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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Restricting and Sorting Data | 15% | - Operator precedence - WHERE clause and filtering conditions - ORDER BY clause and sorting rules - Substitution variables, DEFINE and VERIFY commands |
| Topic 2: Manipulating Data and Managing Transactions | - INSERT, UPDATE, DELETE, MERGE statements - Transaction control: COMMIT, ROLLBACK, SAVEPOINT - Multi-table inserts | |
| Topic 3: Using Data Dictionary Views | - Retrieve metadata and object information | |
| Topic 4: Managing Tables and Constraints | - Constraints: primary key, foreign key, unique, check, not null - Temporary and external tables - Data types, creating/altering/dropping tables | |
| Topic 5: Conversion Functions and Conditional Expressions | 10% | - NVL, NULLIF, COALESCE and CASE expressions - TO_CHAR, TO_NUMBER, TO_DATE functions - Implicit and explicit data type conversion |
| Topic 6: Controlling User Access | - Roles, granting and revoking privileges - System and object privileges | |
| Topic 7: Displaying Data from Multiple Tables | 15% | - Cartesian products - Equijoins and non-equijoins - Self-joins and outer joins |
| Topic 8: Managing Indexes, Synonyms and Sequences | - Create and use sequences - Create and maintain indexes - Create and use synonyms | |
| Topic 9: Using Subqueries to Solve Queries | - Single-row and multi-row subqueries - Correlated subqueries for update/delete | |
| Topic 10: Working with Time Zones and Date/Time Data | - TIMESTAMP, INTERVAL data types - Time zone conversion functions | |
| Topic 11: Using Single-Row Functions to Customize Output | 20% | - Character, number, and date functions - Nested functions usage |
| Topic 12: Retrieving Data Using SQL SELECT Statement | 20% | - Column aliases, concatenation, literals and DISTINCT - Arithmetic operations and NULL handling - SELECT statement syntax and usage |
| Topic 13: Aggregating Data Using Group Functions | 10% | - GROUP BY and HAVING clauses - Handling NULLs in group functions - SUM, AVG, COUNT, MAX, MIN functions |
| Topic 14: Using SET Operators | - Ordering results with set operations - UNION, UNION ALL, INTERSECT, MINUS operators | |
| Topic 15: Managing Views | - Updatable and read-only views - Create, modify and drop views | |
| Topic 16: Relational Database Concepts | 10% | - Relationship between database and SQL - ERD and SQL statement mapping - Theoretical and physical aspects of relational databases |
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NEW QUESTION # 226
Examine the structure of the SHIPMENTS table:
You want to generate a report that displays the PO_ID and the penalty amount to be paid if the SHIPMENT_DATE is later than one month from the PO_DATE. The penalty is $20 per day.
Evaluate the following two queries:
Which statement is true regarding the above commands?
Answer: A
NEW QUESTION # 227
Examine this Statement which returns the name of each employee and their manager, SELECT e.last name AS emp,,m.last_name AS mgr FROM employees e JOIN managers m ON e.manager_ id = m. employee_ id ORDER BY emp; You want to extend the query to include employees with no manager. What must you add before JOIN to do this?
Answer: D
Explanation:
To include employees with no manager in the query results, a LEFT OUTER JOIN should be used. This type of join returns all records from the left table (employees), and the matched records from the right table (managers). The result is NULL from the right side if there is no match.
Here's the modified query:
SELECT e.last_name AS emp, m.last_name AS mgr FROM employees e LEFT OUTER JOIN managers m ON e.manager_id = m.employee_id ORDER BY emp; This ensures that even if an employee does not have a manager (i.e., e.manager_id is NULL or there is no corresponding m.employee_id), that employee will still be included in the results.
NEW QUESTION # 228
Which three are true about granting object privileges on tables, views, and sequences?
Answer: B,C,F
NEW QUESTION # 229
Which is the default column or columns for sorting output from compound queries using SET operators such as INTERSECT in a SQL statement?
Answer: A
Explanation:
For the sorting of output in compound queries (INTERSECT, UNION, etc.):
D . The first column in the first SELECT of the compound query: By default, Oracle does not automatically sort the results of SET operations unless an ORDER BY clause is explicitly stated. However, if an ORDER BY is implied or specified without explicit columns, the default sorting would logically involve the first column specified in the first SELECT statement of the compound query.
NEW QUESTION # 230
You need to display the first names of all customers from the CUSTOMERS table that contain the character 'e' and have the character 'a' in the second last position.
Which query would give the required output?
Answer: D
NEW QUESTION # 231
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