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| Section | Weight | Objectives |
|---|---|---|
| Asynchronous Programming | 13% | - Async/Await syntax - Promises (creation, chaining, error handling) - Event loop and execution flow - Callbacks - Asynchronous patterns for business requirements |
| Browser and Events | 17% | - Event propagation (bubbling and capturing) - Browser-specific APIs - Event handling and listeners - DOM manipulation - Browser Developer Tools usage - Interacting with forms and user input |
| Debugging and Error Handling | 7% | - Error handling techniques (try/catch/finally) - Custom error types - Console methods for debugging - Breakpoints and code inspection |
| Server Side JavaScript | 8% | - CLI commands - Package management (npm) - Server-side JavaScript implementations - Core Node.js modules - Node.js fundamentals |
| Objects, Functions, and Classes | 25% | - ES6 classes and inheritance - Variable scope and closures - Object creation and manipulation - Higher-order functions - Prototypal inheritance - Modules and decorators - Execution flow and context - Arrow functions - Function declarations and expressions |
| Testing | 7% | - Writing and modifying unit tests - Test coverage and reliability - Test effectiveness evaluation - Unit testing concepts |
| Variables, Types, and Collections | 23% | - Strings, numbers, and dates - Variable declarations and initialization - Type coercion and conversion - Arrays and collections - Truthy and falsy evaluations - Primitive and complex data types - JSON parsing and manipulation |
>> JavaScript-Developer-I Valid Test Objectives <<
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NEW QUESTION # 58
A developer is required to write a function that calculates the sum of elements in an array but is getting undefined every time the code is executed. The developer needs to find what is missing in the code below.
01 const sumFunction = arr = > {
02 return arr.reduce((result, current) = > {
03 //
04 result += current;
05 //
06 }, 10);
07 };
Which line replacement makes the code work as expected?
Answer: A
Explanation:
* In a reduce callback, you must return the new accumulator value.
* Currently:
(result, current) = > {
result += current;
// no return
}
This returns undefined each time, so the accumulator becomes undefined on the next iteration, leading to incorrect results.
Fix by returning result:
const sumFunction = arr = > {
return arr.reduce((result, current) = > {
result += current;
return result; // line 05
}, 10);
};
Option D correctly adds the return.
Options A/B/C do not fix the missing return in the reducer and therefore do not resolve the core issue.
NEW QUESTION # 59
A developer creates a simple webpage with an input field. When a user enters text in the input field and clicks the button, the actual value of the field must be displayed in the console.
Here is the HTML file content:
<input type =" text" value="Hello" name ="input">
<button type ="button" >Display </button>
The developer wrote the javascript code below:
Const button = document.querySelector('button');
button.addEvenListener('click', () => (
Const input = document.querySelector('input');
console.log(input.getAttribute('value'));
When the user clicks the button, the output is always "Hello".
What needs to be done make this code work as expected?
Answer: A
NEW QUESTION # 60
Given the following code:
01 let x = null;
02 console.log(typeof x);
What is the output of line 02?
Answer: B
Explanation:
This question focuses on the typeof operator and how JavaScript represents the type of the value null.
* Declaration on line 1:
let x = null;
Here:
* x is explicitly assigned the value null.
* In JavaScript, null is a special primitive value that represents "no value" or "empty value".
* Line 2:
console.log(typeof x);
The typeof operator returns a string indicating the type of the operand. For example:
* typeof 1 returns " number "
* typeof " hello " returns " string "
* typeof true returns " boolean "
* typeof undefined returns " undefined "
* typeof {} returns " object "
* typeof [] returns " object " (arrays are objects)
* typeof function() {} returns " function "
For null, due to an early design decision in JavaScript, the result is:
typeof null === " object "
This is a known historical quirk of the language:
* Although null is a primitive and conceptually means "no object", typeof null returns the string " object "
.
Therefore, typeof x when x is null evaluates to " object " .
So on line 2, the value printed is:
" object "
This matches option A.
The incorrect options are:
* B. " undefined " : would be typeof x if x were undefined, not null.
* C. " x " : typeof returns a string describing the type of the value, not the variable name.
* D. " null " : although intuitive, JavaScript does not return " null " for typeof null; it returns " object " instead.
