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Oracle 1z1-071 Exam Syllabus Topics:

Section	Objectives
Topic 1: Relational Database Concepts	- Data types and database objects overview - Tables, rows, columns, and relational model basics
Topic 2: Subqueries and Advanced SQL	- Single-row and multi-row subqueries - Correlated subqueries and nested queries
Topic 3: SQL Retrieval	- Joins and set operations 1. UNION, INTERSECT, MINUS 2. INNER, OUTER, CROSS joins - SELECT statements and filtering data 1. WHERE clause and conditions 2. ORDER BY and row limiting
Topic 4: SQL Functions	- Conversion and conditional functions 1. TO_CHAR, TO_NUMBER, CASE expressions - Single-row functions 1. Character, numeric, date functions
Topic 5: Data Manipulation and Schema Objects	- DML operations 1. INSERT, UPDATE, DELETE, MERGE - DDL operations 1. CREATE, ALTER, DROP tables and constraints

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Oracle Database SQL Sample Questions (Q220-Q225):

NEW QUESTION # 220
Which two statements are true about date/time functions in a session where NLS_DATE_FORMATis set to DD- MON-YYYY HH24:MI:SS? (Choose two.)

A. CURRENT_TIMESTAMPreturns the same date and time as SYSDATEwith additional details of fractional seconds.
B. CURRENT_TIMESTAMPreturns the same date as CURRENT_DATE.
C. SYSDATEcan be used in expressions only if the default date format is DD-MON-RR.
D. CURRENT_DATEreturns the current date and time as per the session time zone.
E. SYSDATEcan be queried only from the DUALtable.
F. SYSDATEand CURRENT_DATEreturn the current date and time set for the operating system of the database server.

Answer: D,E

NEW QUESTION # 221
Examine the description of the PRODUCT_INFORMATIONtable:

Which query retrieves the number of products with a null list price?
SELECT COUNT (DISTINCT list_price) FROM product_information WHERE list_price

A. IS NULL;
SELECT COUNT (list_price) FROM product_information WHERE list_price IS NULL;
B. SELECT COUNT(NVL(list_price, 0)) FROM product_information WHERE list_price IS
C. NULL;
D. SELECT COUNT (list_price) FROM product_information WHERE list_price = NULL;

Answer: C

Explanation:
Explanation/Reference: https://www.oracletutorial.com/oracle-aggregate-functions/oracle-avg/

NEW QUESTION # 222
You execute this command:

Which two are true?

A. It drops any triggers defined on the table.
B. A FLASHBACK TABLE statement can be used to retrieve the deleted data.
C. It retains the indexes defined on the table.
D. A ROLLBACK statement can be used to retrieve the deleted data.
E. It retains the integrity constraints defined on the table.
F. It always retains the space used by the removed rows.

Answer: C,E

NEW QUESTION # 223
View the exhibit and examine the data in the PROJ_TASK_DETAILS table. (Choose the best answer.)

The PROJ_TASK_DETAILS table stores information about project tasks and the relation between them.
The BASED_ON column indicates dependencies between tasks.
Some tasks do not depend on the completion of other tasks.
You must generate a report listing all task IDs, the task ID of any task upon which it depends and the name of the employee in charge of the task upon which it depends.
Which query would give the required result?

A. SELECT p.task_id, p.based_on, d.task_in_charge
FROM proj_task_details p JOIN proj_task_details d
ON (p.task_id = d.task_id);
B. SELECT p.task_id, p.based_on, d.task_in_charge
FROM proj_task_details p JOIN proj_task_details d
ON (p.based_on = d.task_id);
C. SELECT p.task_id, p.based_on, d.task_in_charge
FROM proj_task_details p FULL OUTER JOIN proj_task_details d ON (p.based_on = d.task_id);
D. SELECT p.task_id, p.based_on, d.task_in_charge
FROM proj_task_details p LEFT OUTER JOIN proj_task_details d ON (p.based_on = d.task_id);

Answer: D

NEW QUESTION # 224
Examine the description of the CUSTOMERS table:

Which two SELECT statements will return these results:
CUSTOMER_ NAME
--------------------
Mandy
Mary

A. SELECT customer_ name FROM customers WHERE customer name LIKE 'Ma%' ;
B. SELECT customer_ name FROM customers WHERE UPPER (customer name) LIKE 'MA&';
C. SELECT customer_ name FROM customers WHERE customer name LIKE 'Ma*';
D. SELECT customer_ name FROM customers WHERE customer_ name LIKE ' % a % ' ;
E. SELECT customer_ name FROM customers WHERE customer_ name='*Ma*';
F. SELECT customer_ name FROM customers WHERE customer_ name KIKE .*Ma*';
G. SELECT customer_ name FROM customers WHERE UPPER (customer_ name ) LIKE 'MA*. ;

Answer: A,D

NEW QUESTION # 225
......

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