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| Section | Objectives |
|---|---|
| Testing and Debugging | - Trace Errors - Debugging Techniques - Unit Testing Concepts |
| Python Fundamentals | - Operators and Expressions - Input/Output Operations - Type Conversion - Variables and Data Types |
| Data Structures | - Sets - String Manipulation - Lists and List Operations - Dictionaries - Tuples |
| Functions | - Scope (local and global) - Recursion - Function Definition and Call - Return Values - Parameters and Arguments |
| File Handling and Exceptions | - Exception Handling (try, except, finally) - Custom Exceptions - Reading and Writing Files |
| Control Structures | - Conditional Statements (if, elif, else) - Loop Control (break, continue, pass) - Nested Conditionals and Loops - Loops (for, while) |
| Object-Oriented Programming | - Inheritance - Constructors (__init__) - Classes and Objects - Encapsulation - Attributes and Methods |
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NEW QUESTION # 31
Write a complete function password_strength(password) that returns " Strong " if the password is at least 8 characters long and contains both letters and numbers, " Weak " otherwise.
For example, password_strength( " abc123def " ) should return " Strong " .
def password_strength(password):
# TODO: Return " Strong " or " Weak " based on password criteria
if len(password) < 8:
return " Weak "
has_letter = False
has_number = False
for char in password:
if char.isalpha():
has_letter = True
elif char.isdigit():
has_number = True
# TODO: Add your return logic here based on has_letter and has_number
pass
Answer:
Explanation:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: First, check the password length using len(password).
Step 2: If the password has fewer than 8 characters, return " Weak " immediately.
Step 3: Create two Boolean variables: has_letter and has_number.
Step 4: Loop through each character in the password.
Step 5: Use .isalpha() to check for letters and .isdigit() to check for numbers.
Step 6: If the password contains both at least one letter and at least one number, return " Strong " .
Step 7: Otherwise, return " Weak " .
Correct code:
def password_strength(password):
if len(password) < 8:
return " Weak "
has_letter = False
has_number = False
for char in password:
if char.isalpha():
has_letter = True
elif char.isdigit():
has_number = True
if has_letter and has_number:
return " Strong "
else:
return " Weak "
Example:
print(password_strength( " abc123def " ))
print(password_strength( " abcdefgh " ))
print(password_strength( " 12345678 " ))
Output:
Strong
Weak
Weak
NEW QUESTION # 32
How can the first four characters be extracted from the string ' computer ' ?
Answer: A
Explanation:
Python strings are sequences, and sequence values can be accessed using indexing and slicing.
The first character in a Python string has index 0. To extract the first four characters from ' computer ' , the slice should start at index 0 and stop at index 4.
Example:
' computer ' [0:4]
Result:
' comp '
In Python slicing, the start index is included, but the stop index is excluded. So [0:4] includes characters at indexes 0, 1, 2, and 3.
The official Python documentation explains that slicing with a[start:stop] selects items from the start index up to, but not including, the stop index.
Therefore, the correct answer is A. ' computer ' [0:4].
NEW QUESTION # 33
Write a complete function word_count(text) that counts and returns the number of words in the given text.
Words are separated by spaces.
For example, word_count( " Hello world Python " ) should return 3.
def word_count(text):
# TODO: Count and return the number of words in text
pass
Answer:
Explanation:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: The function receives one string parameter named text.
Step 2: Since words are separated by spaces, use the .split() method to split the string into a list of words.
Step 3: Use len() to count how many items are in the list.
Step 4: Return that count.
Correct code:
def word_count(text):
return len(text.split())
Example:
print(word_count( " Hello world Python " ))
Output:
3
NEW QUESTION # 34
Which data type does the expression 5 > 3 evaluate to in Python?
Answer: A
Explanation:
In Python, comparison expressions such as 5 > 3 evaluate to aBooleanvalue.
The expression:
5 > 3
checks whether 5 is greater than 3. Since this statement is true, Python returns:
True
True and False are Boolean values in Python.
Therefore, the correct answer isC. Boolean.
NEW QUESTION # 35
Fix the logic error in this function that should return the larger of two numbers.
def find_maximum(a, b):
if a < b:
return a
else:
return b
Answer:
Explanation:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: The function should return the larger number.
Step 2: The condition a < b means b is larger than a.
Step 3: In the original code, when a < b is true, it incorrectly returns a.
Step 4: The return values need to be corrected.
Correct code:
def find_maximum(a, b):
if a < b:
return b
else:
return a
Alternative correct code:
def find_maximum(a, b):
if a > b:
return a
else:
return b
Example:
print(find_maximum(10, 20))
print(find_maximum(30, 15))
Output:
20
30
NEW QUESTION # 36
......
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