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| Certification Vendor: | Huawei |
|---|---|
| Exam Name: | HCIA-Datacom V2.0 |
| Exam Number: | H12-811_V2.0 |
| Related Certifications: | HCIP-Datacom HCIE-Datacom |
| Exam Duration: | 90 minutes |
| Available Languages: | English |
| Passing Score: | 600/1000 |
| Real Exam Qty: | 60 |
| Exam Format: | Short Response Item, Drag and Drop Item, True or False, Multiple-answer Question, Single-answer Question |
| Certificate Validity Period: | 3 years |
| Exam Price: | 200 USD |
| Recommended Training: | Huawei HCIA-Datacom Training Course |
| Exam Registration: | Pearson VUE Registration Huawei Official Certification |
| Sample Questions: | Huawei H12-811_V2.0 Sample Questions |
| Exam Way: | Online proctored or onsite at Pearson VUE test centers |
| Pre Condition: | No mandatory prerequisites |
| Official Syllabus URL: | https://e.huawei.com/en/training/certification/exam/h12-811_v2.0 |
With the Huawei H12-811_V2.0 PDF questions file, you can prepare for the Huawei H12-811_V2.0 test on the go since the format is portable and works with all smart devices. The Huawei H12-811_V2.0 probable exam questions in PDF save you time so that you do not have to go through sleepless nights owing to a tight daily routine.
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NEW QUESTION # 66
There are several distinct topologies for data communication networks. Which of the following network topologies presents the risk of network-wide communication breakdown in the case of a single device fault?
Answer: B
Explanation:
In a ring topology, each device is connected in a closed loop, so data travels through each node in sequence. If a single device or link fails, it can interrupt the entire loop and break communication across the network unless redundancy mechanisms are in place.
NEW QUESTION # 67
In an IPv6 address, two or more consecutive groups of 0s can be compressed using a double colon (::), reducing the overall length of the address. For example, 2001:DBFF:130F:0:0:0:0:130B can be compressed to
2001:DBFF:130F::130B.
Answer: A
Explanation:
IPv6 text representation permits zero compression to make long addresses easier to read and write. One or more consecutive 16-bit groups containing only zeros can be replaced by a double colon, subject to the rule that the double-colon compression is used only once in a single IPv6 address; otherwise the number of omitted groups would be ambiguous. In the address 2001:DBFF:130F:0:0:0:0:130B, four consecutive zero groups appear between 130F and 130B. Replacing that run with :: produces 2001:DBFF:130F::130B, which expands back unambiguously to the original eight groups. Leading zeros within an individual 16-bit group can also be omitted, but that is a separate abbreviation rule. The example in the question follows valid IPv6 notation and does not alter the numeric address. Consequently, the statement that the address can be compressed in the manner shown is TRUE. The correct answer is A. The compression changes only the written representation of the IPv6 address; it does not change the underlying 128-bit address value itself in any way.
NEW QUESTION # 68
What is the broadcast address of the network that contains a host with IP address 192.168.1.147/28?
Answer: A
NEW QUESTION # 69
Which of the following configurations can enable connectivity between interfaces on R1 and R3? (Select all that apply)
Answer: A,B
Explanation:
For two directly connected edge networks to communicate through intermediate routing, each end router must have a route to the remote destination network pointing to the correct next hop on the transit link. Since
10.0.0.0/24 is directly connected to R1 and 20.1.1.0/24 is directly connected to R3, R1 needs a route to
20.1.1.0/24, and R3 needs a route to 10.0.0.0/24.
Option A is correct because it configures on R1 a static route to the remote network 20.1.1.0/24 using next hop 10.0.0.2, which is the neighbor toward the transit path. Option D is correct because it configures on R3 a static route to the remote network 10.0.0.0/24 using next hop 20.1.1.1, which is the proper adjacent forwarding address in that direction. Option B is incorrect because a router cannot use a next hop that belongs to the remote destination network but is not directly reachable as a valid immediate forwarding address in this topology. Option C is also incorrect because the specified next hop is not the correct adjacent next-hop address for R3. HCIA-Datacom stresses that static routes must always point to a reachable next hop or outbound interface.
NEW QUESTION # 70
On the switched network shown in the figure, STP is enabled on all devices. SW1 is the root bridge. The port costs are shown in the figure. Other parameters retain the default values. After the network is stable, which of the following ports are alternate ports? (Choose all that apply.)
Answer: C,D
Explanation:
To find the alternate ports, we first identify the quickest path to the root bridge, SW1, for every other switch. SW2 reaches the root directly through its top port with a cost of 30. SW3 has the fastest direct path with a cost of 10. SW4 calculates that going through SW3 is cheaper than going directly to the root, giving it a total root cost of 40. SW5 finds its best path by going through SW4, resulting in a total root cost of 50. All of these preferred entry points become Root Ports.
Next, we look at the remaining open links to see which ports must be blocked to prevent loops.
On any connection between two switches, the switch that is further away from the root bridge loses the battle and has to block its port, turning it into an Alternate Port.
When comparing the cross-link between SW1 and SW4, SW1 is the root bridge itself, so SW4 loses this matchup and blocks its GE1/0/3 port. Looking at the link between SW3 and SW5, SW3 is much closer to the root bridge with a cost of 10 compared to SW5's cost of 50, which forces SW5 to block its GE1/0/1 port. On the remaining links, SW2 forces SW4 to block its GE1/0/2 port, and SW3 forces SW2 to block its GE1/0/3 port.
Matching these blocked paths to the given choices leaves us with GE1/0/3 of SW4 and GE1/0/1 of SW5 as the alternate ports.
NEW QUESTION # 71
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