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| Section | Weight | Objectives |
|---|---|---|
| Computer Architecture & Organization | 15% | - Instruction sets and execution cycles - Memory hierarchy and performance - CPU, memory, I/O systems - Von Neumann architecture |
| Algorithms & Complexity | 25% | - Recursion and iterative structures - Sorting and searching algorithms - Big O notation, time and space complexity - Algorithm design and analysis |
| Software Engineering & Programming Basics | 15% | - Basic syntax and control structures - Software development lifecycle - Programming paradigms - Testing and debugging fundamentals |
| Data Structures | 20% | - Trees, graphs, hash tables - Primitive and composite data types - Data storage and retrieval principles - Arrays, linked lists, stacks, queues |
| Discrete Mathematics & Logic | 25% | - Boolean algebra and digital logic - Propositional and predicate logic - Set theory, relations, functions - Proof techniques and mathematical induction |
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NEW QUESTION # 36
m = 30
n = 30
What will be the output of print(id(m), id(n)) after executing the following code?
Answer: D
Explanation:
In Python, id(x) returns the "identity" of an object, which in CPython (the most common implementation) is typically the object's memory address. When you write m = 30 and n = 30, both names may refer to thesame integer objectbecause CPython caches a range of small integer objects for efficiency. This optimization means that commonly used small integers are pre-created and reused, so repeated occurrences of the same small integer literal often point to the same object, producing identical id() values. As a result, print(id(m), id (n)) will most likely displaytwo identical numbersin standard CPython builds when 30 falls within the cached range. (Real Python) This behavior is an implementation detail, but it is widely discussed in Python education because it illustrates the difference between object identity (whether two variables reference the same object) and value equality (whether two objects have the same value). Even if id(m) and id(n) were different in some edge environment, m == n would still be True because the values are equal; id() is about identity, not value. The options "0 0" and "Error" are not consistent with how id() works for valid objects.
NEW QUESTION # 37
Which order is impossible when traversing a binary tree using depth first search?
Answer: A
Explanation:
Depth-first search (DFS) explores a tree by going as deep as possible along a branch before backtracking. In binary trees, DFS gives rise to the classic traversal orderspre-order,in-order, andpost-order, each defined by when you "visit" the node relative to its left and right subtrees. Pre-order visits the node first, then left subtree, then right subtree. In-order visits left subtree, then the node, then right subtree. Post-order visits left subtree, then right subtree, then the node. These are all DFS-based because they fully explore subtrees before moving sideways to another branch.
Level-order traversalis different: it visits nodes layer by layer from the root outward (all nodes at depth 0, then depth 1, then depth 2, etc.). This is a hallmark ofbreadth-first search (BFS), not DFS. Textbooks emphasize this distinction because DFS and BFS have different properties: BFS naturally finds shortest paths in unweighted graphs and produces level-order traversal in trees, while DFS is useful for tasks like topological sorting, cycle detection, and exploring structure recursively.
Therefore, the traversal order that is impossible to produce as a depth-first traversal of a binary tree is level-order traversal. The DFS orders (pre-, in-, post-) are all achievable by depth-first strategies, typically implemented recursively or with an explicit stack.
NEW QUESTION # 38
What is the expected output of calling .shape on a NumPy 2D array?
Answer: D
Explanation:
In NumPy, every ndarray has a shape attribute that describes the size of the array along each dimension. For a
2D array, shape returns a tuple with two integers: (number_of_rows, number_of_columns). For example, if a
= np.array([[1, 2, 3], [4, 5, 6]]), then a.shape is (2, 3), meaning 2 rows and 3 columns. This is a fundamental idea in matrix and array computing, because shape governs how indexing, slicing, broadcasting, and linear algebra operations behave.
Option A describes the dtype, which can be accessed with a.dtype, not a.shape. Option C is incorrect because shape provides per-dimension sizes, not their sum. Option D refers to the total number of elements, which NumPy provides via a.size (or equivalently np.prod(a.shape)).
Textbooks emphasize shape because many errors in numerical computing come from mismatched dimensions. For example, matrix multiplication requires compatible inner dimensions, and broadcasting rules depend on dimension sizes. By checking .shape, programmers can verify their data layout before applying algorithms, ensuring rows represent observations and columns represent features (or vice versa). Thus, for a 2D NumPy array, .shape indicates the number of rows and columns.
NEW QUESTION # 39
How can a user subset a NumPy array bmi to only include values over 23?
Answer: C
Explanation:
NumPy supports a powerful technique calledBoolean indexing(also called Boolean masking) to filter arrays based on a condition. When you write bmi > 23, NumPy performs an element-wise comparison and produces a Boolean array of the same shape, containing True where the condition holds and False otherwise. Using that Boolean array inside square brackets, as in bmi[bmi > 23], tells NumPy to return a new 1D array containing only the elements whose mask value is True. This approach is heavily emphasized in scientific computing curricula because it expresses selection logic without explicit loops and runs efficiently in optimized compiled code.
Option B looks close but is not standard NumPy usage. The function commonly used is np.where(condition) or np.where(condition, x, y). While np.where(bmi > 23) can return indices, bmi.where(...) is not a NumPy array method; it is more associated with pandas objects. Options A and C are not valid NumPy APIs for filtering.
Boolean indexing is central in data analysis tasks such as removing invalid measurements, selecting a population subgroup, applying thresholds, and building feature subsets. It composes cleanly with vectorized computation, for example bmi[bmi > 23].mean(), enabling concise and high-performance numerical workflows.
NEW QUESTION # 40
What is the layer of programming between the operating system and the hardware that allows the operating system to interact with it in a more independent and generalized manner?
Answer: D
Explanation:
TheHardware Abstraction Layer (HAL)is a software layer that sits between the operating system kernel and the physical hardware. Its purpose is to hide hardware-specific details behind a consistent interface, allowing the OS to be more portable and easier to maintain across different hardware platforms. Textbooks explain that without abstraction, the OS would need extensive device- and architecture-specific code scattered throughout the kernel, making updates and cross-platform support far more difficult.
The HAL typically provides standardized functions for interacting with low-level components such as interrupts, timers, memory mapping, and device I/O. With a HAL, the OS can call general routines (for example, to configure an interrupt controller) while the HAL handles the platform-specific implementation.
This supports a key systems principle: separate policy (what the OS wants to do) from mechanism (how hardware accomplishes it).
The other options are not correct. A boot loader runs at startup to load the operating system into memory; it is not the general interface layer during normal operation. The task scheduler is a kernel subsystem that manages CPU time among processes, not a hardware-independence layer. The file system layer manages storage organization and access semantics; it is not the general abstraction for all hardware interactions.
Therefore, the programming layer that enables generalized OS interaction with hardware is the hardware abstraction layer.
NEW QUESTION # 41
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