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| Section | Weight | Objectives |
|---|---|---|
| Data Handling and Logic | 15% | - Error handling
|
| Swift Programming Fundamentals | 30% | - Basic types and operators
|
| SwiftUI Basics | 25% | - State management
|
| App Design and Best Practices | 15% | - Code organization
|
| Development Environment | 15% | - Debugging techniques
|
>> Sample Apple App-Development-with-Swift-Certified-User Questions <<
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NEW QUESTION # 23
When you press ' Show Button ' on your app. a modal View appears.
Complete the code by selecting the correct option from each drop-down list.
Note: You will receive partial credit for each correct answer.
Answer:
Explanation:
Explanation:
This question belongs to View Building with SwiftUI , specifically the domain on creating a multi-view app with navigation stacks, links, and sheets .
To present a modal view in SwiftUI when a Boolean state changes, the correct modifier is .sheet . The matching sheet API for a Boolean binding is:
sheet(isPresented: $showInfo) {
// modal content
}
So the first blank must be .sheet , and the second blank must be (isPresented: .
The logic works like this:
* @State stores the local Boolean that controls presentation.
* Pressing the button calls showInfo.toggle(), changing the value from false to true.
* When that Boolean becomes true, the .sheet(isPresented:) modifier presents the modal view.
* When the modal is dismissed, SwiftUI updates the Boolean back as needed.
There is also a typing issue in the screenshot: the state variable appears as ShowInfo, while the button and binding use showInfo. Swift is case-sensitive, so those names must match. The corrected code should use the same identifier consistently, such as:
@State var showInfo = false
Therefore, the correct dropdown selections are:
sheet
(isPresented:
NEW QUESTION # 24
Review the code snippet.
What will print after the final line of code is executed?
Answer:
Explanation:
Answer the question by typing in the box.
2
Explanation:
This question belongs to Swift Programming Language , specifically the objective on variable scope and shadowing .
The code first declares:
let even = 2
This creates a constant named even in the outer scope with the value 2.
Inside the for loop, the code declares another constant with the same name:
let even = num * 2
This inner even exists only inside the loop body. It shadows the outer even, which means that within the loop, the name even refers to the loop's local constant, not the original one. However, that inner constant goes out of scope at the end of each loop iteration.
After the loop finishes, the inner even no longer exists. So when the final line runs:
print(even)
Swift uses the original outer constant, which is still 2.
So the output is:
2
This question tests two important Swift concepts:
* Scope : where a variable or constant can be accessed
* Shadowing : when a local declaration temporarily hides another declaration with the same name Therefore, the correct answer is 2 .
NEW QUESTION # 25
For each statement about Navigation in SwiftUI. select True or False.
Answer:
Explanation:
Explanation:
* You can treat a NavigationLink like a button, and run some Swift code when it is pressed. - False
* NavigationSplitView can be used to do navigation differently on different device sizes. - True
* You can put a header on your present View in a NavigationStack using .navigationTitle. - True
* If you have a NavigationLink that goes to another View with a NavigationLink, you need to declare a NavigationStack at each level. - False This question belongs to View Building with SwiftUI , specifically the objective on creating a multi-view app with navigation stacks, links, and sheets . Statement 1 is False because NavigationLink is primarily a navigation control that pushes or presents a destination in a navigation container; Apple documents it as creating a navigation link that presents a destination, not as a general-purpose action control like Button.
Statement 2 is True because NavigationSplitView is designed for adaptive navigation and can present navigation in different ways depending on platform and available space. Apple documents NavigationSplitView as a container for navigation across multiple columns, and this adaptive behavior is exactly why it is used differently across device sizes.
Statement 3 is True because .navigationTitle(...) sets the navigation title for a view shown inside a navigation container. Apple explicitly describes a view's navigation title as something used to visually display the current navigation state of an interface.
Statement 4 is False because you do not need a separate NavigationStack at every level. Apple describes NavigationStack as the container that manages a stack of views, and NavigationLink pushes additional destinations onto that stack. Nested destinations can keep navigating within the same stack.
NEW QUESTION # 26
Review the code.
struct ContentView: View {
let fruits = [ " Apple " , " Banana " , " Kiwi " ]
var body: some View {
List(fruits, id: \.self) { fruit in
Text(fruit)
.font(.headline)
.padding()
}
}
}
Which of the following statements is true about the code?
Answer: C
Explanation:
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question belongs to View Building with SwiftUI , especially the domain covering List Views to iterate through collections . In the code, fruits is an array of strings, and the List initializer is being used to create one row for each item in that collection. Apple's SwiftUI documentation explains that List can present rows from a collection of data, and when the data elements are not supplied through a type that already provides identity, you can provide an id key path so SwiftUI can uniquely identify each row. Here, id: \.self tells SwiftUI to use each string value itself as the identifier.
Option D is therefore the correct statement because the List is clearly rendering the contents of the fruits array as separate rows, and each row shows a Text(fruit) view. Apple's app development tutorials describe List as a container view that displays rows of data arranged in a single scrollable column, which matches exactly what this code is doing.
Option A is false because for an array of String values in this form, id: \.self is used to identify each row.
Option B is false because the key path is not related to .font(.headline) or .padding(); those are standard view modifiers, not dynamic property extraction in this example. Option C is false because Swift key-path syntax uses a backslash, as in \.self, not /self. Apple's KeyPath documentation shows that Swift key paths use the backslash form.
NEW QUESTION # 27
Review the code snippet.
The code snippet does not compile.
Which two actions will fix the errors? (Choose 2.)
Answer: C,E
Explanation:
This question belongs to Swift Programming Language , especially the domains covering basic Swift types
, operators , and constants versus variables .
There are two compile problems in the snippet. First, unitPrice and shipping are inferred as Double, while quantity is inferred as Int. In Swift, arithmetic operands must have compatible types; Swift does not automatically mix Int and Double in one arithmetic expression. So unitPrice * quantity fails unless quantity is changed to Double or explicitly converted. That makes A a correct fix.
Second, the line totalCost += ... uses the compound assignment operator +=, which stores a new value back into the left-hand side. Swift requires the left-hand side of += to be mutable, so totalCost must be declared with var, not let. That makes D the second correct fix.
The other choices do not solve the actual compile issues. B is unnecessary because totalCost is already explicitly declared as Double, so 0 is valid there. C would still leave shipping as Double, so the mixed-type arithmetic problem remains. E is irrelevant because shipping is never reassigned. Therefore, the two correct answers are A and D
NEW QUESTION # 28
......
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