2026 Professional 1z1-071: Valid Oracle Database SQL Exam Prep

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Oracle Database SQL Sample Questions (Q298-Q303):

NEW QUESTION # 298
Examine the structure of the EMPLOYEES table.

You must display the maximum and minimum salaries of employees hired 1 year ago.
Which two statements would provide the correct output? (Choose two.)

A. SELECT minsal, maxsalFROM (SELECT MIN(salary) minsal, MAX(salary) maxsalFROM employeesWHERE hire_date < SYSDATE-365)GROUP BY maxsal, minsal;
B. SELECT MIN(Salary) minsal, MAX(salary) maxsalFROM employeesWHERE hire_date < SYSDATE-365GROUP BY MIN(salary), MAX(salary);
C. SELECT minsal, maxsalFROM (SELECT MIN(salary) minsal, MAX(salary) maxsalFROM employeesWHERE hire_date < SYSDATE-365GROUP BY MIN(salary), MAX(salary));
D. SELECT MIN(Salary), MAX(salary)FROM (SELECT salary FROMemployeesWHERE hire_date < SYSDATE-365);

Answer: A,D

NEW QUESTION # 299
View the Exhibit and examine the details of the PRODUCT_INFORMATION table. (Choose two.)

Evaluate this SQL statement:
SELECT TO_CHAR(list_price,'$9,999')
From product_information;
Which two statements are true regarding the output? (Choose two.)

A. A row whose LIST_PRICE column contains value 1123.90 would be displayed as $1,124.
B. A row whose LIST_PRICE column contains value 11235.90 would be displayed as $1,123.
C. A row whose LIST_PRICE column contains value 11235.90 would be displayed as #######.
D. A row whose LIST_PRICE column contains value 1123.90 would be displayed as $1,123.

Answer: A,C

NEW QUESTION # 300
Examine this Statement which returns the name of each employee and their manager,
SELECT e.last name AS emp,,m.last_name AS mgr
FROM employees e JOIN managers m
ON e.manager_ id = m. employee_ id ORDER BY emp;
You want to extend the query to include employees with no manager. What must you add before JOIN to do this?

A. CROSS
B. RIGHT OUTER
C. FULL OUTER
D. LEFT OUTER

Answer: D

NEW QUESTION # 301
Examine the description of the countries table:

Examine the description of the departments table:

Examine the description of the locations table:

Which two queries will return a list of countries with no departments?

Answer: B,C

Explanation:
The query's goal is to return a list of countries that have no departments linked to them.
Option B and Option D are the correct answers because they use set operations that will effectively return countries that do not have a corresponding entry in the departments table:
* Option B uses the NOT IN subquery to exclude countries that have departments linked to them. It looks for country_id values in the countries table that are not present in the list of country_id values associated with locations that are, in turn, associated with departments. This will correctly return countries that have no departments.
* Option D uses the MINUS set operator, which subtracts the results of the second SELECT statement from the results of the first. This statement will return all countries from the countries table minus those that have an associated department_id in the departments table, effectively listing countries with no departments.
Option A and Option C are incorrect because:
* Option A will not execute successfully as it tries to join tables using a column (country_id) that doesn't exist in the departments table, which will lead to an error.
* Option C's use of INTERSECT is incorrect for this requirement. INTERSECT returns only the rows that exist in both queries. Since we want countries with no departments, using INTERSECT would actually return the opposite of what is required.
References:
* Oracle Documentation on NOT IN clause: SQL Language Reference - Subquery
* Oracle Documentation on MINUS operator: SQL Language Reference - Set Operators Therefore, the correct options are B and D, which use subquery exclusion and the MINUS set operator, respectively, to accurately identify and return countries without departments.

NEW QUESTION # 302
The customers table has the following structure:
You need to write a query that does the following tasks:
1. Display the first name and tax amount of the customers. Tax is 5% of their credit limit.
2. Only those customers whose income level has a value should be considered.
3. Customers whose tax amount is null should not be considered.
Which statement accomplishes all the required tasks?

A. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNT
FROM customers
WHERE cust_income_level <> NULL AND
tax_amount <> NULL;
B. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNT
FROM customers
WHERE (cust_income_level, tax_amount) IS NOT NULL;
C. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNT
FROM customers
WHERE cust_income_level IS NOT NULL AND
cust_credit_limit IS NOT NULL;
D. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNT
FROM customers
WHERE cust_income_level IS NOT NULL AND
tax_amount IS NOT NULL;

Answer: C

NEW QUESTION # 303
......

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