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AEE CEM Exam Syllabus Topics:

SectionWeightObjectives
HVAC Systems and Building Envelope15%- Load calculation and system selection
- Thermal envelope performance
- Heating, ventilation and air conditioning
Measurement and Verification5%- Baseline development and savings calculation
- M&V protocols and standards
Distributed Generation and Renewable Energy4–6- Combined heat and power (CHP)
- Grid integration and economics
- Solar, wind, biomass, geothermal
Building Automation and Controls5%- Building management systems
- Control systems and strategies
- Automation and optimization
Energy Accounting and Economics15%- Time value of money, NPV, IRR, payback analysis
- Life cycle costing and economic analysis
- Utility rate structures and tariffs
- Energy units and conversions
Energy Savings Performance Contracting5%- Contract structures and financing
- Guaranteed savings and risk allocation
Energy Storage Systems3–5- Integration and benefits
- Storage technologies and applications
Industrial Systems6–8- Compressed air, pumping, and drying systems
- Process energy efficiency
Boiler and Steam Systems4–6- Maintenance and optimization
- Operation and efficiency
Operations, Maintenance and Commissioning5%- Commissioning and retro-commissioning
- Maintenance best practices
Energy Audits and Instrumentation10%- Measurement tools and instrumentation
- Data collection and analysis
- Energy performance indicators
- Audit levels and methodologies
Electrical Power Systems and Motors15%- Power distribution and quality
- Power factor correction and load management
- Motor systems, efficiency and controls
Lighting Systems10%- Lighting technologies and efficiency
- Daylighting integration
- Design and control strategies
Codes, Standards and Regulations5%- Compliance and reporting requirements
- Energy efficiency codes and standards
- Sustainability policies and frameworks

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AEE Certified Energy Manager (CEM) Sample Questions (Q108-Q113):

NEW QUESTION # 108
A compressed air system has a total volume of 247,500 liters. During a 30-minute break in production (air compressor system turned off and no production demand for compressed air), the system pressure drops from
7 bar, gauge (700 kPa, gauge) to 5 bar, gauge (500 kPa, gauge). Calculate the leakage rate in the compressed air system.

Answer: D


NEW QUESTION # 109
An energy-saving project costs $540,000. The project will have maintenance costs of $25,000 per year. The energy savings from the project are $160,000 per year. What is the simple payback of the project?

Answer: A

Explanation:
To determine the simple payback period for the energy-saving project, we need to apply the standard formula used in energy management as per the Association of Energy Engineers (AEE) Certified Energy Manager (CEM) guidelines. The simple payback period is a widely used metric in energy efficiency projects to evaluate how long it takes for the initial investment to be recovered through net savings. Let's break this down step-by-step using the provided data and CEM-aligned methodology.
Step 1: Understand the Simple Payback Formula
* Formula: Simple Payback Period (years)=Initial Investment CostNet Annual Savings\text{Simple Payback Period (years)} = \frac{\text{Initial Investment Cost}}{\text{Net Annual Savings}} Simple Payback Period (years)=Net Annual SavingsInitial Investment Cost
* Definition: The simple payback period represents the time (in years) required for the cumulative savings to equal the initial investment, without considering the time value of money (e.g., discount rates or inflation).
* CEM Reference: AEE CEM training materials emphasize this formula in the "Energy Economics" section, where simple payback is a fundamental tool for assessing project feasibility.
Step 2: Identify Given Data
* Initial Investment Cost: $540,000 (one-time cost of the project).
* Annual Energy Savings: $160,000 per year (benefit from the project).
* Annual Maintenance Costs: $25,000 per year (additional cost incurred due to the project).
* Net Annual Savings: This must account for both the savings and the costs incurred annually.
Step 3: Calculate Net Annual Savings
* Definition: Net annual savings is the difference between the annual energy savings and any additional annual costs (e.g., maintenance).
* Verification: The problem specifies maintenance costs as an ongoing expense tied to the project, which reduces the effective savings. CEM guidelines require including such costs in payback calculations unless explicitly stated otherwise.
Step 4: Compute the Simple Payback Period
* Apply the Formula: Simple Payback Period=Initial Investment CostNet Annual Savings\text{Simple Payback Period} = \frac{\text{Initial Investment Cost}}{\text{Net Annual Savings}} Simple Payback Period=Net Annual SavingsInitial Investment Cost Simple Payback Period=540,
000135,000=4.0 years\text{Simple Payback Period} = \frac{540,000}{135,000} = 4.0 \, \text{years} Simple Payback Period=135,000540,000=4.0years
* Result: The payback period is exactly 4.0 years, meaning it takes 4 years for the net savings to recover the initial investment.
Step 5: Validate Against Options
* Options:A. 2.0 yearsB. 3.0 yearsC. 4.0 yearsD. 5.0 years
* Check:
* If we ignored maintenance costs (incorrectly), payback would be 540,000160,000=3.375 \frac
{540,000}{160,000} = 3.375 160,000540,000=3.375 years, which rounds to 3.4-not an exact match for any option.
* With maintenance costs included, 540,000135,000=4.0 \frac{540,000}{135,000} = 4.0
135,000540,000=4.0, which matches option C precisely.
* Conclusion: Option C (4.0 years) is correct based on the net savings approach.


NEW QUESTION # 110
An office building is illuminated with T8 fluorescent lamps. Which of the following is the best schedule for group relamping (total replacement of all the T8 fluorescent lamps in the building)?

Answer: D


NEW QUESTION # 111
If installed without ancillary equipment, photovoltaic power cells generate what type of power?

Answer: B


NEW QUESTION # 112
Natural gas costs $4.80/GJ. How much does it cost to heat 500 liters of water from 18°C to 50°C using a natural gas water heater with an efficiency of 85%? [The efficiency and fuel price are both based on HHV.
The specific heat of water (C) is 4.2 kJ/kg-°C.]

Answer: D

Explanation:
To calculate the cost of heating water using natural gas:
Step 1: Compute Energy Required to Heat the Water
Given:
* Mass of water = 500 L = 500 kg
* Temperature rise (#T) = 50°C - 18°C = 32°C
* Specific heat of water (Cp) = 4.2 kJ/kg-°C
Energy Required (Q)=m×Cp×#T
=500×4.2×32
=67,200 kJ=67.2 MJ


NEW QUESTION # 113
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