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Wollen Sie, ein ITer, durch den Erfolg zu IT-Zertifizierungsprüfungen Ihre Fähigkeit beweisen? Und heute besitzen immer mehr Ihre Freuden und Kommilitonen die IT-Zertifizierungen. Und in diesem Fall können Sie weniger Chancen haben, wenn Sie keine Zertifizierung haben. Und haben Sie sich entschieden, welche Prüfung abzulegen? Wie sind Salesforce Prüfungen? Oder Salesforce JS-Dev-101 Zeritifizierungsprüfung? Salesforce JS-Dev-101 Zeritifizierungsprüfung ist wertvoll und hilft Ihnen unbedingt, Ihren Wunsch zu erreichen.

Salesforce JS-Dev-101 Exam Overview:

Certification Vendor:Salesforce
Exam Name:Salesforce Certified JavaScript Developer - Multiple Choice
Exam Number:JS-Dev-101
Exam Duration:105 minutes
Available Languages:English, Japanese
Exam Price:USD 200
Exam Format:Multiple select, Multiple choice
Certificate Validity Period:Does not expire; requires maintenance updates
Passing Score:65%
Related Certifications:Salesforce Certified Platform Developer I
Salesforce Certified Developer
Real Exam Qty:60 scored + up to 5 unscored
Recommended Training:Trailhead JavaScript Developer I Certification Prep
Exam Registration:Salesforce Certification Registration
Sample Questions:Salesforce JS-Dev-101 Sample Questions
Exam Way:Online proctored or onsite at authorized testing centers
Pre Condition:No formal prerequisites; recommended: strong JavaScript fundamentals, ES6+ experience, web development familiarity
Official Syllabus URL:https://trailheadacademy.salesforce.com/certificate/exam-javascript-dev---JS-Dev-101

>> JS-Dev-101 Examsfragen <<

Zertifizierung der JS-Dev-101 mit umfassenden Garantien zu bestehen

Es ist uns allen bekannt, dass IT-Branche eine neue Branche und auch eine Kette ist, die die wirtschaftliche Entwicklung fördert. So ist ihre Position nicht zu ignorieren. Die Salesforce JS-Dev-101 IT-Zertifizierung ist eine Methode für den Wettbewerb. Durch die Salesforce JS-Dev-101 Zertifizierung werden Sie sich in allen Aspekten verbessern. Aber es ist nicht so einfach, die Prüfung zu bestehen. So empfehle ich Ihnen unsere originale Fragen. Wenn Sie die Schulungsressourcen wählen, ist Pass4Test die erste Wahl. Seine Erfolgsquote beträgt 100%. Und Sie können die Salesforce JS-Dev-101 Prüfung sicher bestehen.

Salesforce JS-Dev-101 Prüfungsplan:

ThemaEinzelheiten
Thema 1
  • Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.
Thema 2
  • Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
Thema 3
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.
Thema 4
  • Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
Thema 5
  • Testing: Covers evaluating unit test effectiveness against a block of code and modifying tests to improve their coverage and reliability.

Salesforce Certified JavaScript Developer - Multiple Choice JS-Dev-101 Prüfungsfragen mit Lösungen (Q43-Q48):

43. Frage
Given the HTML below:
<div>
<div id="row-uc">Universal Containers</div>
<div id="row-as">Applied Shipping</div>
<div id="row-bt">Burlington Textiles</div>
</div>
Which statement adds the priority-account CSS class to the Applied Shipping row?

Antwort: C

Begründung:
document.querySelector('#row-as') returns the single element with id row-as.
That element has a classList property with add, remove, etc.
Correct usage:
document.querySelector('#row-as').classList.add('priority-account');
Why others are wrong:
A: querySelectorAll returns a NodeList, not a single element, so it does not have a classList property.
C: DOM elements do not have a classes array or push; they have classList.
D: document.getElementById('row-as') is fine to get the element, but there is no addClass method in standard DOM; that's a jQuery-style API, not vanilla JS.
________________________________________


44. Frage
Given a value, which two options can a developer use to detect if the value is NaN?

Antwort: A,C

Begründung:
We already know NaN is special: it is not equal to itself.
Check each:
A . value === Number.NaN
Number.NaN is NaN.
NaN === NaN is always false.
This will never be true; cannot reliably detect NaN.
B . value == NaN
NaN == NaN is also always false.
Again, this never detects NaN.
C . isNaN(value)
Global isNaN converts its argument to a number and then checks if the result is NaN.
This can detect NaN, but it may also return true for non-number values that coerce to NaN, such as isNaN('foo').
Regardless, it is a standard way to detect if a value is "NaN-like" in JavaScript.
D . Object.is(value, NaN)
Object.is(NaN, NaN) returns true.
This is a strict way to detect a value that is exactly NaN (no coercion).
Therefore, among the given choices, the two viable ways to detect NaN are:
isNaN(value)
Object.is(value, NaN)


45. Frage
Refer to the code snippet:
Function getAvailabilityMessage(item) {
If (getAvailability(item)){
Var msg ="Username available";
}
Return msg;
}
A developer writes this code to return a message to user attempting to register a new username. If the username is available, variable.
What is the return value of msg hen getAvailabilityMessage ("newUserName" ) is executed and getAvailability("newUserName") returns false?

Antwort: B


46. Frage
Refer to the code below:
Let str = 'javascript';
Str[0] = 'J';
Str[4] = 'S';
After changing the string indexvalues, the value of str is 'javascript'. What is the reason for this value:

Antwort: B


47. Frage
Refer to the code:
01 function execute() {
02 return new Promise((resolve, reject) => reject());
03 }
04 let promise = execute();
05
06 promise
07 .then(() => console.log('Resolved1'))
08 .then(() => console.log('Resolved2'))
09 .then(() => console.log('Resolved3'))
10 .catch(() => console.log('Rejected'))
11 .then(() => console.log('Resolved4'));
What is the result when the Promise in the execute function is rejected?

Antwort: A

Begründung:
execute() returns a Promise that immediately calls reject().
So promise starts in a rejected state.
When a Promise is rejected and you chain .then() calls without rejection handlers, all those .then() callbacks are skipped until a .catch() is encountered:
promise
.then(...) // skipped
.then(...) // skipped
.then(...) // skipped
.catch(...) // executed
.then(...); // executed after catch
Execution:
.then(() => console.log('Resolved1')) is skipped.
.then(() => console.log('Resolved2')) is skipped.
.then(() => console.log('Resolved3')) is skipped.
.catch(() => console.log('Rejected')) runs and logs Rejected.
The .catch() returns a resolved Promise (no explicit return, so undefined), so the next .then() runs:
.then(() => console.log('Resolved4')) logs Resolved4.
Final output:
Rejected
Resolved4
This matches option D.


48. Frage
......

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