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NEW QUESTION # 120
static delay = async delay => {
return new Promise(resolve => {
setTimeout(resolve, delay);
});
};
static asyncCall = async () => {
await delay(1000);
console.log(1);
};
console.log(2);
asyncCall();
console.log(3);
Assume delay and asyncCall are in scope as functions.
What is logged to the console?
Answer: C
Explanation:
The correct answer is D, because JavaScript executes synchronous code first, while the code after await runs later after the Promise resolves.
The execution order is:
console.log(2);
This runs first, so JavaScript logs:
2
Then this line runs:
asyncCall();
The asyncCall() function starts executing. Inside it, JavaScript reaches:
await delay(1000);
The delay(1000) function returns a Promise that resolves after 1000 milliseconds:
return new Promise(resolve => {
setTimeout(resolve, delay);
});
Because await pauses the rest of the asyncCall() function, this line does not run immediately:
console.log(1);
Instead, JavaScript continues executing the remaining synchronous code outside the async function:
console.log(3);
So JavaScript logs:
3
After approximately 1000 milliseconds, the Promise returned by delay(1000) resolves. Then the paused async function continues and runs:
console.log(1);
So JavaScript logs:
1
Final console output:
2
3
1
Important JavaScript concepts involved:
An async function always returns a Promise.
The await keyword pauses execution only inside the async function where it appears.
Code outside the async function continues running normally.
setTimeout() schedules its callback to run later, after the current synchronous code has finished.
Therefore, the verified answer is D. 2 3 1.
NEW QUESTION # 121
Refer to the code below:
Which value can a developer expect when referencing country,capital,cityString?
Answer: B
NEW QUESTION # 122
Refer to the code below:
01 const objBook = {
02 title: 'JavaScript',
03 };
04 Object.preventExtensions(objBook);
05 const newObjBook = objBook;
06 newObjBook.author = 'Robert';
What are the values of objBook and newObjBook respectively?
Answer: B
Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge Object.preventExtensions(obj) This built-in JavaScript method marks an object so that no new properties can be added to it.
Existing properties can still be read and updated, but adding new ones is disallowed.
const newObjBook = objBook;
Both variables reference the same object in memory. JavaScript objects are assigned by reference, not copied.
newObjBook.author = "Robert";
Because the object has been marked as non-extensible, JavaScript will not allow new properties to be added.
The behavior depends on mode:
In non-strict mode: the assignment silently fails and does nothing.
In strict mode: this would throw a TypeError.
Since nothing indicates strict mode, this is non-strict behavior, making the assignment fail silently.
Therefore, the object remains:
{ title: "JavaScript" }
Both objBook and newObjBook point to the same unchanged object.
This matches option A.
________________________________________
JavaScript knowledge references (text-only)
Object.preventExtensions() prevents adding new properties.
Assigning an object to another variable copies the reference, not the object.
Adding a property to a non-extensible object silently fails in non-strict mode.
NEW QUESTION # 123
01 function changeValue(obj) {
02 obj.value = obj.value / 2;
03 }
04 const objA = { value: 10 };
05 const objB = objA;
06
07 changeValue(objB);
08 const result = objA.value;
What is the value of result?
Answer: C
Explanation:
objA is created with:
{ value: 10 }
objB = objA;
Objects in JavaScript are assigned by reference, not copied.
So objA and objB refer to the same object in memory.
The function:
changeValue(obj) {
obj.value = obj.value / 2;
}
When called as changeValue(objB), it updates the value property of the shared object:
value = 10 / 2 โ 5
Therefore:
objA.value === 5
Because objA and objB refer to the same object, the change is reflected in both.
JavaScript Knowledge Reference (text-only)
Objects are stored and passed by reference.
Mutating an object inside a function mutates the original object.
NEW QUESTION # 124
Refer to the code below:
const event = new CustomEvent(
//Missing Code
);
obj.dispatchEvent(event);
A developer needs to dispatch a custom event called update to send information about recordId.
Which two options could a developer insert at the placeholder in line 02 to achieve this?
Choose 2 answers
Answer: A,C
NEW QUESTION # 125
......
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