Therefore, the correct answer is:
The answer: A
JavaScript knowledge / study guide reference concepts:
* typeof operator and its return values
* Primitive types in JavaScript (null, undefined, number, string, boolean, symbol, bigint)
* Historical behavior: typeof null returning " object "
* Difference between null and undefined in JavaScript
NEW QUESTION # 61
Refer to the code below:
01 let total = 10;
02 const interval = setInterval(() = > {
03 total++;
04 clearInterval(interval);
05 total++;
06 }, 0);
07 total++;
08 console.log(total);
Considering that JavaScript is single-threaded, what is the output of line 08 after the code executes?
Answer: D
Explanation:
* Synchronous execution order JavaScript executes code in a single thread, following a well-defined order:
* All synchronous code runs first, line by line.
* Asynchronous callbacks (like those scheduled with setInterval or setTimeout) are placed into the event queue and executed only after the current call stack is empty.
Let's follow the code step by step:
* Line 01:
* let total = 10;
total is initialized with the value 10.
* Line 02:
* const interval = setInterval(() = > {
* total++;
* clearInterval(interval);
* total++;
* }, 0);
setInterval schedules the callback function to run repeatedly after a delay of at least 0 milliseconds, but it does not run immediately. The callback is added to the timer queue and will be invoked after the current synchronous script finishes and the event loop gets to process timer callbacks.
At this point, interval holds the interval ID, but the callback has not executed yet.
* Line 07:
* total++;
This is still synchronous, so it runs before any scheduled callbacks.
total was 10, now it becomes 11.
* Line 08:
* console.log(total);
At this moment, the interval callback has still not run (because the event loop has not yet processed the timer queue).
So total is 11, and console.log(total); outputs 11.
Therefore, the value printed at line 08 is 11, making option A correct.
* What happens after the log (for understanding, not affecting the answer) After the main script finishes, the event loop processes the timer callback for setInterval:
Callback:
() = > {
total++; // from 11 to 12
clearInterval(interval); // cancels further executions
total++; // from 12 to 13
}
So eventually total becomes 13, but this happens after console.log(total) has already executed. Since the question asks specifically for the output at line 08, the asynchronous updates do not change that line's output.
* Why other options are incorrect
* Option B (12): This would require the callback to run before the log, which does not happen because asynchronous callbacks are queued and executed after the current stack finishes.
* Option C (10): Ignores the total++ on line 07.
* Option D (13): This is the final value after the callback finishes, but it occurs after the console.log line executes, not at the time line 08 runs.
JavaScript knowledge references (descriptive, no links):
* JavaScript is single-threaded and uses an event loop with a call stack and task queues.
* setInterval schedules callbacks to run asynchronously after a minimum delay; the callback never runs before the current synchronous code finishes.
* Synchronous statements like total++ on line 07 execute before any queued interval callback.
NEW QUESTION # 62
Refer to the HTML below:
< div id= " main " >
< ul >
< li > Leo < /li >
< li > Tony < /li >
< li > Tiger < /li >
< /ul >
< /div >
Which JavaScript statement results in changing " Leo " to " The Lion " ?
Answer: A
Explanation:
We want to select the first < li > under #main and change its content.
* document.querySelector(selector) returns the first element matching the CSS selector.
* In the DOM, the < li > elements under < ul > are children in order:
* 1st child: " Leo "
* 2nd child: " Tony "
* 3rd child: " Tiger "
li:nth-child(1) is the CSS pseudo-class that selects the first < li > inside its parent.
So:
document.querySelector( ' #main li:nth-child(1) ' ).innerHTML = ' The Lion ' ; selects the first < li > ( " Leo " ) inside #main and sets its innerHTML to " The Lion " .
Why others are incorrect:
* A. #main #Leo
* There is no element with id " Leo " . id is not set on the < li > , so the selector matches nothing.
* B. li:second-child
* There is no :second-child pseudo-class. The valid pseudo-class is :nth-child(2); and that would select " Tony " , not " Leo " .
* C. ' #main li,Leo '
* This selector means "all #main li and all elements named < Leo > ".
* There is no < Leo > tag, and querySelectorAll returns a NodeList, which does not have a single innerHTML property.
Therefore, D is the correct statement.
Study Guide Concepts:
* document.querySelector vs querySelectorAll
* CSS selectors: nth-child()
* DOM element innerHTML property
NEW QUESTION # 63
......
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