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NEW QUESTION # 80
A developer wrote the following code:
01 let x = object.value;
02
03 try {
04 handleObjectValue(x);
05 } catch(error) {
06 handleError(error);
07 }
The developer has a getNextValue function to execute after handleObjectValue(), but does not want to execute getNextValue() if an error occurs. How can the developer change the code to ensure this behavior?
Answer: B
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
Requirement:
getNextValue() should run only if handleObjectValue(x) does not throw an error.
If an error occurs, handleError(error) should run, and getNextValue() should be skipped.
Option B:
try {
handleObjectValue(x);
getNextValue();
} catch (error) {
handleError(error);
}
Behavior:
If handleObjectValue(x) succeeds (no error):
Execution continues to getNextValue();.
If handleObjectValue(x) throws:
Control jumps directly to catch, getNextValue() is skipped.
handleError(error); is called.
This matches the requirement perfectly.
Why others are incorrect:
A: } then { is invalid JavaScript syntax.
C:
try {
handleObjectValue(x);
} catch (error) {
handleError(error);
}
getNextValue();
getNextValue() is called after the try...catch regardless of whether an error occurred. Not acceptable.
D: finally always runs:
try {
handleObjectValue(x);
} catch (error) {
handleError(error);
} finally {
getNextValue();
}
getNextValue() will execute in both success and error cases.
Therefore, the correct approach is B.
Concepts: try/catch control flow, finally semantics, placing code inside vs outside try/catch blocks.
________________________________________
NEW QUESTION # 81
A developer has a fizzbuzz function that, when passed in a number, returns the following:
'fizz' if the number is divisible by 3.
'buzz' if the number is divisible by 5.
'fizzbuzz' if the number is divisible by both 3 and 5.
Empty string '' if the number is divisible by neither 3 nor 5.
Which two test cases properly test scenarios for the fizzbuzz function?
Answer: A,C
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
First, recall the fizzbuzz rules:
If n divisible by 3 and not by 5 → return 'fizz'.
If n divisible by 5 and not by 3 → return 'buzz'.
If n divisible by both 3 and 5 → return 'fizzbuzz'.
Otherwise → return '' (empty string).
Evaluate each test:
Option A:
let res = fizzbuzz(true);
console.assert(res === '');
In JavaScript, when using arithmetic operations with true, it is coerced to the number 1. A typical implementation of fizzbuzz would treat the argument as a number and compute:
true % 3 → 1 % 3 → 1
true % 5 → 1 % 5 → 1
So true is effectively treated as 1, which is divisible by neither 3 nor 5. The function should return ''. The assertion res === '' will pass.
This test covers the scenario "neither divisible by 3 nor 5".
Option B:
let res = fizzbuzz(3);
console.assert(res === '');
3 is divisible by 3 but not by 5.
According to fizzbuzz rules, fizzbuzz(3) should return 'fizz'.
This test expects '', so it is incorrect; the assertion would fail in a correct implementation.
Option C:
let res = fizzbuzz(5);
console.assert(res === 'fizz');
5 is divisible by 5 but not by 3.
According to fizzbuzz rules, fizzbuzz(5) should return 'buzz'.
This test expects 'fizz', so it is incorrect.
Option D:
let res = fizzbuzz(15);
console.assert(res === 'fizzbuzz');
15 is divisible by both 3 and 5.
According to fizzbuzz rules, fizzbuzz(15) should return 'fizzbuzz'.
This assertion correctly matches the expected result, so it is a proper test case.
Thus, the two test cases that correctly test valid fizzbuzz behavior are:
Study Guide / Concept Reference (no links):
Modulo operator (%) for divisibility checks
Truthy/number coercion of boolean true in arithmetic (Number(true) === 1) Designing unit tests with console.assert Typical fizzbuzz logic structure and expected outputs
________________________________________
NEW QUESTION # 82
Value of:
true + 3 + '100' + null
Answer: A
Explanation:
The correct answer is A.
JavaScript evaluates the expression from left to right:
true + 3 + '100' + null
Step 1:
true + 3
In numeric addition, true is converted to:
1
So:
true + 3
becomes:
1 + 3
Result:
4
Step 2:
4 + '100'
Because one operand is a string, JavaScript performs string concatenation instead of numeric addition.
So:
4 + '100'
becomes:
"4100"
Step 3:
"4100" + null
Again, because one operand is already a string, JavaScript converts null into the string:
"null"
So the final result is:
"4100null"
Execution summary:
true + 3 + '100' + null
// 1 + 3 + '100' + null
// 4 + '100' + null
// "4100" + null
// "4100null"
Therefore, the verified answer is A.
NEW QUESTION # 83
Given the code below:
const delay = async delay =>{
return new Promise((resolve,reject)=>{
console.log(1);
setTimeout(resolve,deleay);
});
};
const callDelay =async ()=>{
console.log(2);
const yup = await delay(1000);
console.log(3);
}
console.log(4);
callDelay();
console.log(5);
What is logged to the console?
Answer:
Explanation:
4 2 1 5 3
NEW QUESTION # 84
Given the JavaScript below:
function onLoad() {
console.log("Page has loaded!");
}
Where can the developer see the log statement after loading the page in the browser?
Answer: D
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
console.log() in browser-side JavaScript writes output to the browser's JavaScript console, which is available in the browser's Developer Tools.
In a typical browser (Chrome, Firefox, Edge, etc.), you open DevTools and go to the Console tab.
Any console.log("Page has loaded!"); executed in page JavaScript will appear there.
Why A is correct:
The function onLoad is a client-side function (runs in the browser).
When it executes, the console.log call goes to the browser's JavaScript console, not the server.
Why the others are incorrect:
B . On the terminal console running the web server
That console shows logs from the server-side runtime (e.g., Node.js logs).
This code is clearly browser-side JavaScript (no Node.js or server context shown).
Therefore, the output does not appear in the terminal.
C . In the browser performance tools log
Performance tools (Timeline, Performance tab, etc.) show metrics about rendering, CPU time, network, etc., not generic console.log messages.
console.log messages appear in the Console tab, not in performance logs.
D . On the webpage console log
There is no built-in concept of a "webpage console log" UI rendered on the page itself by default.
Unless you explicitly code something to display logs in the DOM, console.log output is not visible on the page, only in Developer Tools.
Therefore, the correct place to see that log is:
JavaScript knowledge / Study Guide references (concept names only, no links):
Browser Developer Tools - Console tab
console.log() in client-side JavaScript
Difference between client-side logs and server-side logs
________________________________________
NEW QUESTION # 85
......
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