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Apple App-Development-with-Swift-Certified-User Exam Syllabus Topics:

SectionObjectives
Swift Programming Language- Manage data using collection types
  • 1. Dictionaries
  • 2. Arrays
- Demonstrate the use of Optional types
  • 1. Apply Optional binding and Optional chaining (including but not limited to if let, guard let)
  • 2. Demonstrate how to unwrap Optionals safely
- Demonstrate proper use of structs, classes
  • 1. Differentiate between various initializers
  • 2. Define and use property observers
  • 3. Differentiate between structures and classes
  • 4. Define and use properties and methods
- Evaluate variable scope and shadowing
- Declare and use basic Swift types
  • 1. Demonstrate when to use constants and variables
  • 2. Describe and use data types and operators
  • 3. Interpret and use basic types
  • 4. Demonstrate the use of type casting in both safe and unsafe ways
- Use functions
  • 1. Create and call a function
  • 2. Organize and structure code
  • 3. Demonstrate how to use a function's return value
  • 4. Customize internal, external, and anonymous naming of parameters in functions
  • 5. Implement default parameter values
- Know how and when to apply control flow and loops
  • 1. Use Guard
  • 2. Use logical operators
  • 3. Use range operators
View Building with SwiftUI- Create multiple Views to implement app logic
- Use @State, @Binding, @Environment, and/or Observable to share data between Views
- Position and/or layout a single SwiftUI View with standard Views and modifiers
- Extract Subviews to simplify the structure of an overlarge View
- Use List Views to iterate through collections
- Create a multi-view app with navigation Stacks, Links, and/or Sheets
Xcode Developer Tools- Use debugging techniques including, but not limited to, breakpoints, watchpoints, and logging to resolve errors
  • 1. Set breakpoints and step through code line by line
- Demonstrate how to build and run an app
  • 1. on the iOS simulator
  • 2. on the iOS device
- Identify and use the features of the Xcode interface
  • 1. Create and modify views with Interface Builder
  • 2. Demonstrate how to access documentation and help
  • 3. Navigate Xcode

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最新的 Apple App Development with Swift App-Development-with-Swift-Certified-User 免費考試真題 (Q22-Q27):

問題 #22
For each statement about Navigation in SwiftUI. select True or False.

答案:

解題說明:

Explanation:
* You can treat a NavigationLink like a button, and run some Swift code when it is pressed. - False
* NavigationSplitView can be used to do navigation differently on different device sizes. - True
* You can put a header on your present View in a NavigationStack using .navigationTitle. - True
* If you have a NavigationLink that goes to another View with a NavigationLink, you need to declare a NavigationStack at each level. - False This question belongs to View Building with SwiftUI , specifically the objective on creating a multi-view app with navigation stacks, links, and sheets . Statement 1 is False because NavigationLink is primarily a navigation control that pushes or presents a destination in a navigation container; Apple documents it as creating a navigation link that presents a destination, not as a general-purpose action control like Button.
Statement 2 is True because NavigationSplitView is designed for adaptive navigation and can present navigation in different ways depending on platform and available space. Apple documents NavigationSplitView as a container for navigation across multiple columns, and this adaptive behavior is exactly why it is used differently across device sizes.
Statement 3 is True because .navigationTitle(...) sets the navigation title for a view shown inside a navigation container. Apple explicitly describes a view's navigation title as something used to visually display the current navigation state of an interface.
Statement 4 is False because you do not need a separate NavigationStack at every level. Apple describes NavigationStack as the container that manages a stack of views, and NavigationLink pushes additional destinations onto that stack. Nested destinations can keep navigating within the same stack.


問題 #23
Which code correctly creates a size 300 rectangular Image View with rounded corners that displays the entire image, regardless of size?

