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| Section | Weight | Objectives |
|---|---|---|
| Restricting and Sorting Data | 15% | - Substitution variables, DEFINE and VERIFY commands - Operator precedence - WHERE clause and filtering conditions - ORDER BY clause and sorting rules |
| Using Single-Row Functions to Customize Output | 20% | - Character, number, and date functions - Nested functions usage |
| Using SET Operators | - Ordering results with set operations - UNION, UNION ALL, INTERSECT, MINUS operators | |
| Relational Database Concepts | 10% | - Relationship between database and SQL - ERD and SQL statement mapping - Theoretical and physical aspects of relational databases |
| Managing Views | - Updatable and read-only views - Create, modify and drop views | |
| Retrieving Data Using SQL SELECT Statement | 20% | - Arithmetic operations and NULL handling - SELECT statement syntax and usage - Column aliases, concatenation, literals and DISTINCT |
| Manipulating Data and Managing Transactions | - INSERT, UPDATE, DELETE, MERGE statements - Transaction control: COMMIT, ROLLBACK, SAVEPOINT - Multi-table inserts | |
| Managing Indexes, Synonyms and Sequences | - Create and use synonyms - Create and maintain indexes - Create and use sequences | |
| Managing Tables and Constraints | - Temporary and external tables - Constraints: primary key, foreign key, unique, check, not null - Data types, creating/altering/dropping tables | |
| Working with Time Zones and Date/Time Data | - Time zone conversion functions - TIMESTAMP, INTERVAL data types | |
| Conversion Functions and Conditional Expressions | 10% | - TO_CHAR, TO_NUMBER, TO_DATE functions - NVL, NULLIF, COALESCE and CASE expressions - Implicit and explicit data type conversion |
| Controlling User Access | - Roles, granting and revoking privileges - System and object privileges | |
| Displaying Data from Multiple Tables | 15% | - Equijoins and non-equijoins - Cartesian products - Self-joins and outer joins |
| Aggregating Data Using Group Functions | 10% | - Handling NULLs in group functions - SUM, AVG, COUNT, MAX, MIN functions - GROUP BY and HAVING clauses |
| Using Subqueries to Solve Queries | - Single-row and multi-row subqueries - Correlated subqueries for update/delete | |
| Using Data Dictionary Views | - Retrieve metadata and object information |
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NEW QUESTION # 366
Examine this partial statement:
SELECT ename, sal,comm FROM emp
Now examine this output:
WHICH ORDER BY clause will generate the displayed output?
Answer: D
Explanation:
The ORDER BY clause is used in a SELECT statement to sort the returned rows by one or more columns.
A). This clause would attempt to order by ename as if it were a numeric column, which is not correct since ename is not numeric.
B). This is the correct answer. The NVL function replaces nulls with the specified value, in this case, 0. This clause sorts by comm, with nulls considered as 0 and appearing first, followed by the actual values, and then sorts by ename.
C). This clause is incorrect because it would place null values at the end, but in the output, rows with null comm appear at the beginning.
D). This clause would sort the comm in descending order with the nulls at the end, which is not consistent with the output shown.
References:
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "ORDER BY Clause"
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "NVL Function" Please note that the correct formatting of SQL statements and clauses is crucial for the successful execution of queries.
NEW QUESTION # 367
View the exhibit and examine the structure of ORDERSand CUSTOMERStables.
Which INSERT statement should be used to add a row into the ORDERStable for the customer whose CUST_LAST_NAMEis Robertsand CREDIT_LIMITis 600? Assume there exists only one row with CUST_LAST_NAME as Roberts and CREDIT_LIMIT as 600.
Answer: B
NEW QUESTION # 368
View the Exhibit and examine the structure of the CUSTOMERS table.
Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
Answer: C
NEW QUESTION # 369
View the exhibit and examine the data in the PROJ_TASK_DETAILS table.
The PROJ_TASK_DETAILS table stores information about project tasks and the relation between them.
The BASED_ON column indicates dependencies between tasks.
Some tasks do not depend on the completion of other tasks.
You must generate a report listing all task IDs, the task ID of any task upon which it depends and the name of the employee in charge of the task upon which it depends.
Which query would give the required result? (Choose the best answer.)
Answer: C
NEW QUESTION # 370
Evaluate the following CREATE TABLE commands:
CREATE_TABLE orders
(ord_no NUMBER (2) CONSTRAINT ord_pk PRIMARY KEY,
ord_date DATE,
cust_id NUMBER (4) );
CREATE TABLE ord_items
(ord _no NUMBER (2),
item_no NUMBER(3),
qty NUMBER (3) CHECK (qty BETWEEEN 100 AND 200),
expiry_date date CHECK (expiry_date> SYSDATE),
CONSTRAINT it_pk PRIMARY KEY (ord_no, item_no),
CONSTARAINT ord_fk FOREIGN KEY (ord_no) REFERENCES orders (ord_no) );
The above command fails when executed. What could be the reason?
Answer: B
NEW QUESTION # 371
......
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