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Salesforce JS-Dev-101 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.
Topic 2
  • Testing: Covers evaluating unit test effectiveness against a block of code and modifying tests to improve their coverage and reliability.
Topic 3
  • Objects, Functions, and Classes: Covers function, object, and class implementations to meet business requirements, along with the use of modules, decorators, variable scope, and execution flow.
Topic 4
  • Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
Topic 5
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.

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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q96-Q101):

NEW QUESTION # 96
A developer publishes a new version of a package with bug fixes but no breaking changes. The old version number was 2.1.1.
What should the new package version number be based on semantic versioning?

Answer: A

Explanation:
Semantic versioning: MAJOR.MINOR.PATCH
MAJOR: incompatible API changes.
MINOR: add functionality in a backward compatible manner.
PATCH: backward compatible bug fixes.
Here:
Bug fixes only, no breaking changes โ†’ increment PATCH.
From 2.1.1 to 2.1.2.
So the correct new version is 2.1.2.


NEW QUESTION # 97
A developer copied a JavaScript object:
01 function Person() {
02 this.firstName = "John";
03 this.lastName = "Doe";
04 this.name = () => `${this.firstName},${this.lastName}`;
05 }
06
07 const john = new Person();
08 const dan = Object.assign({}, john);
09 dan.firstName = 'Dan';
How does the developer access dan's firstName, lastName?

Answer: B

Explanation:
Person instances have:
firstName and lastName as string properties.
A name method that returns a combined string: `${this.firstName},${this.lastName}`.
Object.assign({}, john) creates a shallow copy of john into a new object, dan.
After:
dan.firstName = 'Dan';
dan.name() returns "Dan,Doe".
Analysis of options:
A: dan.firstName() and dan.lastName() are function calls, but firstName/lastName are strings, not functions โ†’ TypeError.
B: Calls the defined method and uses both names correctly.
C: dan.name is a function reference; you'd still need to call it: dan.name().
D: dan.firstName + dan.lastName is "DanDoe", no separator. It accesses the properties but not in the method the developer defined.
The intended way, using the provided API, is dan.name().
________________________________________


NEW QUESTION # 98
A developer uses a parsed JSON string to work with user information as in the block below:
01 const userInformation = {
02 "id": "user-01",
03 "email": "user01@universalcontainers.demo",
04 "age": 25
05 };
Which two options access the email attribute in the object?

Answer: A,B

Explanation:
userInformation is a plain JavaScript object:
{
id: "user-01",
email: "user01@universalcontainers.demo",
age: 25
}
You can access object properties in two standard ways:
Dot notation: object.propertyName
Bracket notation: object['propertyName']
Apply to each option:
A . userInformation.email
Correct dot notation; accesses "user01@universalcontainers.demo".
B . userInformation.get("email")
.get() is a method on Map instances, not on plain objects.
A regular object does not have a .get method; this would be TypeError.
C . userInformation["email"]
Correct bracket notation; string "email" is used as the property key.
Returns "user01@universalcontainers.demo".
D . userInformation[email]
Here email is treated as a variable, not a string literal.
Unless there is a variable named email defined with a value matching a property key, this will either:
Throw a ReferenceError (if email is not defined), or
Use the value of email as a computed key (not what is intended here).
It is not the correct way to access the "email" property literal.
Therefore, the correct ways are:
Answe r: A, C
Relevant concepts: object property access (. vs []), plain objects vs Map, literal property names vs computed property names.


NEW QUESTION # 99
developer is trying to convince management that their team will benefit from using Node.js for a backend server that they are going to create. The server will be a web server that handles API requests from a website that the teamhas already built using HTML, CSS, and JavaScript.
Which three benefits of Node.js can the developer use to persuade their manager?
Choose 3 answers:

Answer: C,D,E


NEW QUESTION # 100
01 function Monster() { this.name = 'hello'; };
02 const m = Monster();
What happens due to the missing new keyword?

Answer: C

Explanation:
In JavaScript, when calling a constructor function without new:
const m = Monster();
the following happens:
The function executes as a normal function, not as a constructor.
Inside a regular function (in non-strict mode), this refers to the global object:
In a browser: window
So the line:
this.name = 'hello';
becomes:
window.name = 'hello';
Since Monster() does not return anything, its return value is undefined:
const m = undefined;
Therefore:
m is undefined
window.name becomes "hello"
This matches option B.
JavaScript Knowledge Reference (text-only)
Calling a function without new uses the global object as this in non-strict mode.
Constructor functions must use new to create a new object.
Functions without an explicit return return undefined.


NEW QUESTION # 101
......

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