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| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I - Multiple Choice Exam (JS-Dev-101) |
| Exam Number: | JS-Dev-101 |
| Exam Format: | Multiple Select Questions, Multiple Choice Questions |
| Certificate Validity Period: | 1 year (maintenance required annually in Salesforce certification program) |
| Real Exam Qty: | 60 (multiple choice) |
| Exam Price: | $200 USD |
| Available Languages: | English |
| Passing Score: | 65% |
| Related Certifications: | Salesforce Platform Developer I Salesforce Platform Developer II |
| Exam Duration: | 105 minutes |
| Recommended Training: | Salesforce Trailhead - JavaScript Developer I MDN Web Docs - JavaScript Guide |
| Exam Registration: | Kryterion Webassessor (Exam Delivery) Salesforce Certification Registration |
| Sample Questions: | Salesforce JS-Dev-101 Sample Questions |
| Exam Way: | Online proctored exam via Salesforce authorized testing platform (e.g., Webassessor) |
| Pre Condition: | No formal prerequisites, but familiarity with JavaScript and web development is recommended. |
| Official Syllabus URL: | https://trailhead.salesforce.com/credentials/javascriptdeveloper |
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NEW QUESTION # 51
Refer to the following code:
01 let obj = {
02 foo: 1,
03 bar: 2
04 }
05 let output = []
06
07 for (let something of obj) {
08 output.push(something);
09 }
10
11 console.log(output);
What is the value of output on line 11?
Answer: A
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
The key line is:
for (let something of obj) {
In JavaScript:
for...of is used to iterate over iterable objects, such as:
Arrays
Strings
Maps
Sets
Other objects that implement a [Symbol.iterator] method.
Plain JavaScript objects created with object literal {} are not iterable by default. They do not have [Symbol.iterator], so using for...of directly on them causes a runtime error.
Specifically:
for (let something of obj) { ... }
will throw a TypeError similar to:
obj is not iterable
Therefore, the loop body never executes, and console.log(output); is never reached without an error.
Why other options are incorrect:
B . [1, 2]
To get [1, 2], you could use Object.values(obj) and iterate that array.
But here, for...of obj never yields values because it throws an error.
C . ["foo", "bar"]
To get property names, you could use Object.keys(obj) with for...of.
Again, the code does not do that; it incorrectly tries to iterate the object directly.
D . ["foo:1", "bar:2"]
You would need both keys and values, combining them manually.
The given code does not implement such logic and fails before pushing anything into output.
Hence, the correct answer is:
Answe r: A
Study Guide / Concept Reference (no links):
Difference between for...of and for...in
Iterables in JavaScript and [Symbol.iterator]
Plain objects {} are not iterable by default
Correct patterns to iterate object keys/values (Object.keys, Object.values, Object.entries)
________________________________________
NEW QUESTION # 52
Refer the code below.
x=3.14;
function myfunction() {
"use strict";
y=x;
}
z=x;
myFunction();
Answer:
Explanation:
See the Answer below in explanation
NEW QUESTION # 53
A developer uses a parsed JSON string to work with user information as in the block below:
01 const userInformation = {
02 "id": "user-01",
03 "email": "user01@universalcontainers.demo",
04 "age": 25
05 };
Which two options access the email attribute in the object?
Answer: B,D
Explanation:
userInformation is a plain JavaScript object:
{
id: "user-01",
email: "user01@universalcontainers.demo",
age: 25
}
You can access object properties in two standard ways:
Dot notation: object.propertyName
Bracket notation: object['propertyName']
Apply to each option:
A . userInformation.email
Correct dot notation; accesses "user01@universalcontainers.demo".
B . userInformation.get("email")
.get() is a method on Map instances, not on plain objects.
A regular object does not have a .get method; this would be TypeError.
C . userInformation["email"]
Correct bracket notation; string "email" is used as the property key.
Returns "user01@universalcontainers.demo".
D . userInformation[email]
Here email is treated as a variable, not a string literal.
Unless there is a variable named email defined with a value matching a property key, this will either:
Throw a ReferenceError (if email is not defined), or
Use the value of email as a computed key (not what is intended here).
It is not the correct way to access the "email" property literal.
Therefore, the correct ways are:
Answe r: A, C
Relevant concepts: object property access (. vs []), plain objects vs Map, literal property names vs computed property names.
NEW QUESTION # 54
Given the HTML below:
Which statement adds the priority-account css class to the Applied Shipping row?
Answer:
Explanation:
document.querySelector('#row-as').classList.add('priority-account');
NEW QUESTION # 55
A developer creates a simple webpage with an input field. When a user enters text in the inputfield and clicks the button, the actual value of the field must be displayed in the console.
Here is the HTML file content:
<input type =" text" value="Hello" name ="input">
<button type ="button" >Display </button>
The developer wrote the javascript codebelow:
Const button = document.querySelector('button');
button.addEvenListener('click', () => (
Const input = document.querySelector('input');
console.log(input.getAttribute('value'));
When the user clicks the button, the output is always "Hello".
What needs to be done make this code work as expected?
Answer: C
NEW QUESTION # 56
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