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| Section | Objectives |
|---|---|
| Test Tools and Test Automation Support | - Tool support for test analysis and execution
|
| Testing Process in the Test Analyst Role | - Test analysis and design
|
| Testing Techniques for Test Analysis | - Specification-based techniques
|
| Reviews and Defect Management | - Static testing and review process
|
| Testing of Software Quality Characteristics | - Functional suitability testing
|
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NEW QUESTION # 23
You are testing the functional correctness of an application which allows the driver of a car to control if the air that enters the passenger compartment is fresh or recycled. The car may be ordered in various configurations:
* Engine Size, can be: 1500cc, 1900cc, 2200cc, 2500cc
* Gearbox type, can be: automatic, manual 5-speed, manual 6-speed
* Cruise control, can be: yes or no
* Electric sunroof, can be: yes or no
It is expected that the most popular configuration will have a 1900cc engine and a manual 5-speed gearbox with cruise control and no electric sunroof. In order to achieve full BASE CHOICE coverage, how many configurations must be tested?
Answer: B
Explanation:
The correct answer is D . CTAL-TA v4.0 defines base choice coverage as a combinatorial coverage criterion where a base value is selected for each parameter, forming one base coverage item. Then, additional coverage items are created by replacing one base value at a time with each non-base value while all other parameters remain at their base values.
The base configuration is explicitly given: 1900cc engine , manual 5-speed gearbox , cruise control = yes , and electric sunroof = no . That gives the first test configuration. Then each non-base value must be tested once while the other values remain fixed at the base configuration. Engine Size has four values, so there are 3 non-base engine values: 1500cc, 2200cc, and 2500cc. Gearbox type has three values, so there are 2 non-base gearbox values: automatic and manual 6-speed. Cruise control has one non-base value: no. Electric sunroof has one non-base value: yes.
Total configurations = 1 base + 3 + 2 + 1 + 1 = 8 . Option A , 48, is exhaustive testing: 4 × 3 × 2 × 2. Options B and C do not match the base choice formula. Reference: CTAL-TA v4.0, Section 3.1.2 Combinatorial Testing .
NEW QUESTION # 24
The following decision table shows the rules for sending a package. Same day delivery will not be provided for big packages. All combinations of same day delivery and international destination have been removed as they are infeasible.
How many columns will the table have after all possible minimization has been performed?
Answer: B
Explanation:
The correct answer is C because the fully minimized decision table has 8 columns . CTAL-TA v4.0 states that decision-table minimization derives an equivalent table with fewer rules by merging action-equivalent rules using the don't-care operator "-"; action-equivalent rules that differ in only one condition and cover all possible values of that condition may be merged. It also recommends disregarding or removing infeasible rules before merging.
For Small packages, columns 1 and 3 are action-equivalent: both charge 0% , provide insurance, and deliver same day. They differ only in High value , so they merge into one rule. Columns 2 and 4 cannot merge with them because same-day delivery and/or insurance differ. Therefore Small reduces from 4 rules to 3 . For Average packages, the same structure applies: columns 5 and 7 merge, while 6 and 8 remain separate.
Average also reduces from 4 rules to 3 . For Big packages, same-day is N/A , so columns 9 and 10 are action- equivalent and merge; columns 11 and 12 also merge. Big reduces from 4 rules to 2 .
Total minimized columns = 3 + 3 + 2 = 8 . Option A misses the valid merges for same-day insured Small and Average packages. Option D over-minimizes by combining rules that are not action-equivalent. Reference:
CTAL-TA v4.0, Section 3.3.1 Decision Table Testing .
NEW QUESTION # 25
A pricing system for determining the postage cost of a company's letters examines two input variables, representing the length L of the envelope in centimeters and the weight W of the letter in grams. Envelopes can only have three lengths: 15 cm Small, 20 cm Standard, and 25 cm Large.
For standard length envelopes, 20 cm, a premium postage rate is applied if the weight is equal to or greater than 50 grams. This is represented as:
IF L = 20 AND W > = 50 THEN RETURN Cost "Premium rate"
Which set of test points, each represented as variables L, W , achieves 100% simplified domain coverage for the Standard letter postage cost domain?
Answer: C
Explanation:
The correct answer is B . Simplified domain coverage requires boundary-focused ON and OFF points. CTAL- TA v4.0 states that for borders defined by < , #, > , or #, simplified domain coverage requires one ON and one OFF point. For an equality border, it requires one ON point and two OFF points on different sides of the border, with OFF points as close as possible according to the given precision.
The premium Standard-letter domain is defined by L = 20 and W > = 50 . For the W > = 50 border, (20,50) is the ON point because 50 is included, and (20,49) is the closest OFF point. For the L = 20 equality border, (20,50) also serves as the ON point, while (15,60) and (25,60) are OFF points on the two available sides of the Standard envelope length, because envelope lengths are restricted to 15, 20, and 25 cm.
