " B " )


NEW QUESTION # 112
The graph shows the number of people watching a live video. The number of minutes since the video began is on the horizontal axis, and the number of viewers is on the vertical axis. When were there 432 viewers?
Exhibit:

Answer: B

Explanation:
This problem requires reading a value from a graph. The horizontal axis gives time in minutes, and the vertical axis gives the number of viewers. To solve it, find 432 on the vertical axis, locate where the graph reaches that value, and then move down to the horizontal axis. From the exhibit, the graph reaches 432 viewers at minute 1. That means the ordered pair is approximately (1, 432), so the input is 1 minute and the output is 432 viewers. The other listed minutes correspond to different viewer counts on the graph. In graphical depictions, matching the correct input-output pair is the key step. Therefore, the correct answer is B.


NEW QUESTION # 113
The graph shows the daily practice duration for a musician, where the number of days since the beginning of the month is along the horizontal axis and the number of minutes practiced per day is along the vertical axis.

Based on the graph, what was the practice duration for day 8?

Answer: A

Explanation:
This question asks us to interpret a value from a graph.
The horizontal axis represents:
Days
The vertical axis represents:
Practice duration in minutes
We need to find the practice duration on day 8.
To do this:
Locate 8 on the horizontal axis.
Move vertically until you reach the blue graph.
Read the corresponding value on the vertical axis.
From the graph, when:
x=8
the blue graph is at:
y=115
So the musician practiced for:
115 minutes


NEW QUESTION # 114
......

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