1z0-071全真模擬試験、1z0-071復習解答例

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Oracle 1z0-071 Exam Overview:

Certification Vendor:	Oracle
Exam Name:	Oracle Database SQL
Exam Number:	1z0-071
Real Exam Qty:	70
Related Certifications:	Oracle Database Administrator Certified Associate (DBA) Oracle Database SQL Certified Associate
Available Languages:	Japanese, Korean, Portuguese, English, Simplified Chinese
Exam Format:	Multiple Choice
Exam Price:	$245 USD
Certificate Validity Period:	No expiration for this exam/certification
Passing Score:	63%
Exam Duration:	120 minutes
Sample Questions:	Oracle 1z0-071 Sample Questions
Exam Way:	Pearson VUE testing center (online proctored option available)
Pre Condition:	No formal prerequisites required, but basic knowledge of relational database concepts is recommended
Official Syllabus URL:	https://education.oracle.com/oracle-database-sql-exam

>> 1z0-071全真模擬試験 <<

Oracle Database SQL 認定 1z0-071 試験問題 (Q386-Q391):

質問 # 386
Examine the structure of the members table:

What is the outcome?

A. It executes successfully and displays the column details in three separate columns and replaces only the last column heading with the alias.
B. It executes successfully and displays the column details in a single column with only the alias column heading.
C. It fails because the space specified in single quotation marks after the first two column names is invalid.
D. It fails because the alias name specified after the column names is invalid.

正解：A

質問 # 387
Examine the description of the transactions table:

Which two SQL statements execute successfully?

A. SELECT customer id AS CUSTOMER-ID, transaction_date AS TRANS_DATE, amount+100 "DUES AMOUNT" FROM transactions;
B. SELECT customer_id AS 'CUSTOMER-ID',transaction_date AS DATE, amount+100 'DUES' from transactions;
C. SELECT customer_id AS "CUSTOMER-ID", transaction_date AS "DATE", amount+100 DUES FROM transactions;
D. SELECT customer_id AS "CUSTOMER-ID", transaction_date AS DATE, amount+100 "DUES" from transactions;
E. SELECT customer_id CUSTID, transaction_date TRANS_DATE,amount+100 DUES FROM transactions;

正解：C、E

質問 # 388
Examine the description of the CUSTOMERS table:

You need to display last names and credit limits of all customers whose last name starts with A or B In lower or upper case, and whose credit limit is below 1000.
Examine this partial query:
SELECT cust_last_nare, cust_credit_limit FROM customers
Which two WHERE conditions give the required result?

A. WHERE UPPER(cust_last_name) IN ('A%', 'B%') AND cust_credit_limit < 1000:
B. WHERE (UPPER(cust_last_name) LIKE 'A%' OR UPPER(cust_last_name) LIKE 'B%') AND ROUND(cust_credit_limit) < 1000;
C. WHERE (INITCAP(cust_last_name) LIKE 'A%' OR ITITCAP(cust_last_name) LIKE 'B%') AND cust_credit_limit < 1000
D. WHERE (UPPER(cust_last_name) like INITCAP ('A') OR UPPER(cust_last_name) like INITCAP('B')) AND ROUND(cust_credit_limit) < ROUND(1000) ;
E. WHERE UPPER(cust_last_name) BETWEEN UPPER('A%' AND 'B%') AND ROUND(cust_credit_limit) < 1000;

正解：B、C

解説：
The SQL query must find all customers with last names starting with A or B, regardless of case, and a credit limit below 1000:
B . WHERE (INITCAP(cust_last_name) LIKE 'A%' OR INITCAP(cust_last_name) LIKE 'B%') AND cust_credit_limit < 1000: The INITCAP function initializes the first letter to uppercase for comparison. However, it should be noted that using INITCAP is not necessary when using the LIKE operator with a wildcard % following a single character, because it will not correctly filter all last names that start with an upper or lower case A or B.
D . WHERE (UPPER(cust_last_name) LIKE 'A%' OR UPPER(cust_last_name) LIKE 'B%') AND cust_credit_limit < 1000: This correctly filters last names beginning with A or B in any case and includes only those with a credit limit below 1000. The UPPER function is used to convert cust_last_name to uppercase before comparison.
Reference:
Oracle Database SQL Language Reference 12c, especially sections on string functions and conditions.

質問 # 389
Examine these SQL statements that are executed in the given order:

What will be the status of the foreign key EMP_MGR_FK?

A. It will remain disabled and can be re-enabled manually.
B. It will be enabled and immediate.
C. It will be enabled and deferred.
D. It will remain disabled and can be enabled only by dropping the foreign key constraint and re-creating it.

正解：A

質問 # 390
Examine the data in the EMP table:

You execute this query:
SELECT deptno AS "Department", AVG(sal) AS AverageSalary, MAX(sal) AS "Max Salary" FROM emp WHERE sal >= 12000 GROUP BY "Department " ORDER BY AverageSalary; Why does an error occur?

A. An alias name must not be used in a GROUP BY clause.
B. An alias name must always be specified in quotes.
C. An allas name must not contain space characters.
D. An alias name must not be used in an ORDER BY clause.

正解：A

質問 # 391
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1z0-071全真模擬試験、1z0-071復習解答例

Oracle 1z0-071 Exam Overview:

最新の1z0-071全真模擬試験 & 合格スムーズ1z0-071復習解答例 | 認定する1z0-071学習指導

Oracle Database SQL 認定 1z0-071 試験問題 (Q386-Q391):