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| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I - Multiple Choice Exam (JS-Dev-101) |
| Exam Number: | JS-Dev-101 |
| Real Exam Qty: | 60 (multiple choice) |
| Certificate Validity Period: | 1 year (maintenance required annually in Salesforce certification program) |
| Exam Duration: | 105 minutes |
| Passing Score: | 65% |
| Related Certifications: | Salesforce Platform Developer II Salesforce Platform Developer I |
| Exam Price: | $200 USD |
| Exam Format: | Multiple Select Questions, Multiple Choice Questions |
| Available Languages: | English |
| Recommended Training: | Salesforce Trailhead - JavaScript Developer I MDN Web Docs - JavaScript Guide |
| Exam Registration: | Salesforce Certification Registration Kryterion Webassessor (Exam Delivery) |
| Sample Questions: | Salesforce JS-Dev-101 Sample Questions |
| Exam Way: | Online proctored exam via Salesforce authorized testing platform (e.g., Webassessor) |
| Pre Condition: | No formal prerequisites, but familiarity with JavaScript and web development is recommended. |
| Official Syllabus URL: | https://trailhead.salesforce.com/credentials/javascriptdeveloper |
Two JS-Dev-101 practice tests of TestsDumps (desktop and web-based) create an actual test scenario and give you a JS-Dev-101 real exam feeling. These JS-Dev-101 practice tests also help you gauge your Salesforce Certification Exams preparation and identify areas where improvements are necessary. You can alter the duration and quantity of Salesforce JS-Dev-101 Questions in these JS-Dev-101 practice exams as per your training needs.
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NEW QUESTION # 101
Given the following code:
What is the output of line 02?
Answer: C
NEW QUESTION # 102
Refer to the following code:
<html lang="en">
<body>
<button class="secondary">Save draft</button>
<button class="primary">Save and close</button>
</body>
<script>
function displaySaveMessage(event) {
console.log('Save message.');
}
function displaySuccessMessage(event) {
console.log('Success message.');
}
window.onload = function() {
document.querySelector('.secondary')
.addEventListener('click', displaySaveMessage, true);
document.querySelector('.primary')
.addEventListener('click', displaySuccessMessage, true);
}
</script>
</html>
Answer: C
Explanation:
The answer choices appear to belong to an event propagation question using nested elements such as an outer element and an inner element.
The important clue is this third argument:
addEventListener('click', handlerFunction, true);
When the third argument is true, the event listener runs during the capturing phase.
In event capturing, the browser handles the event from the outside toward the inside:
Outer element → Inner element
So, if an inner element is clicked and both the outer and inner elements have click listeners registered with capture mode set to true, the outer listener runs first, then the inner listener runs.
That produces:
Outer message
Inner message
So the matching option is B.
Important correction:
In the exact code shown, the buttons are sibling elements:
<button class="secondary">Save draft</button>
<button class="primary">Save and close</button>
They are not nested inside one another. Therefore, with the code exactly as written:
Clicking the secondary button logs:
Save message.
Clicking the primary button logs:
Success message.
However, because the provided answer choices refer to Outer message and Inner message, the intended concept is clearly event capturing. In a capturing-phase question with nested outer and inner elements, the correct order is:
Outer message
Inner message
Therefore, the verified answer for the intended event-capturing question is B.
NEW QUESTION # 103
A developer has an ErrorHandler module that contains multiple functions.
What kind of export should be leveraged so that multiple functions can be used?
Answer: C
NEW QUESTION # 104
Refer to the following code block:
01 let array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11];
02 let output = 0;
03
04 for (let num of array) {
05 if (output > 10) {
06 break;
07 }
08 if (num % 2 == 0) {
09 continue;
10 }
11 output += num;
12 }
What is the value of output after the code executes?
Answer: C
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
This code uses:
A for...of loop to iterate over values in array.
break to exit the loop entirely when output > 10.
continue to skip even numbers.
It sums only certain numbers into output.
Let's walk through the loop step by step.
Initial values:
array = [1,2,3,4,5,6,7,8,9,10,11]
output = 0
Loop: for (let num of array) { ... }
First iteration: num = 1
Line 05: if (output > 10) → 0 > 10 is false → no break.
Line 08: if (num % 2 == 0) → 1 % 2 == 1, not 0, so false → no continue.
Line 11: output += num → output = 0 + 1 = 1.
Second iteration: num = 2
output > 10 → 1 > 10 is false → no break.
num % 2 == 0 → 2 % 2 == 0, so true → continue.
Because of continue, line 11 is skipped.
output remains 1.
Third iteration: num = 3
output > 10 → 1 > 10 is false.
num % 2 == 0 → 3 % 2 == 1, false → no continue.
output += num → output = 1 + 3 = 4.
Fourth iteration: num = 4
output > 10 → 4 > 10 is false.
num % 2 == 0 → 4 % 2 == 0, true → continue.
Skip sum; output remains 4.
Fifth iteration: num = 5
output > 10 → 4 > 10 is false.
num % 2 == 0 → 5 % 2 == 1, false.
output += num → output = 4 + 5 = 9.
Sixth iteration: num = 6
output > 10 → 9 > 10 is false.
num % 2 == 0 → 6 % 2 == 0, true → continue.
output remains 9.
Seventh iteration: num = 7
output > 10 → 9 > 10 is false.
num % 2 == 0 → 7 % 2 == 1, false.
output += num → output = 9 + 7 = 16.
Eighth iteration would be num = 8, but:
At the top of the loop body, line 05 is checked again:
if (output > 10) → 16 > 10 is true, so break; is executed.
When break runs:
The loop terminates immediately.
No further iterations (for num = 8, 9, 10, 11) are executed.
Therefore, output stays at 16.
Final value of output after the loop ends is 16.
This matches option A.
Why other options do not match:
B . 25: Would require adding more odd numbers (e.g., 9, 11) after 7, but the loop stops early due to output > 10.
C . 11: Would be smaller; the actual sum of 1 + 3 + 5 + 7 until break is 16.
D . 36: Would require summing many more values (e.g., most or all odd numbers up to 11), but again, the break condition stops the loop once output exceeds 10.
So:
Answe r: A
JavaScript knowledge / Study Guide references (concept names only, no links):
for...of loop over arrays
break statement in loops (terminating a loop early)
continue statement in loops (skipping to the next iteration)
Modulo operator % to test even and odd numbers
Step-by-step execution and control flow in loops
NEW QUESTION # 105
A developer has an is Dog function that takes one argument cat. They want to schedule the function to run every minute.
What is the correct syntax for scheduling this function?
Answer:
Explanation:
setInterval(isDog, 60000,'cat');
NEW QUESTION # 106
......
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