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| Section | Objectives |
|---|
| Topic 1: Browser and DOM Interaction | - Browser APIs (fetch, storage, timers) - Event handling and propagation - DOM manipulation and traversal
|
| Topic 2: Salesforce Platform Integration | - Calling Apex methods from JavaScript - Security considerations in Salesforce JavaScript - Lightning Web Components (LWC) JavaScript usage
|
| Topic 3: JavaScript Language Fundamentals | - Data types, variables, and operators - Functions, scope, and closures - ES6+ syntax and features
|
| Topic 4: Testing and Debugging | - Unit testing principles - Debugging techniques and tools
|
| Topic 5: Asynchronous JavaScript | - Error handling in async workflows - Promises and async/await - Event loop and concurrency model
|
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Salesforce Certified JavaScript Developer (JS-Dev-101) Sample Questions (Q145-Q150):
NEW QUESTION # 145
Refer to the code below:
class Student {
constructor(name) {
this._name = name;
}
displayGrade() {
console.log(`${this._name} got 70% on test.`);
}
}
class GraduateStudent extends Student {
constructor(name) {
super(name);
this._name = " Graduate Student " + name;
}
displayGrade() {
console.log(`${this._name} got 100% on test.`);
}
}
let student = new GraduateStudent( " Jane " );
student.displayGrade();
What is the console output?
- A. Better student Jackie got 70% on test.
- B. Graduate Student Jane got 100% on test.
- C. Jackie got 70% on test.
- D. Uncaught ReferenceError
Answer: B
Explanation:
The correct answer is C , after correcting the option text to match the actual code.
The object is created here:
let student = new GraduateStudent( " Jane " );
Because GraduateStudent extends Student, its constructor runs:
constructor(name) {
super(name);
this._name = " Graduate Student " + name;
}
The call to:
super(name);
runs the parent Student constructor first and temporarily sets:
this._name = " Jane " ;
Then this line in the child constructor overwrites that value:
this._name = " Graduate Student " + name;
So the final value of this._name becomes:
" Graduate Student Jane "
Next, this line executes:
student.displayGrade();
Since student is an instance of GraduateStudent, JavaScript uses the overridden displayGrade() method from GraduateStudent, not the parent method from Student.
The executed method is:
displayGrade() {
console.log(`${this._name} got 100% on test.`);
}
Therefore, the console output is:
Graduate Student Jane got 100% on test.
Important correction: the original option C said something like " Better student Jackie got 100% on test. " , but the actual code uses " Graduate Student " and the name " Jane " . The verified corrected answer remains C
.
NEW QUESTION # 146
Given the code below:

What is logged to the console'
- A. 2 5 1 3 4
- B. 1 2 3 4 5
- C. 2 5 3 4 1
- D. 1 2 5 3 4
Answer: C
NEW QUESTION # 147
Refer to the following code:

Which two statement could be inserted at line 17 to enable the function call on line 18?
Choose 2 answers
- A. leo.prototype.roar = ( ) =>( console.log('They\'re pretty good!'); };
- B. Object.assign (leo. Tiger);
- C. leo.roar = () => { console.log('They\'re pretty good!'); );
- D. Object.assign (leo, tony);
Answer: C,D
NEW QUESTION # 148
Refer to the code below:
function foo () {
const a =2;
function bat() {
console.log(a);
}
return bar;
}
Why does the function bar have access to variable a ?
- A. Hoisting
- B. Prototype chain
- C. Inner function's scope
- D. Outer function's scope
Answer: D
NEW QUESTION # 149
A developer has a fizzbuzz function that, when passed in a number, returns the following:
* ' fizz ' if the number is divisible by 3.
* ' buzz ' if the number is divisible by 5.
* ' fizzbuzz ' if the number is divisible by both 3 and 5.
* Empty string if the number is divisible by neither 3 nor 5.
Which two test cases properly test scenarios for the fizzbuzz function?
- A. let res = fizzbuzz(Infinity);
console.assert(res === ' ' ); - B. let res = fizzbuzz(3);
console.assert(res === ' buzz ' ); - C. let res = fizzbuzz(NaN);
console.assert(isNaN(res)); - D. let res = fizzbuzz(15);
console.assert(res === ' fizzbuzz ' );
Answer: A,D
Explanation:
The correct answers are B and D .
A strong test case checks whether the actual output matches the expected behavior of the function.
For Option B :
let res = fizzbuzz(15);
console.assert(res === ' fizzbuzz ' );
The number 15 is divisible by both 3 and 5:
15 % 3 === 0
15 % 5 === 0
So the correct return value is:
' fizzbuzz '
That makes option B a valid test.
For Option D :
let res = fizzbuzz(Infinity);
console.assert(res === ' ' );
Infinity is not a normal finite divisible number. In JavaScript:
Infinity % 3
Infinity % 5
produce NaN, and comparisons such as:
Infinity % 3 === 0
are false.
So a typical fizzbuzz implementation would not treat Infinity as divisible by 3 or 5, meaning it should return:
' '
That makes option D a valid test for the "neither divisible by 3 nor 5" path.
Now compare the incorrect options:
Option A is wrong because:
fizzbuzz(3)
should return:
' fizz '
not:
' buzz '
Option C is wrong because the function specification says the function returns strings such as ' fizz ' , ' buzz '
, ' fizzbuzz ' , or ' ' . It does not say the function returns numeric NaN.
So this assertion is not appropriate:
console.assert(isNaN(res));
Therefore, the verified answers are B and D .
NEW QUESTION # 150
......
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