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問題 #147
Refer to the following array:
Let arr = [1, 2, 3, 4, 5];
Which three options result in x evaluating as [1,2]?
Choose 3 answer
答案：A,D,E
問題 #148
Refer to the code below:
01 async function functionUnderTest(isOK) {
02 if (isOK) return ' OK ' ;
03 throw new Error( ' not OK ' );
04 }
Which assertion accurately tests the above code?
答案：C
解題說明：
The function:
async function functionUnderTest(isOK) {
if (isOK) return ' OK ' ;
throw new Error( ' not OK ' );
}
Behavior:
* If isOK is true:
* The function resolves (fulfills the promise) with value ' OK ' .
* If isOK is false:
* The function throws, which in an async function becomes a rejected promise with Error( ' not OK ' ).
We want an assertion that accurately tests the successful path for isOK === true.
Key points about console.assert:
* Signature: console.assert(condition, message?)
* If condition is falsy , it logs message as an assertion failure.
* If condition is truthy , nothing is logged.
We also must understand await:
* await functionUnderTest(true) will resolve to the string ' OK ' .
Now evaluate options.
Option A:
console.assert(await functionUnderTest(true), ' OK ' );
* await functionUnderTest(true) # ' OK ' (truthy).
* console.assert( ' OK ' , ' OK ' );
* Condition is ' OK ' (truthy), so assertion passes.
* The message ' OK ' is only shown if the condition is falsy, which it is not.
This correctly verifies that the promise resolved (i.e., did not reject). Among the given options, this is the only one that both:
* Uses await properly on the async function, and
* Associates the message with the expected success " OK " .
Option B:
console.assert(await (functionUnderTest(true), ' not OK ' ));
* Inside the parentheses, the comma operator (a, b) evaluates a, discards it, and returns b.
* So (functionUnderTest(true), ' not OK ' ):
* Calls functionUnderTest(true) (returns a promise, but its result is discarded),
* The expression evaluates to the string ' not OK ' .
* Then await ' not OK ' just resolves to ' not OK ' immediately (not a promise).
* console.assert( ' not OK ' );
* Condition is ' not OK ' (truthy), so the assertion passes regardless of what functionUnderTest actually does.
* This does not meaningfully test the function and is misleading.
Option C:
console.assert(functionUnderTest(true), ' OK ' );
* functionUnderTest(true) returns a Promise , not the string ' OK ' directly.
* A Promise object is always truthy.
* So console.assert(promise, ' OK ' ) will pass, even if the promise later rejects.
* Also, there is no await, so we are not actually waiting for the async result.
* This is not a correct way to assert on an async function's resolved value.
Option D:
console.assert(await functionUnderTest(true), ' not OK ' );
* await functionUnderTest(true) still resolves to ' OK ' (truthy).
* console.assert( ' OK ' , ' not OK ' ); passes.
* However, the message ' not OK ' is the opposite of what we expect for the success case and is only used when the condition fails.
* This makes the assertion logically inconsistent with the function behavior (it would show " not OK " if the assertion failed).
Therefore, the only assertion that:
* Properly waits on the async function, and
* Has expectation text that matches the successful behavior ( ' OK ' )
is:
The answer: A
Study Guide / Concept References (no links):
* async and await behavior in JavaScript
* Promises resolving vs rejecting in async functions
* console.assert(condition, message) usage
* Truthy and falsy values in JavaScript
* Comma operator (a, b) semantics
問題 #149
Given the code below:
What is logged to the console?
答案：B
問題 #150
Refer to the code below:
console.log(''start);
Promise.resolve('Success') .then(function(value){
console.log('Success');
});
console.log('End');
What is the output after the code executes successfully?
答案：D
問題 #151
Refer to the code below:
01 let total = 10;
02 const interval = setInterval(() = > {
03 total++;
04 clearInterval(interval);
05 total++;
06 }, 0);
07 total++;
08 console.log(total);
Considering that JavaScript is single-threaded, what is the output of line 08 after the code executes?
答案：A
解題說明：
* Synchronous execution order JavaScript executes code in a single thread, following a well-defined order:
* All synchronous code runs first, line by line.
* Asynchronous callbacks (like those scheduled with setInterval or setTimeout) are placed into the event queue and executed only after the current call stack is empty.
Let's follow the code step by step:
* Line 01:
* let total = 10;
total is initialized with the value 10.
* Line 02:
* const interval = setInterval(() = > {
* total++;
* clearInterval(interval);
* total++;
* }, 0);
setInterval schedules the callback function to run repeatedly after a delay of at least 0 milliseconds, but it does not run immediately. The callback is added to the timer queue and will be invoked after the current synchronous script finishes and the event loop gets to process timer callbacks.
At this point, interval holds the interval ID, but the callback has not executed yet.
* Line 07:
* total++;
This is still synchronous, so it runs before any scheduled callbacks.
total was 10, now it becomes 11.
* Line 08:
* console.log(total);
At this moment, the interval callback has still not run (because the event loop has not yet processed the timer queue).
So total is 11, and console.log(total); outputs 11.
Therefore, the value printed at line 08 is 11, making option A correct.
* What happens after the log (for understanding, not affecting the answer) After the main script finishes, the event loop processes the timer callback for setInterval:
Callback:
() = > {
total++; // from 11 to 12
clearInterval(interval); // cancels further executions
total++; // from 12 to 13
}
So eventually total becomes 13, but this happens after console.log(total) has already executed. Since the question asks specifically for the output at line 08, the asynchronous updates do not change that line's output.
* Why other options are incorrect
* Option B (12): This would require the callback to run before the log, which does not happen because asynchronous callbacks are queued and executed after the current stack finishes.
* Option C (10): Ignores the total++ on line 07.
* Option D (13): This is the final value after the callback finishes, but it occurs after the console.log line executes, not at the time line 08 runs.
JavaScript knowledge references (descriptive, no links):
* JavaScript is single-threaded and uses an event loop with a call stack and task queues.
* setInterval schedules callbacks to run asynchronously after a minimum delay; the callback never runs before the current synchronous code finishes.
* Synchronous statements like total++ on line 07 execute before any queued interval callback.
問題 #152
......
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