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NEW QUESTION # 27
Refer to the following code (correcting the missing template literal backticks):
let codeName = 'Bond';
let sampleText = `The name is ${codeName}, Jim ${codeName}`;
A developer is trying to determine if a certain substring is part of a string.
Which three code statements return true?
Answer: A,C,E
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
First, compute sampleText:
let codeName = 'Bond';
let sampleText = `The name is ${codeName}, Jim ${codeName}`;
The template literal evaluates to:
"The name is Bond, Jim Bond"
Now evaluate each statement:
Option A: sampleText.includes('Jim');
String.prototype.includes(substring) returns true if substring occurs anywhere in the string.
sampleText clearly contains "Jim" ("The name is Bond, Jim Bond").
So this returns true.
Option B: sampleText.includes('The', 1);
includes(searchString, position) starts searching from the given position index.
"The name is Bond, Jim Bond" has "The" starting at index 0.
Starting search at index 1 means "The" at index 0 is not considered, and there is no second "The".
So this returns false.
Option C: sampleText.includes('Jim', 4);
"Jim" appears after "The name is Bond, " which is longer than 4 characters; the index of "Jim" is well past 4.
So when searching from index 4, "Jim" is still found.
This returns true.
Option D: sampleText.indexOf('Bond') !== -1;
String.prototype.indexOf(substring) returns:
-1 if the substring is not found,
Otherwise, the starting index of the first occurrence.
"Bond" appears twice in "The name is Bond, Jim Bond".
So sampleText.indexOf('Bond') is some non-negative index (for the first occurrence).
Therefore indexOf('Bond') !== -1 is true.
Option E: sampleText.substring('Jim');
substring expects numeric indexes: substring(startIndex, endIndex?).
If given a string "Jim" as the argument, JavaScript coerces it to a number:
Number('Jim') → NaN
NaN for startIndex is treated as 0.
So sampleText.substring('Jim') is effectively sampleText.substring(0), which returns the full string "The name is Bond, Jim Bond".
This is a string, not a boolean. The question asks "which code statements return true?" This statement returns a string, not the boolean value true.
Thus, the three statements that actually return true (boolean) are:
Study Guide / Concept Reference (no links):
Template literals and ${} interpolation
String.prototype.includes(searchString, position?)
String.prototype.indexOf(substring) and checking for !== -1
String.prototype.substring(start, end?) and argument coercion
Boolean vs non-boolean return types in string methods
________________________________________
NEW QUESTION # 28
Which two console logs output NaN?
Choose 2 answers | |
Answer: C,D
NEW QUESTION # 29
Given the code below:
Which method can be used to provide a visual representation of the list of users and to allow sorting by the name or email attribute?
Answer: C
NEW QUESTION # 30
Universal Container(UC) just launched a new landing page, but users complain that the website is slow. A developer found some functions that cause this problem.To verify this, the developer decides to do everything and log the time each of these three suspicious functions consumes.
console.time('Performance');
maybeAHeavyFunction();
thisCouldTakeTooLong();
orMaybeThisOne();
console.endTime('Performance');
Which function can the developer use to obtain the time spent by every one of the three functions?
Answer: D
NEW QUESTION # 31
Which two implementations of utils.js support foo and bar?
Answer: C,D
Explanation:
}
Explanation:
The correct answers are A and C because both use named exports for foo and bar.
A module can export multiple values by name:
export { foo, bar };
This allows another file to import them like this:
import { foo, bar } from './utils.js';
Option A is correct because it defines both functions locally and exports both of them as named exports.
const foo = () => { return 'foo'; };
const bar = () => { return 'bar'; };
export { foo, bar };
Option C is also correct after correcting the typing issue so that both foo and bar are imported first:
import { foo, bar } from "./helpers/utils.js";
export { foo, bar };
This is called re-exporting. The module imports foo and bar from another module, then exports them again from utils.js.
Option B is not the best answer for named access because it exports one default object:
export default { foo, bar };
That would require a default import first:
import utils from './utils.js';
utils.foo();
utils.bar();
It does not directly support named imports in the same way as:
import { foo, bar } from './utils.js';
Option D exports a default class. Its foo() and bar() are class instance methods, not named exported functions. It would require usage like:
import Utils from './utils.js';
const utils = new Utils();
utils.foo();
utils.bar();
So for direct multiple function exports, the correct implementations are A and C.
NEW QUESTION # 32
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