Foundations-of-Computer-Science Test Questions Answers - Latest Foundations-of-Computer-Science Guide Files

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WGU Foundations-of-Computer-Science Exam Syllabus Topics:

SectionWeightObjectives
Topic 1: Software Engineering & Programming Basics15%- Software development lifecycle
- Testing and debugging fundamentals
- Basic syntax and control structures
- Programming paradigms
Topic 2: Discrete Mathematics & Logic25%- Propositional and predicate logic
- Proof techniques and mathematical induction
- Set theory, relations, functions
- Boolean algebra and digital logic
Topic 3: Algorithms & Complexity25%- Recursion and iterative structures
- Algorithm design and analysis
- Big O notation, time and space complexity
- Sorting and searching algorithms
Topic 4: Data Structures20%- Trees, graphs, hash tables
- Arrays, linked lists, stacks, queues
- Primitive and composite data types
- Data storage and retrieval principles
Topic 5: Computer Architecture & Organization15%- Memory hierarchy and performance
- Instruction sets and execution cycles
- Von Neumann architecture
- CPU, memory, I/O systems

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WGU Foundations of Computer Science Sample Questions (Q41-Q46):

NEW QUESTION # 41
How can someone subset the last two rows and columns of a 2D NumPy array?

Answer: C

Explanation:
NumPy slicing uses the same start/stop rules as Python sequences, and it also supports negative indices to count from the end. In a 2D array, slicing is written as array[rows, columns]. To get thelast two rows, you use
-2: in the row position, meaning "start two rows from the end and go to the end." Similarly, to get thelast two columns, you use -2: in the column position. Combining these gives array[-2:, -2:], which selects the bottom- right 2×2 subarray.
Option A, array[-2:, :], selects the last two rows butall columns, so it is not restricted to the last two columns.
Option D, array[:, -2:], selects all rows but only the last two columns. Option B, array[-1:, -1:], selects only the last row and the last column, producing a 1×1 (or 1×1 view) subarray, not a 2×2.
This kind of slicing is widely taught because it is essential for matrix operations, extracting submatrices, working with sliding windows, and manipulating image or time-series data where "take the last k observations/features" is common. Negative indexing reduces errors and makes code clearer, especially compared with computing explicit indices like array[rows-2:rows, cols-2:cols].


NEW QUESTION # 42
Which type of data structure is the only focus of a binary search?

Answer: D

Explanation:
Binary search is designed for searching in asorted (ordered) sequence. Its efficiency comes from repeatedly comparing the target to the middle element and discarding half of the remaining search space. This halving logic only works when the data is ordered, because the algorithm relies on the guarantee that all elements on one side of the midpoint are smaller (or larger) than the midpoint. In textbooks, this requirement is stated explicitly: binary search assumes the collection is sorted according to the same ordering used for comparisons.
An "ordered list" is therefore the correct focus among the options. Binary search can be implemented on arrays or other random-access structures where you can quickly access the middle element by index. While you can conceptually perform binary search on a linked list, it becomes inefficient because finding the middle requires linear traversal, losing the O(log n) advantage. Stacks and queues are not appropriate because they restrict access to ends only (LIFO for stacks, FIFO for queues), preventing direct access to the midpoint and making the binary search strategy infeasible.
Thus, the central requirement for binary search is a sorted/ordered sequence, typically supporting efficient indexing, which is why the correct choice is an ordered list.


NEW QUESTION # 43
What code would print a subarray of the first 5 elements in numpy_array?

Answer: C

Explanation:
NumPy arrays support slicing using the same start:stop convention as Python sequences. To take the first five elements, you want indices 0 through 4. The slice numpy_array[:5] means "start from the beginning (default start is 0) and stop before index 5." Because the stop index is exclusive, this returns exactly the first five elements. Printing that slice with print(numpy_array[:5]) displays a 1D view (or copy depending on context) containing those elements.
Option A, numpy_array[1:5], starts at index 1, so it returns elements 1 through 4-only four elements-and it excludes the element at index 0, so it is not the first five elements. Options B and D are incorrect because NumPy arrays do not provide a .get() method for slicing in this manner; .get() is a method associated with dictionaries, not arrays.
Textbooks stress slicing because it is efficient and expressive, especially in data analysis. With slicing, you can take prefixes, suffixes, windows, or regularly spaced samples without writing loops. In NumPy, slicing is particularly important because many slices create views into the same underlying data buffer, enabling memory-efficient operations on large datasets. Understanding inclusive start and exclusive stop boundaries is critical to avoid off-by-one mistakes and to work correctly with batches and segments of numerical data.


NEW QUESTION # 44
What happens if one element of a NumPy array is changed to a string?

Answer: A

Explanation:
A central rule in NumPy is that an ndarray has a single, fixed data type called itsdtype. That dtype is chosen when the array is created (for example, int64, float64, etc.), and it normally does not change just because you assign a new value into one element. When you attempt an assignment, NumPy tries tocastthe assigned value into the array's existing dtype. If the cast is possible, the assignment succeeds; if the cast is impossible, NumPy raises an error.
So, if you have a numeric array such as arr = np.array([1, 2, 3]), its dtype is an integer type. Trying arr[0] =
"hello" cannot be converted into an integer, so NumPy raises a ValueError (a casting/conversion error). This is exactly the behavior textbooks highlight when contrasting NumPy arrays with Python lists: lists can hold mixed types freely, but NumPy arrays trade that flexibility for speed and memory efficiency via uniform typing.
Option A is a common misconception. While NumPy may "upcast" values to a more general dtype at array creation time when mixed types are provided (e.g., numbers and strings in the same constructor), a pre-existing numeric array will not automatically convert itself into a string array during a single- element assignment. Options C and D do not reflect NumPy's assignment rules.


NEW QUESTION # 45
What is an ndarray in Python?

Answer: A

Explanation:
An ndarray is NumPy's fundamental data structure: ann-dimensional arraydesigned for efficient numerical computation. The term stands for "N-dimensional array," and it is implemented as numpy.ndarray. Unlike Python's built-in list, an ndarray stores elements in a compact, homogeneous format defined by its dtype (such as integers or floating-point numbers). This uniform representation enables fast, vectorized operations and efficient use of memory, which is why ndarray is central in scientific computing and data analysis.
An ndarray supports multiple dimensions: a 1D array behaves like a vector, a 2D array like a matrix (rows and columns), and higher-dimensional arrays represent tensors. Textbooks emphasize that ndarray operations are typically element-wise by default (for example, a + b adds corresponding elements), and that slicing and broadcasting allow powerful computations without explicit loops. This approach is both expressive and efficient because the heavy lifting happens in optimized low-level code.
Option A is incorrect because ndarray is not built into core Python; it comes from NumPy. Option B describes a tree, which is a different data structure entirely. Option D is incorrect because sockets and XML-related functionality belong to other parts of Python's standard library, not to NumPy or ndarray.
In short, an ndarray is the primary array object of NumPy, providing high-performance multi- dimensional numerical storage and computation.


NEW QUESTION # 46
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