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Snowflake ARA-C01 Exam Overview:

Certification Vendor:	Snowflake
Exam Name:	SnowPro Advanced: Architect Certification Exam
Exam Number:	ARA-C01
Exam Price:	USD 375
Available Languages:	English
Related Certifications:	SnowPro Core SnowPro Advanced: Data Analyst SnowPro Advanced: Data Engineer
Certificate Validity Period:	2 years
Real Exam Qty:	65
Exam Duration:	115 minutes
Passing Score:	750 / 1000
Exam Format:	Multiple Choice, Multiple Select
Recommended Training:	Snowflake Advanced Architect Learning Path Snowflake Documentation
Exam Registration:	Pearson VUE Registration Snowflake Certification Portal
Sample Questions:	Snowflake ARA-C01 Sample Questions
Exam Way:	Online proctored or Onsite testing center
Pre Condition:	Recommended: SnowPro Core certification + 2+ years hands-on experience as Snowflake Architect in production environment
Official Syllabus URL:	https://learn.snowflake.com/en/certifications/snowpro-advanced-architect/

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To take the Snowflake ARA-C01 exam, candidates must have previously passed the SnowPro Core Certification and have significant experience working with Snowflake's cloud data warehouse platform. ARA-C01 exam consists of 60 multiple-choice questions and must be completed within 90 minutes. A passing score of 80% or higher is required to earn the SnowPro Advanced Architect Certification, which is recognized by organizations worldwide as a validation of advanced skill and knowledge in Snowflake data warehousing.

Obtaining the Snowflake ARA-C01 Certification demonstrates that an individual has the skills and expertise to design, implement, and manage complex data solutions on the Snowflake platform. SnowPro Advanced Architect Certification certification is highly valued in the IT industry and can lead to better job opportunities and higher salaries. Additionally, Snowflake ARA-C01 certified professionals can help their organizations to optimize their data solutions and achieve better business outcomes.

Snowflake SnowPro Advanced Architect Certification Sample Questions (Q196-Q201):

NEW QUESTION # 196
An Architect has a table called leader_follower that contains a single column named JSON. The table has one row with the following structure:
{
"activities": [
{ "activityNumber": 1, "winner": 5 },
{ "activityNumber": 2, "winner": 4 }
],
"follower": {
"name": { "default": "Matt" },
"number": 4
},
"leader": {
"name": { "default": "Adam" },
"number": 5
}
}
Which query will produce the following results?
ACTIVITY_NUMBER
WINNER_NAME
1
Adam
2
Matt

A. SELECT
B. value:winner = lf.json:leader.number,
lf.json:leader.name.default,
lf.json:follower.name.default
)::VARCHAR AS winner_name
FROM leader_follower lf,
LATERAL FLATTEN(input => json:activities) p;
C. value:winner = lf.json:leader.number,
lf.json:leader,
lf.json:follower
)::VARCHAR AS winner_name
FROM leader_follower lf,
LATERAL FLATTEN(input => json:activities) p;
D. value:activityNumber AS activity_number,
IFF(
E. value:activityNumber AS activity_number,
IFF(
F. SELECT
G. value:winner = lf.json:leader.number,
lf.json:leader.name.default,
lf.json:follower.name.default
)::VARCHAR AS winner_name
FROM leader_follower lf,
LATERAL FLATTEN(input => json:activities, outer => TRUE) p;
H. SELECT
I. value:activityNumber AS activity_number,
IFF(
J. SELECT lf.json:activities.activityNumber AS activity_number,
IFF(
lf.json:activities.activityNumber = lf.json:leader.number,
lf.json:leader.name.default,
lf.json:follower.name.default
)::VARCHAR
FROM leader_follower lf;

Answer: A

Explanation:
This question tests several core Snowflake semi-structured data concepts that are explicitly part of the SnowPro Architect exam scope: working with VARIANT data, array handling, and the use of LATERAL FLATTEN. The activities element in the JSON structure is an array, meaning it must be flattened before individual attributes such as activityNumber and winner can be accessed. Option A is invalid because it attempts to directly reference fields inside an array without flattening it.
Option B correctly uses LATERAL FLATTEN on json:activities, which produces one row per activity. The alias p.value represents each array element, allowing access to activityNumber and winner. The IFF expression then compares the activity's winner value with leader.number. When they match, the query returns leader.name.default; otherwise, it returns follower.name.default. Casting the result to VARCHAR ensures a proper scalar output.
Option C is incorrect because it attempts to return full JSON objects (leader or follower) rather than the nested name.default value. Option D uses OUTER => TRUE, which is unnecessary in this case because the activities array is guaranteed to exist; while it would still work, Snowflake exam questions typically expect the most precise and minimal correct solution.

NEW QUESTION # 197
What step will improve the performance of queries executed against an external table?

A. Use an internal stage instead of an external stage to store the source files.
B. Partition the external table.
C. Shorten the names of the source files.
D. Convert the source files' character encoding to UTF-8.

Answer: B

NEW QUESTION # 198
An Architect is designing a pipeline to stream event data into Snowflake using the Snowflake Kafka connector. The Architect's highest priority is to configure the connector to stream data in the MOST cost-effective manner.
Which of the following is recommended for optimizing the cost associated with the Snowflake Kafka connector?

A. Utilize a higher Buffer.size.bytes in the connector configuration.
B. Utilize a higher Buffer.flush.time in the connector configuration.
C. Utilize a lower Buffer.size.bytes in the connector configuration.
D. Utilize a lower Buffer.count.records in the connector configuration.

Answer: D

NEW QUESTION # 199
A Snowflake Architect is designing a multi-tenant application strategy for an organization in the Snowflake Data Cloud and is considering using an Account Per Tenant strategy.
Which requirements will be addressed with this approach? (Choose two.)

A. Tenant data shape may be unique per tenant.
B. There needs to be fewer objects per tenant.
C. Storage costs must be optimized.
D. Compute costs must be optimized.
E. Security and Role-Based Access Control (RBAC) policies must be simple to configure.

Answer: A,E

Explanation:
The Account Per Tenant strategy involves creating separate Snowflake accounts for each tenant within the multi-tenant application. This approach offers a number of advantages.
Option B: With separate accounts, each tenant's environment is isolated, making security and RBAC policies simpler to configure and maintain. This is because each account can have its own set of roles and privileges without the risk of cross-tenant access or the complexity of maintaining a highly granular permission model within a shared environment.
Option D: This approach also allows for each tenant to have a unique data shape, meaning that the database schema can be tailored to the specific needs of each tenant without affecting others. This can be essential when tenants have different data models, usage patterns, or application customizations.

NEW QUESTION # 200
All multi cluster warehouses that were using the Legacy policy now use the default Standard policy

A. TRUE
B. FALSE

Answer: A

NEW QUESTION # 201
......

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