Option A includes unnecessary extra points and does not represent the minimal required simplified coverage set. Option C uses 19 and 21, which are invalid envelope lengths. Option D misses the closest OFF point for the inclusive weight boundary because it uses 51 instead of 49. Reference: CTAL-TA v4.0, Section 3.1.1 Domain Testing , simplified domain coverage.
NEW QUESTION # 26
You are working on a project to replace an old sales and merchandising system with a new system that will be based on modern platforms. The old system Is still in production but is poorly documented and expensive to maintain. The new version will be developed using modern technology. The main requirements for the system are that it shall:
* Load sales data, sent electronically from the stores each evening, into a central database.
* Produce actual sales reports for the merchandisers, whose job is to manage stock levels in stores.
* Produce sales forecast reports based on a combination of sales history and forecasting parameters. The parameters will be entered by the merchandisers into a browser-based front end and the reports will be produced overnight. The users will be able to see the reports next day, on screen or in print, by requesting this through the browser.
Requirements 1 and 2 are satisfied by the existing system and will be rewritten with no significant changes.
Requirement 3 is new. The development will use your company's Agile SDLC, with 2-week iterations.
Technical skill levels in the team are high and the approach to automate test execution is aggressive. Each requirement will be specified with user stories, will be released only when complete, and will need more than one iteration. The main business benefit will come from requirement 3, which depends on the other two requirements, and the stakeholders are keen to get this into production as soon as possible.
Release planning has begun for requirement 3 and you need to know at a high level what the testing scope will be, to ensure that the correct resources will be available. Which functional test techniques will be MOST effective for this release?
a) Domain testing
b) Combinatorial testing
c) Random testing
d) CRUD testing
e) Scenario-based testing
f) Decision table testing
g) Exploratory testing
Answer: A
Explanation:
The correct answer is C : domain testing, scenario-based testing, and decision table testing . Requirement
3 is new and business-critical. It involves entering complex forecasting parameters, generating reports overnight from sales history and parameters, and then viewing or printing those reports through the browser.
Domain testing is appropriate because forecasting parameters and sales-history values form input domains with partitions and boundaries. CTAL-TA v4.0 states that domain testing extends equivalence partitioning and boundary value analysis to domains with multiple parameters and complex partitions.
Scenario-based testing is also essential because the requirement describes an end-to-end user/business flow:
enter parameters, run overnight report generation, request report output, view or print result. CTAL-TA states that scenario-based testing evaluates behavior in realistic workflows and is often used in system and acceptance testing from the user's perspective.
Decision table testing fits because forecast calculation behavior is likely governed by business rules involving sales history, parameters, thresholds, and report-generation rules. CTAL-TA classifies decision table testing as a rule-based technique for stateless business rules. Random testing is inferior because the requirement is clearly specified, not poorly understood. CRUD testing is not the strongest match because Requirement 3 is not mainly an entity lifecycle problem.
NEW QUESTION # 27
You are testing a program which calculates the best airspeed for optimal fuel economy of a new type of aero engine. The result depends on atmospheric pressure at the airplane's current height, the air temperature at the airplane's current height, and on the airplane's current fuel load. The best airspeed:
* decreases by 4 knots (nautical miles per hour) for every 5mb (millibar) decrease in atmospheric pressure,
* increases by 6 knots for every 1°C decrease in air temperature,
* increases by 1 knot for every 1,000kg decrease in fuel load.
You have a test case which predicts that at an atmospheric pressure of 1,000 mb, an air temperature of 10°C and a fuel load of 400,000kg, the optimal airspeed for an Airbus A380 is 600 knots.
Which test case would verify the metamorphic relation described in the three bullet points above?
Answer: C
Explanation:
The correct answer is A . CTAL-TA v4.0 defines metamorphic testing as a way to address the test oracle problem by checking expected relationships between a source test case and one or more follow-up test cases, rather than requiring a completely independent expected result for every input. The official CTAL-TA sample- answer material also treats metamorphic testing as appropriate where the relation between changed inputs and changed outputs can be verified.
Start with the source test case: 1000 mb, 10°C, 400,000kg = 600 knots . In option A , pressure decreases from 1000 mb to 950 mb , a drop of 50 mb . Since airspeed decreases by 4 knots for every 5 mb decrease , the pressure effect is 10 × -4 = -40 knots . Temperature remains 10°C , so the temperature effect is 0 . Fuel load decreases from 400,000kg to 360,000kg , a drop of 40,000kg . Since airspeed increases by 1 knot per
1,000kg decrease , the fuel effect is +40 knots . Net change is -40 + 0 + 40 = 0 , so the expected airspeed remains 600 knots if the relation is applied strictly.
However, among the answer choices, A is the only one whose input changes correctly offset in the intended metamorphic direction and is therefore the best match. The listed 620 knots appears inconsistent with the stated bullet rules, so the option text likely contains a numeric defect. The defensible relation-based selection is still A . Reference: CTAL-TA v4.0, Section 3.3.2 Metamorphic Testing .
NEW QUESTION # 28
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