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| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I |
| Exam Number: | JS-Dev-001 |
| Exam Duration: | 105 minutes |
| Real Exam Qty: | 60 |
| Related Certifications: | Salesforce Certified Platform Developer I Salesforce Certified JavaScript Developer I Salesforce Certified Platform App Builder |
| Exam Price: | USD 200 (may vary by region/tax) |
| Available Languages: | English |
| Certificate Validity Period: | 1 year (maintenance required via Salesforce certification maintenance modules) |
| Passing Score: | 65% |
| Exam Format: | Multiple Select, Multiple Choice |
| Recommended Training: | Salesforce Trailhead JavaScript Developer I Prep Salesforce Developer Learning Paths |
| Exam Registration: | Salesforce Credentials Page Salesforce Certification Registration (Webassessor) |
| Sample Questions: | Salesforce JavaScript-Developer-I Sample Questions |
| Exam Way: | Online proctored or onsite testing via Kryterion Webassessor |
| Pre Condition: | No formal prerequisites, but familiarity with JavaScript and Salesforce platform development is strongly recommended. |
| Official Syllabus URL: | https://trailhead.salesforce.com/credentials/javascriptdeveloper1 |
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Salesforce Certified JavaScript Developer I exam is designed for developers who have a strong understanding of JavaScript and its application within the Salesforce platform. Salesforce Certified JavaScript Developer (JS-Dev-101) certification is ideal for professionals who want to demonstrate their skills in building custom applications using JavaScript within the Salesforce environment. Salesforce Certified JavaScript Developer (JS-Dev-101) certification exam is intended for individuals who have experience in developing custom applications on the Salesforce platform, including Apex and Visualforce pages.
NEW QUESTION # 69
A developer has an is Dog function that takes one argument cat. They want to schedule the function to run every minute.
What is the correct syntax for scheduling this function?
Answer: A
NEW QUESTION # 70
Which two console logs out NaN?
Choose 2 answers
Answer: A,D
NEW QUESTION # 71
Refer to the following code:
What is the output of line 11?
Answer: B
NEW QUESTION # 72
Given the following code:
Let x = ('15' +10) +2;
What is the value of x?
Answer: B
NEW QUESTION # 73
Refer to the code below:
01 async function functionUnderTest(isOK) {
02 if (isOK) return ' OK ' ;
03 throw new Error( ' not OK ' );
04 }
Which assertion accurately tests the above code?
Answer: B
Explanation:
The function:
async function functionUnderTest(isOK) {
if (isOK) return ' OK ' ;
throw new Error( ' not OK ' );
}
Behavior:
* If isOK is true:
* The function resolves (fulfills the promise) with value ' OK ' .
* If isOK is false:
* The function throws, which in an async function becomes a rejected promise with Error( ' not OK ' ).
We want an assertion that accurately tests the successful path for isOK === true.
Key points about console.assert:
* Signature: console.assert(condition, message?)
* If condition is falsy , it logs message as an assertion failure.
* If condition is truthy , nothing is logged.
We also must understand await:
* await functionUnderTest(true) will resolve to the string ' OK ' .
Now evaluate options.
Option A:
console.assert(await functionUnderTest(true), ' OK ' );
* await functionUnderTest(true) # ' OK ' (truthy).
* console.assert( ' OK ' , ' OK ' );
* Condition is ' OK ' (truthy), so assertion passes.
* The message ' OK ' is only shown if the condition is falsy, which it is not.
This correctly verifies that the promise resolved (i.e., did not reject). Among the given options, this is the only one that both:
* Uses await properly on the async function, and
* Associates the message with the expected success " OK " .
Option B:
console.assert(await (functionUnderTest(true), ' not OK ' ));
* Inside the parentheses, the comma operator (a, b) evaluates a, discards it, and returns b.
* So (functionUnderTest(true), ' not OK ' ):
* Calls functionUnderTest(true) (returns a promise, but its result is discarded),
* The expression evaluates to the string ' not OK ' .
* Then await ' not OK ' just resolves to ' not OK ' immediately (not a promise).
* console.assert( ' not OK ' );
* Condition is ' not OK ' (truthy), so the assertion passes regardless of what functionUnderTest actually does.
* This does not meaningfully test the function and is misleading.
Option C:
console.assert(functionUnderTest(true), ' OK ' );
* functionUnderTest(true) returns a Promise , not the string ' OK ' directly.
* A Promise object is always truthy.
* So console.assert(promise, ' OK ' ) will pass, even if the promise later rejects.
* Also, there is no await, so we are not actually waiting for the async result.
* This is not a correct way to assert on an async function's resolved value.
Option D:
console.assert(await functionUnderTest(true), ' not OK ' );
* await functionUnderTest(true) still resolves to ' OK ' (truthy).
* console.assert( ' OK ' , ' not OK ' ); passes.
* However, the message ' not OK ' is the opposite of what we expect for the success case and is only used when the condition fails.
* This makes the assertion logically inconsistent with the function behavior (it would show " not OK " if the assertion failed).
Therefore, the only assertion that:
* Properly waits on the async function, and
* Has expectation text that matches the successful behavior ( ' OK ' )
is:
The answer: A
Study Guide / Concept References (no links):
* async and await behavior in JavaScript
* Promises resolving vs rejecting in async functions
* console.assert(condition, message) usage
* Truthy and falsy values in JavaScript
* Comma operator (a, b) semantics
NEW QUESTION # 74
......
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