答案:D

解題說明:
This question belongs to View Building with SwiftUI , specifically the objective on positioning and laying out a single SwiftUI view with standard views and modifiers.
The correct answer is D because it uses the right combination of SwiftUI image modifiers for all three requirements:
* the image is made resizable with .resizable()
* it is given rounded corners with .clipShape(RoundedRectangle(cornerRadius: 50))
* it displays the entire image with .aspectRatio(contentMode: .fit)
* it is sized with .frame(width: 300)
The key part is .aspectRatio(contentMode: .fit) . In SwiftUI, .fit scales the image so the whole image remains visible inside the available frame. That matches the requirement "displays the entire image, regardless of size." By contrast, .fill may crop part of the image, so options using .fill do not satisfy the requirement.
Why the others are wrong:
* Option A uses .fill, so the full image may not remain visible.
* Option B uses invalid modifiers such as .sizablc() and .size(width: 300), and also uses Rectangle (cornerRadius: 50), which is not the correct rounded-rectangle shape syntax.
* Option C also uses invalid syntax and .fill, which can crop the image.
* Option D uses valid SwiftUI syntax and the correct content mode.
So the correct choice is D , because it is the only option that correctly creates a 300-width image with rounded corners while ensuring the entire image is shown.


問題 #24
Review the code snippet.

What value does the code output?

答案:

解題說明:
Answer the question by typing in the box.
2
Explanation:
This question belongs to Swift Programming Language , specifically the objectives covering functions , control flow , and default parameter values . The function is declared as func getAgeCategory(_ age: Int =
20) - > Int, which means if no argument is supplied, Swift uses the default value 20. Apple's Swift documentation explains that you can define a default value for any parameter, and that value is used when the caller omits that argument. Since the code calls getAgeCategory() with no parameter, the function executes using age = 20.
The conditional logic is then evaluated in order:
* if age > 64 # false, because 20 is not greater than 64
* else if age > 19 # true, because 20 is greater than 19
* so the function returns 2
Because Swift's if / else if control flow stops at the first true condition, the later checks are never reached once age > 19 succeeds. Apple describes Swift as supporting standard control flow including conditional branching, and this example is a direct use of that branching behavior.
Therefore, print(getAgeCategory()) outputs 2 , which corresponds to option B .


問題 #25
You are creating or updating human resource records for your employees. For each identifier, select whether it is a Constant or a Variable Note: You will receive partial credit for each correct answer.

答案:

解題說明:

Explanation:
* age - Variable
* birthDate - Constant
* socialSecurityNumber - Constant
* salary - Variable
* currentDepartment - Variable
This question belongs to Swift Programming Language , specifically the objective on demonstrating when to use constants and variables . In Swift, a constant is declared with let and is used for values that should not change after they are set. A variable is declared with var and is used for values that may change over time.
Birth date is a constant because a person's date of birth does not change. Social security number is also a constant because it is intended to be a fixed identifier for that employee record. By contrast, age is a variable because it changes over time. Salary is a variable because compensation can be adjusted. Current department is also a variable because an employee may transfer to another department.
This matches Swift best practice: use let for fixed data and var for mutable data. So in a human resources record, identifiers that are permanent should be constants, while values that can change during employment should be variables.


問題 #26
Review the code snippet and identify what happens when the program is executed.

答案:A

解題說明:
This question belongs to Swift Programming Language , specifically the objectives covering arrays , loops
, and range operators . The array has 6 elements, so menuItems.count is 6. The loop uses the half-open range operator:
for index in 1.. < (menuItems.count - 1)
That becomes:
for index in 1.. < 5
In Swift, the half-open range operator a.. < b includes the lower bound but does not include the upper bound.
So this loop runs with index values 1, 2, 3, 4, not 0 and not 5.
Array subscripting uses those indexes to print:
* menuItems[1] # " Burger "
* menuItems[2] # " Chicken "
* menuItems[3] # " Pasta "
* menuItems[4] # " Salad "
That means " Pizza " at index 0 is skipped, and " Steak " at index 5 is also skipped. Swift arrays use zero- based indexing, and count returns the number of elements in the array.
Therefore, the program prints only " Burger " , " Chicken " , " Pasta " , and " Salad " , so the correct answer is A .


問題 #27
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