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| Section | Objectives |
|---|
| Topic 1: Functions and Graphs | - Graphing Functions
- 1. Transformations of graphs
- 2. Coordinate plane interpretation
- Function Concepts
- 1. Function notation
- 2. Domain and range
|
| Topic 2: Exponential and Logarithmic Concepts | - Logarithmic Basics
- 1. Conversion between exponential and logarithmic form
- 2. Logarithm properties
- Exponential Functions
- 1. Exponential equations
- 2. Growth and decay models
|
| Topic 3: Polynomial and Rational Expressions | - Polynomials
- 1. Factoring techniques
- 2. Operations with polynomials
- Rational Expressions
- 1. Restrictions on variables
- 2. Simplification
|
| Topic 4: Linear Functions and Systems | - Systems of Equations
- 1. Elimination method
- 2. Substitution method
- Linear Equations
- 1. Point-slope form
- 2. Slope-intercept form
|
| Topic 5: Foundations of Algebra | - Equations and Inequalities
- 1. Linear equations in one variable
- 2. Inequalities and interval notation
- Algebraic Expressions
- 1. Order of operations
- 2. Simplifying expressions
- 3. Evaluating expressions
|
>> Applied-Algebra Latest Exam Questions <<
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WGU Applied Algebra FXO2 PFXP C957 Sample Questions (Q103-Q108):
NEW QUESTION # 103
The graph shows the number of customers, C(t), showing up to a store, where the number of hours since opening is along the horizontal axis and the number of customers showing up to the store each hour is along the vertical axis.

How can the concavity be described from t=6.2to t=10.1?
- A. The number of customers decreases slower and slower and then increases faster and faster.
- B. The number of customers increases slower and slower and then decreases faster and faster.
- C. The number of customers increases slower and slower and then increases faster and faster.
- D. The number of customers increases faster and faster and then increases slower and slower.
Answer: B
Explanation:
From t=6.2to about t=8.5, the graph is increasing, but it is becoming less steep as it approaches a local maximum.
That means the number of customers is:
" increasing slower and slower "
After the local maximum, from about t=8.5to t=10.1, the graph begins to decrease and becomes steeper downward.
That means the number of customers is:
" decreasing faster and faster "
So the full description is:
" The number of customers increases slower and slower and then decreases faster and faster. " Therefore, the correct answer is:
# ( " D " )
NEW QUESTION # 104
A coach is placing an order for team shirts. The graph shows the total cost based on the number of shirts.
What is the cost of each additional shirt?
Exhibit:

- A. $3.90
- B. $49.00
- C. $10.00
- D. $13.90
Answer: C
Explanation:
This question asks for the cost of each additional shirt, which is the slope of the linear graph. The slope tells how much the total cost increases for each increase of 1 shirt. From the exhibit, the graph shows a starting cost near $39 and a point near (10, 139). The increase in cost from 0 shirts to 10 shirts is 139#39=100 dollars.
Dividing by 10 shirts gives a rate of 10 dollars per shirt. The fixed starting cost is not the cost of a shirt; it is the initial fee or setup cost. Since the graph rises by $10 for each additional shirt, the cost per additional shirt is $10.00. Therefore, the answer is B.
NEW QUESTION # 105
A researcher collected data on the number of daily posts on a blog. The results are shown in the scatterplot.
The graphed regression function has an r
2
value of 0.89.

Is it appropriate to make a prediction for the number of daily posts after 18.6 months?
- A. Yes. The r2value indicates a strong fit, and x=18.6 is within 50% of the range of the maximum value.
- B. Yes. The r2value indicates a moderate fit, and x=18.6 is within 25% of the range of the maximum value.
- C. No. The r2value indicates a strong fit, but x=18.6 is more than 50% of the range beyond the maximum value.
- D. No. The r2value indicates a moderate fit, but x=18.6 is more than 25% of the range beyond the maximum value.
Answer: A
Explanation:
The value r2=0.89 indicates a strong fit because it is close to 1. A strong fit means the regression function follows the scatterplot data closely enough to support reasonable prediction. The question asks whether a prediction at x=18.6 months is appropriate. This value is outside the observed data range, so the prediction involves extrapolation. For a strong regression model, extrapolation can be acceptable if the new x-value is not too far beyond the maximum observed value. Here, x=18.6 is within 50% of the range beyond the maximum value, so the prediction is considered appropriate. Therefore, the correct answer is C.
NEW QUESTION # 106
The number of people auditioning for a game show is expected to be 3 less than the number of people who auditioned last year. The function A(t)can be used to model the situation, where trepresents the number of people who auditioned last year and Arepresents the number of people expected to audition this year.
Which quantity represents the number of people expected to audition this year, given that 280 people auditioned last year?
- A. A(280)=277
- B. A(277)=280
- C. A(280)=283
- D. A(283)=280
Answer: A
Explanation:
The function A(t)represents the number of people expected to audition this year.
The input trepresents the number of people who auditioned last year.
The problem says this year's number is expected to be 3 less than last year's number. Therefore, the function rule is:
A(t)=t-3
We are told that 280 people auditioned last year, so:
t=280
Substitute 280into the function:
A(280)=280-3
A(280)=277
So, the notation that represents the number of people expected to audition this year is:
A(280)=277
This means if 280 people auditioned last year, then 277 people are expected to audition this year.
Therefore, the correct answer is:
# ( " A " )
NEW QUESTION # 107
The graph shows the number of people watching a live video. The number of minutes since the video began is on the horizontal axis, and the number of viewers is on the vertical axis. When were there 432 viewers?
Exhibit:

- A. Minute 4
- B. Minute 0
- C. Minute 1
- D. Minute 2
Answer: C
Explanation:
This problem requires reading a value from a graph. The horizontal axis gives time in minutes, and the vertical axis gives the number of viewers. To solve it, find 432 on the vertical axis, locate where the graph reaches that value, and then move down to the horizontal axis. From the exhibit, the graph reaches 432 viewers at minute 1. That means the ordered pair is approximately (1, 432), so the input is 1 minute and the output is 432 viewers. The other listed minutes correspond to different viewer counts on the graph. In graphical depictions, matching the correct input-output pair is the key step. Therefore, the correct answer is B.
NEW QUESTION # 108
......
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