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| Section | Weight | Objectives |
|---|---|---|
| Data Handling and Logic | 15% | - Error handling
|
| App Design and Best Practices | 15% | - User experience principles
|
| Development Environment | 15% | - Xcode interface and tools
|
| Swift Programming Fundamentals | 30% | - Functions
|
| SwiftUI Basics | 25% | - Views and controls
|
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NEW QUESTION # 12
Review the code.
When entered into the TextField, which number will display a blue canvas on the SecondView?
Answer: A
Explanation:
This question belongs to View Building with SwiftUI , especially the domain on creating multiple views to implement app logic and sharing values between views. In FirstView, the value typed into the TextField is stored in number, which is a String. When the NavigationLink is tapped, the code passes Int(number) ?? 0 into SecondView. In Swift, converting a string to an integer with Int(...) uses an optional initializer, which means it returns an optional value and will produce nil if the string cannot be converted. The ?? 0 nil- coalescing operator then supplies 0 if conversion fails.
Inside SecondView, the body is:
Color(passedNumber == 3 ? .blue : .red)
This uses the ternary conditional operator. If passedNumber equals 3, the displayed color is blue; otherwise, it is red. Therefore, entering 3 into the TextField causes Int(number) to become 3, which makes the condition passedNumber == 3 true and displays a blue canvas. Any other listed number results in red.
So the correct answer is A. 3 . This matches the SwiftUI pattern of taking user input, converting it to the needed type, passing it into another view, and rendering UI conditionally based on that value.
NEW QUESTION # 13
Review the code.
You need to add the word " Great! " to the Capsule shape.
Complete the code by typing in the boxes.
Answer:
Explanation:
overlay, Text
Explanation:
This question belongs to View Building with SwiftUI , particularly the domain involving positioning and/or laying out a single SwiftUI view with standard views and modifiers . To place text on top of a shape such as a Capsule, SwiftUI uses the overlay modifier. Apple documents overlay as a view modifier that layers one view in front of another, which is exactly what is needed here: the text should appear on top of the blue capsule rather than beside or below it. The second blank must therefore be Text , because SwiftUI uses a Text view to display string content like " Great! " .
The completed code is:
struct ContentView: View {
var body: some View {
Capsule()
.fill(.blue)
.frame(width: 200.0, height: 100.0)
.overlay(
Text( " Great! " )
.font(.largeTitle)
)
}
}
This works because Capsule() creates the shape, .fill(.blue) gives it the blue color, .frame(width:height:) sets its size, and .overlay(...) places the Text( " Great! " ) directly above that shape. This is a standard SwiftUI composition pattern: build a base view, then apply modifiers to style it and layer additional content. In App Development with Swift objectives, this aligns with understanding standard views, modifiers, and layout techniques in SwiftUI.
NEW QUESTION # 14
Review the code snippet and identify what happens when the program is executed.
Answer: A
Explanation:
This question belongs to Swift Programming Language , specifically the objectives covering arrays , loops
, and range operators . The array has 6 elements, so menuItems.count is 6. The loop uses the half-open range operator:
for index in 1.. < (menuItems.count - 1)
That becomes:
for index in 1.. < 5
In Swift, the half-open range operator a.. < b includes the lower bound but does not include the upper bound.
So this loop runs with index values 1, 2, 3, 4, not 0 and not 5.
Array subscripting uses those indexes to print:
* menuItems[1] # " Burger "
* menuItems[2] # " Chicken "
* menuItems[3] # " Pasta "
* menuItems[4] # " Salad "
That means " Pizza " at index 0 is skipped, and " Steak " at index 5 is also skipped. Swift arrays use zero- based indexing, and count returns the number of elements in the array.
Therefore, the program prints only " Burger " , " Chicken " , " Pasta " , and " Salad " , so the correct answer is A .
NEW QUESTION # 15
Review the code snippet.
The code snippet does not compile.
Which two actions will fix the errors? (Choose 2.)
Answer: C,D
Explanation:
This question belongs to Swift Programming Language , especially the domains covering basic Swift types
, operators , and constants versus variables .
There are two compile problems in the snippet. First, unitPrice and shipping are inferred as Double, while quantity is inferred as Int. In Swift, arithmetic operands must have compatible types; Swift does not automatically mix Int and Double in one arithmetic expression. So unitPrice * quantity fails unless quantity is changed to Double or explicitly converted. That makes A a correct fix.
Second, the line totalCost += ... uses the compound assignment operator +=, which stores a new value back into the left-hand side. Swift requires the left-hand side of += to be mutable, so totalCost must be declared with var, not let. That makes D the second correct fix.
The other choices do not solve the actual compile issues. B is unnecessary because totalCost is already explicitly declared as Double, so 0 is valid there. C would still leave shipping as Double, so the mixed-type arithmetic problem remains. E is irrelevant because shipping is never reassigned. Therefore, the two correct answers are A and D
NEW QUESTION # 16
Review the code snippet and then predict the output.
Answer: A
Explanation:
This question belongs to Swift Programming Language , especially the domains covering control flow , loops , logical operators , and guard . The loop runs through 0.. < max, and since max = 101, the values of num are 0 through 100. Inside the loop, the guard statement keeps only values that satisfy both conditions:
* num % 5 == 0 # the number must be divisible by 5
* num % 2 != 0 # the number must be odd
So the code counts numbers from 0 to 100 that are odd multiples of 5 . Those values are:
5, 15, 25, 35, 45, 55, 65, 75, 85, 95
That gives a total of 10 numbers. Therefore count becomes 10, and the printed output is:
Total count: 10
The key Swift concept here is that guard ... else { continue } skips any loop iteration that does not meet the required condition. Only matching values reach count += 1. This is a standard use of guard for early exit and of the remainder operator % for divisibility checks. Therefore, the correct answer is B .
NEW QUESTION # 17
......
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