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Oracle Database SQL Sample Questions (Q235-Q240):

NEW QUESTION # 235
Evaluate the following SQL statement:
SQL> select cust_id, cust_last_name "Last name"
FROM customers
WHERE country_id = 10
UNION
SELECT cust_id CUST_NO, cust_last_name
FROM customers
WHERE country_id = 30
Identify three ORDER BY clauses either one of which can complete the query.

A. ORDER BY CUST_NO
B. ORDER BY 2, cust_id
C. ORDER BY "Last name"
D. ORDER BY "CUST_NO"
E. ORDER BY 2, 1

Answer: B,C,E

Explanation:
Using the ORDER BY Clause in Set Operations
-The ORDER BY clause can appear only once at the end of the compound query.
-Component queries cannot have individual ORDER BY clauses.
-The ORDER BY clause recognizes only the columns of the first SELECT query.
-By default, the first column of the first SELECT query is used to sort the output in an ascending order.

NEW QUESTION # 236
Which three statements indicate the end of a transaction? (Choose three.)

A. after a SAVEPOINTis issued
B. after a ROLLBACKis issued
C. after a CREATEstatement is issued
D. after a SELECTstatement is issued
E. after a COMMITis issued

Answer: B,C,E

NEW QUESTION # 237
View the Exhibit and examine the structure of the EMPLOYEES and JOB_HISTORY tables.

Examine this query which must select the employee IDs of all the employees who have held the job SA_MAN at any time during their employment.
SELECT EMPLOYEE_ID
FROM EMPLOYEES
WHERE JOB_ID = 'SA_MAN'
-------------------------------------
SELECT EMPLOYEE_ID
FROM JOB_HISTORY
WHERE JOB_ID = 'SA_MAN';
Choose two correct SET operators which would cause the query to return the desired result.

A. UNION ALL
B. MINUS
C. INTERSECT
D. UNION

Answer: A,D

NEW QUESTION # 238
Which two join conditions in a from clause are non-equijoins?

A. table1 join table2 ON (table1.column >= table2.column)
B. table1 natural JOIN table2
C. table1 join table2 using (column1, column2)
D. table1 join table2 on (table1.column between table2.column] and table2.column2)
E. tablet join table2 ON (table1.column = table2.column) where table2.column LIKE 'A'

Answer: A,D

Explanation:
Equijoins are joins that use the equality operator (=) to match rows. Non-equijoins are joins that use operators other than the equality operator.
A . False. This condition is an equijoin as it uses the equality operator (=).
B . True. This join condition uses the BETWEEN operator, which is not based on equality.
C . False. A natural join is a type of equijoin where the join is made on all columns with the same names in both tables.
D . False. USING clause is used to specify an equijoin on one or more columns.
E . True. This join condition uses the greater than or equal to (>=) operator, making it a non-equijoin.
Reference:
Oracle Documentation on Joins: https://docs.oracle.com/database/121/SQLRF/queries006.htm#SQLRF52358

NEW QUESTION # 239
Examine this partial statement:
SELECT ename, sal,comm FROM emp
Now examine this output:

WHICH ORDER BY clause will generate the displayed output?

A. ORDER BY NVL(comm,0) ASC NULLS LAST, ename
B. ORDER BY NVL(enam,0) DESC, ename
C. ORDER BY NVL(comm,0) ASC NULLS FIRST, ename
D. ORDER BY comm DESC NULLS LAST, ename

Answer: B,D

NEW QUESTION # 240
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