認定するJS-Dev-101復習攻略問題試験-試験の準備方法-完璧なJS-Dev-101資格準備

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Salesforce JS-Dev-101 認定試験の出題範囲：

トピック出題範囲
トピック 1
  • Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
トピック 2
  • Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
トピック 3
  • Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.
トピック 4
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.
トピック 5
  • Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.

>> JS-Dev-101復習攻略問題 <<

実用的なJS-Dev-101復習攻略問題 | 最初の試行で簡単に勉強して試験に合格する & 効率的なSalesforce Salesforce Certified JavaScript Developer - Multiple Choice

テストSalesforceのJS-Dev-101の認定に合格すると、あなたの就労能力が社会からSalesforce認められ、良い仕事を見つけることができます。 JS-Dev-101クイズトレントを習得して試験に合格した場合。 同僚、上司、親、友人、社会から尊敬されます。 総じて、JS-Dev-101テスト準備を購入すると、試験に合格するだけでなく、キャリアと将来についての夢を実現するのに役立ちます。 そのため、JS-Dev-101試験の教材を購入してすぐに対策を講じることをheしないでください。

Salesforce Certified JavaScript Developer - Multiple Choice 認定 JS-Dev-101 試験問題 (Q117-Q122):

質問 # 117
Which two implementations of utils.js support foo and bar?

正解：A、D

解説：
}
Explanation:
The correct answers are A and C because both use named exports for foo and bar.
A module can export multiple values by name:
export { foo, bar };
This allows another file to import them like this:
import { foo, bar } from './utils.js';
Option A is correct because it defines both functions locally and exports both of them as named exports.
const foo = () => { return 'foo'; };
const bar = () => { return 'bar'; };
export { foo, bar };
Option C is also correct after correcting the typing issue so that both foo and bar are imported first:
import { foo, bar } from "./helpers/utils.js";
export { foo, bar };
This is called re-exporting. The module imports foo and bar from another module, then exports them again from utils.js.
Option B is not the best answer for named access because it exports one default object:
export default { foo, bar };
That would require a default import first:
import utils from './utils.js';
utils.foo();
utils.bar();
It does not directly support named imports in the same way as:
import { foo, bar } from './utils.js';
Option D exports a default class. Its foo() and bar() are class instance methods, not named exported functions. It would require usage like:
import Utils from './utils.js';
const utils = new Utils();
utils.foo();
utils.bar();
So for direct multiple function exports, the correct implementations are A and C.


質問 # 118
At Universal Containers, every team has its own way of copying JavaScript objects. The code Snippet shows an implementation from one team:
Function Person() {
this.firstName = "John";
this.lastName = 'Doe';
This.name =() => (
console.log('Hello $(this.firstName) $(this.firstName)');
)}
Const john = new Person ();
Const dan =JSON.parse(JSON.stringify(john));
dan.firstName ='Dan';
dan.name();
What is the Output of the code execution?

正解：D


質問 # 119
Refer to the following array:
let arr = [1, 2, 3, 4, 5];
Which two lines of code result in a second array, arr2, created such that arr2 is a reference to arr?

正解：A、C

解説：
The correct answers are C and D.
Arrays in JavaScript are objects. When an array variable is assigned directly to another variable, both variables point to the same array in memory.
Option C is correct:
let arr2 = arr;
This does not create a new array. It creates another reference to the same array.
Example:
arr2.push(6);
console.log(arr);
Output:
[1, 2, 3, 4, 5, 6]
Changing arr2 also affects arr because both variables reference the same array.
Option D is also correct:
let arr2 = arr.sort();
The sort() method sorts the array in place and returns the same array reference. Therefore, arr2 refers to the same array object as arr.
The incorrect options create copies:
let arr2 = arr.slice(0, 5);
creates a shallow copy.
let arr2 = Array.from(arr);
also creates a new shallow copy.
So the two lines that make arr2 reference the original arr are C and D.


質問 # 120
01 function Monster() { this.name = 'hello'; };
02 const m = Monster();
What happens due to the missing new keyword?

正解：B

解説：
In JavaScript, when calling a constructor function without new:
const m = Monster();
the following happens:
The function executes as a normal function, not as a constructor.
Inside a regular function (in non-strict mode), this refers to the global object:
In a browser: window
So the line:
this.name = 'hello';
becomes:
window.name = 'hello';
Since Monster() does not return anything, its return value is undefined:
const m = undefined;
Therefore:
m is undefined
window.name becomes "hello"
This matches option B.
JavaScript Knowledge Reference (text-only)
Calling a function without new uses the global object as this in non-strict mode.
Constructor functions must use new to create a new object.
Functions without an explicit return return undefined.


質問 # 121
Refer to the code:
01 const event = new CustomEvent(
02 // Missing code
03 );
04 obj.dispatchEvent(event);
A developer needs to dispatch a custom event called update to send information about recordId.
Which two options can be inserted at line 02?

正解：C、D

解説：
The correct constructor signature for CustomEvent is:
new CustomEvent(eventName, optionsObject)
Where:
eventName is a string.
optionsObject may include:
detail → used to pass custom data
bubbles
cancelable, etc.
Example:
new CustomEvent('update', {
detail: { recordId: '123abc' }
});
Now evaluate each option:
Option A
{ type: 'update', recordId: '123abc' }
Incorrect: The constructor requires (eventName, options), not a single object. type is not used this way.
Option B
'update', { detail: { recordId: '123abc' } }
Correct format. detail is the proper place for custom event data.
Option C
'update', '123abc'
Incorrect: The second argument must be an object (options), not a string.
Option D
'update', { recordId: '123abc' }
Acceptable because any extra properties on the options object are still allowed, even though best practice is to use detail.
This still creates a valid CustomEvent, and the event will dispatch successfully.
Thus the two correct answers are B and D.
JavaScript Knowledge Reference (text-only)
new CustomEvent(name, options) is the required syntax.
The detail property of the options object is the standard location for custom data.
The second argument must be an object; other types are invalid.


質問 # 122
......

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